Inner product of distance between two vectors












1














We can define a 'distance' between two points $P = (x_1,y_1)$ and $Q=(x_2,y_2)$ of the plane by $d(P,Q) = |x_2 - x_1| + |y_2 - y_1|$. Verify if the sentence below is a inner product in the plane.
$$langle(x_1,y_1),(x_2,y_2)rangle = d(P,Q)$$



UPDATE: What i've already made



Positivity
$langle P,Prangle geq 0 $

The distance from a point to a point is 0. [check]



Symmetry
$ langle P,Q rangle = langle Q,P rangle$

The distance from a point P to a point Q is equal to distance from a point Q to the point Q.[check]



Bilinearity
$ langlelambda P,Qrangle = lambdalangle P,Qrangle \
langle(lambda x_1,lambda y_1),(x_2,y_2)rangle = |x_2 - lambda x_1| + | y_2 - lambda y_1 |\$


I'm stuck here, i don't know how get out with this.










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  • 1




    What are the properties of an inner product? How would you verify them in this case?
    – rubikscube09
    Nov 29 '18 at 20:43










  • What have you tried? Show us your work and maybe we can help you.
    – Tito Eliatron
    Nov 29 '18 at 20:54










  • Bilinearity,symmetry and positivity. I've tried and got the symmetry and positivity, but the linearity (even making each linearity separated) i do not.
    – Messias Tayllan
    Nov 29 '18 at 21:52










  • Have you considered that it might not be an inner product? Try a few examples and see if bilinearity holds for those examples.
    – Kevin Long
    Nov 29 '18 at 22:23










  • Yeah, the answer from J.G. helped me. I did not try before because the answer from my professor was that is a inner product, but i was confusing how do this.
    – Messias Tayllan
    Nov 29 '18 at 22:27
















1














We can define a 'distance' between two points $P = (x_1,y_1)$ and $Q=(x_2,y_2)$ of the plane by $d(P,Q) = |x_2 - x_1| + |y_2 - y_1|$. Verify if the sentence below is a inner product in the plane.
$$langle(x_1,y_1),(x_2,y_2)rangle = d(P,Q)$$



UPDATE: What i've already made



Positivity
$langle P,Prangle geq 0 $

The distance from a point to a point is 0. [check]



Symmetry
$ langle P,Q rangle = langle Q,P rangle$

The distance from a point P to a point Q is equal to distance from a point Q to the point Q.[check]



Bilinearity
$ langlelambda P,Qrangle = lambdalangle P,Qrangle \
langle(lambda x_1,lambda y_1),(x_2,y_2)rangle = |x_2 - lambda x_1| + | y_2 - lambda y_1 |\$


I'm stuck here, i don't know how get out with this.










share|cite|improve this question




















  • 1




    What are the properties of an inner product? How would you verify them in this case?
    – rubikscube09
    Nov 29 '18 at 20:43










  • What have you tried? Show us your work and maybe we can help you.
    – Tito Eliatron
    Nov 29 '18 at 20:54










  • Bilinearity,symmetry and positivity. I've tried and got the symmetry and positivity, but the linearity (even making each linearity separated) i do not.
    – Messias Tayllan
    Nov 29 '18 at 21:52










  • Have you considered that it might not be an inner product? Try a few examples and see if bilinearity holds for those examples.
    – Kevin Long
    Nov 29 '18 at 22:23










  • Yeah, the answer from J.G. helped me. I did not try before because the answer from my professor was that is a inner product, but i was confusing how do this.
    – Messias Tayllan
    Nov 29 '18 at 22:27














1












1








1







We can define a 'distance' between two points $P = (x_1,y_1)$ and $Q=(x_2,y_2)$ of the plane by $d(P,Q) = |x_2 - x_1| + |y_2 - y_1|$. Verify if the sentence below is a inner product in the plane.
$$langle(x_1,y_1),(x_2,y_2)rangle = d(P,Q)$$



UPDATE: What i've already made



Positivity
$langle P,Prangle geq 0 $

The distance from a point to a point is 0. [check]



Symmetry
$ langle P,Q rangle = langle Q,P rangle$

The distance from a point P to a point Q is equal to distance from a point Q to the point Q.[check]



Bilinearity
$ langlelambda P,Qrangle = lambdalangle P,Qrangle \
langle(lambda x_1,lambda y_1),(x_2,y_2)rangle = |x_2 - lambda x_1| + | y_2 - lambda y_1 |\$


I'm stuck here, i don't know how get out with this.










share|cite|improve this question















We can define a 'distance' between two points $P = (x_1,y_1)$ and $Q=(x_2,y_2)$ of the plane by $d(P,Q) = |x_2 - x_1| + |y_2 - y_1|$. Verify if the sentence below is a inner product in the plane.
$$langle(x_1,y_1),(x_2,y_2)rangle = d(P,Q)$$



UPDATE: What i've already made



Positivity
$langle P,Prangle geq 0 $

The distance from a point to a point is 0. [check]



