Numerical Change of Variables












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If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.










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  • Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
    – Federico
    Nov 29 '18 at 20:35
















0














If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.










share|cite|improve this question






















  • Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
    – Federico
    Nov 29 '18 at 20:35














0












0








0







If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.










share|cite|improve this question













If I have $f(x)$ represented by 2 arrays. One array is the arrays of $x$ while the other is output from $f(x)$. So basically a numerical representation of the function. If I don't know what $f(x)$ is, can I still change the variable. For example can I calculate $f(frac{1}{x})$ from what I know.







numerical-methods change-of-variable numerical-calculus






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asked Nov 29 '18 at 20:29









twofairtwofair

103




103












  • Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
    – Federico
    Nov 29 '18 at 20:35


















  • Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
    – Federico
    Nov 29 '18 at 20:35
















Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35




Well, you know the values of $f(1/x)$ at the sampled points $1/x_i$, so you can use a quadrature formula to have an estimate of the integral. No need to "change the variable"
– Federico
Nov 29 '18 at 20:35










1 Answer
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Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.






share|cite|improve this answer





















  • Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
    – twofair
    Nov 30 '18 at 21:06











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1 Answer
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Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.






share|cite|improve this answer





















  • Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
    – twofair
    Nov 30 '18 at 21:06
















0














Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.






share|cite|improve this answer





















  • Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
    – twofair
    Nov 30 '18 at 21:06














0












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0






Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.






share|cite|improve this answer












Let's say that you know $f(x_i)=f_i$ for $i=1,dots,n$. Consider the function $g(x)=f(1/x)$ and the points $y_i=1/x_i$. Then you know $g(y_i)=f_i$. Now you can use any quadrature rule (for instance the trapezoidal rule) to get an estimate of the integral of $g$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 29 '18 at 20:38









FedericoFederico

4,849514




4,849514












  • Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
    – twofair
    Nov 30 '18 at 21:06


















  • Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
    – twofair
    Nov 30 '18 at 21:06
















Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06




Thanks, you are correct. It makes sense. I think I was working on this problem for too long and got lost in some details. Thanks again
– twofair
Nov 30 '18 at 21:06


















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