Numerical Change of Variables
If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.
numerical-methods change-of-variable numerical-calculus
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If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.
numerical-methods change-of-variable numerical-calculus
Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35
add a comment |
If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.
numerical-methods change-of-variable numerical-calculus
If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.
numerical-methods change-of-variable numerical-calculus
numerical-methods change-of-variable numerical-calculus
asked Nov 29 '18 at 20:29
twofairtwofair
103
103
Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35
add a comment |
Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35
Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35
Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35
add a comment |
1 Answer
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Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
add a comment |
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1 Answer
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Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
add a comment |
Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
add a comment |
Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.
Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.
answered Nov 29 '18 at 20:38
FedericoFederico
4,849514
4,849514
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
add a comment |
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06
add a comment |
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Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35