Symmetry
$ langle P,Q rangle = langle Q,P rangle$

The distance from a point P to a point Q is equal to distance from a point Q to the point Q.[check]



Bilinearity
$ langlelambda P,Qrangle = lambdalangle P,Qrangle \
langle(lambda x_1,lambda y_1),(x_2,y_2)rangle = |x_2 - lambda x_1| + | y_2 - lambda y_1 |\$


I'm stuck here, i don't know how get out with this.







linear-algebra






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edited Nov 29 '18 at 22:15







Messias Tayllan

















asked Nov 29 '18 at 20:37









Messias TayllanMessias Tayllan

84




84








  • 1




    What are the properties of an inner product? How would you verify them in this case?
    – rubikscube09
    Nov 29 '18 at 20:43










  • What have you tried? Show us your work and maybe we can help you.
    – Tito Eliatron
    Nov 29 '18 at 20:54










  • Bilinearity,symmetry and positivity. I've tried and got the symmetry and positivity, but the linearity (even making each linearity separated) i do not.
    – Messias Tayllan
    Nov 29 '18 at 21:52










  • Have you considered that it might not be an inner product? Try a few examples and see if bilinearity holds for those examples.
    – Kevin Long
    Nov 29 '18 at 22:23










  • Yeah, the answer from J.G. helped me. I did not try before because the answer from my professor was that is a inner product, but i was confusing how do this.
    – Messias Tayllan
    Nov 29 '18 at 22:27














  • 1




    What are the properties of an inner product? How would you verify them in this case?
    – rubikscube09
    Nov 29 '18 at 20:43










  • What have you tried? Show us your work and maybe we can help you.
    – Tito Eliatron
    Nov 29 '18 at 20:54










  • Bilinearity,symmetry and positivity. I've tried and got the symmetry and positivity, but the linearity (even making each linearity separated) i do not.
    – Messias Tayllan
    Nov 29 '18 at 21:52










  • Have you considered that it might not be an inner product? Try a few examples and see if bilinearity holds for those examples.
    – Kevin Long
    Nov 29 '18 at 22:23










  • Yeah, the answer from J.G. helped me. I did not try before because the answer from my professor was that is a inner product, but i was confusing how do this.
    – Messias Tayllan
    Nov 29 '18 at 22:27








1




1




What are the properties of an inner product? How would you verify them in this case?
– rubikscube09
Nov 29 '18 at 20:43




What are the properties of an inner product? How would you verify them in this case?
– rubikscube09
Nov 29 '18 at 20:43












What have you tried? Show us your work and maybe we can help you.
– Tito Eliatron
Nov 29 '18 at 20:54




What have you tried? Show us your work and maybe we can help you.
– Tito Eliatron
Nov 29 '18 at 20:54












Bilinearity,symmetry and positivity. I've tried and got the symmetry and positivity, but the linearity (even making each linearity separated) i do not.
– Messias Tayllan
Nov 29 '18 at 21:52




Bilinearity,symmetry and positivity. I've tried and got the symmetry and positivity, but the linearity (even making each linearity separated) i do not.
– Messias Tayllan
Nov 29 '18 at 21:52












Have you considered that it might not be an inner product? Try a few examples and see if bilinearity holds for those examples.
– Kevin Long
Nov 29 '18 at 22:23




Have you considered that it might not be an inner product? Try a few examples and see if bilinearity holds for those examples.
– Kevin Long
Nov 29 '18 at 22:23












Yeah, the answer from J.G. helped me. I did not try before because the answer from my professor was that is a inner product, but i was confusing how do this.
– Messias Tayllan
Nov 29 '18 at 22:27




Yeah, the answer from J.G. helped me. I did not try before because the answer from my professor was that is a inner product, but i was confusing how do this.
– Messias Tayllan
Nov 29 '18 at 22:27










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It's not an inner product because it isn't linear. For example, the choice $P=Q=(1,,0)$ implies $d(P,,kQ)=|k-1|$, which for $kne 1$ differs from $kd(P,,Q)=0$.






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    1 Answer
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    It's not an inner product because it isn't linear. For example, the choice $P=Q=(1,,0)$ implies $d(P,,kQ)=|k-1|$, which for $kne 1$ differs from $kd(P,,Q)=0$.






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      It's not an inner product because it isn't linear. For example, the choice $P=Q=(1,,0)$ implies $d(P,,kQ)=|k-1|$, which for $kne 1$ differs from $kd(P,,Q)=0$.






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        It's not an inner product because it isn't linear. For example, the choice $P=Q=(1,,0)$ implies $d(P,,kQ)=|k-1|$, which for $kne 1$ differs from $kd(P,,Q)=0$.






        share|cite|improve this answer












        It's not an inner product because it isn't linear. For example, the choice $P=Q=(1,,0)$ implies $d(P,,kQ)=|k-1|$, which for $kne 1$ differs from $kd(P,,Q)=0$.







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        answered Nov 29 '18 at 22:08









        J.G.J.G.

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