Is there a group whose manifold is a fiber bundle with base is $S_1$ and fiber $mathbb{Z_2}?$
$begingroup$
Let's consider a fiber bundle with base $S_1$ and fiber $mathbb{Z}_2$. I want this manifold to be topologically non-trivial, the edge of the Möbius strip.
How do I know if is it possible to introduce a group structure on such a manifold? So that the manifold would turn into a principle bundle.
group-theory fiber-bundles principal-bundles
$endgroup$
add a comment |
$begingroup$
Let's consider a fiber bundle with base $S_1$ and fiber $mathbb{Z}_2$. I want this manifold to be topologically non-trivial, the edge of the Möbius strip.
How do I know if is it possible to introduce a group structure on such a manifold? So that the manifold would turn into a principle bundle.
group-theory fiber-bundles principal-bundles
$endgroup$
add a comment |
$begingroup$
Let's consider a fiber bundle with base $S_1$ and fiber $mathbb{Z}_2$. I want this manifold to be topologically non-trivial, the edge of the Möbius strip.
How do I know if is it possible to introduce a group structure on such a manifold? So that the manifold would turn into a principle bundle.
group-theory fiber-bundles principal-bundles
$endgroup$
Let's consider a fiber bundle with base $S_1$ and fiber $mathbb{Z}_2$. I want this manifold to be topologically non-trivial, the edge of the Möbius strip.
How do I know if is it possible to introduce a group structure on such a manifold? So that the manifold would turn into a principle bundle.
group-theory fiber-bundles principal-bundles
group-theory fiber-bundles principal-bundles
asked Dec 5 '18 at 21:23
mavzolejmavzolej
47028
47028
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
This manifold, considered independent of its fiber bundle structure, is just $S^1$ again, so it admits the same group structure as $S^1$. You can think of the resulting bundle as the short exact sequence
$$1 to mathbb{Z}_2 to S^1 xrightarrow{x mapsto x^2} S^1 to 1.$$
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3027671%2fis-there-a-group-whose-manifold-is-a-fiber-bundle-with-base-is-s-1-and-fiber%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This manifold, considered independent of its fiber bundle structure, is just $S^1$ again, so it admits the same group structure as $S^1$. You can think of the resulting bundle as the short exact sequence
$$1 to mathbb{Z}_2 to S^1 xrightarrow{x mapsto x^2} S^1 to 1.$$
$endgroup$
add a comment |
$begingroup$
This manifold, considered independent of its fiber bundle structure, is just $S^1$ again, so it admits the same group structure as $S^1$. You can think of the resulting bundle as the short exact sequence
$$1 to mathbb{Z}_2 to S^1 xrightarrow{x mapsto x^2} S^1 to 1.$$
$endgroup$
add a comment |
$begingroup$
This manifold, considered independent of its fiber bundle structure, is just $S^1$ again, so it admits the same group structure as $S^1$. You can think of the resulting bundle as the short exact sequence
$$1 to mathbb{Z}_2 to S^1 xrightarrow{x mapsto x^2} S^1 to 1.$$
$endgroup$
This manifold, considered independent of its fiber bundle structure, is just $S^1$ again, so it admits the same group structure as $S^1$. You can think of the resulting bundle as the short exact sequence
$$1 to mathbb{Z}_2 to S^1 xrightarrow{x mapsto x^2} S^1 to 1.$$
answered Dec 5 '18 at 22:29
Qiaochu YuanQiaochu Yuan
278k32585922
278k32585922
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3027671%2fis-there-a-group-whose-manifold-is-a-fiber-bundle-with-base-is-s-1-and-fiber%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown