Making a Perfect Cusp Tikz












8















This Cusp I made came out awkward and I can not fix it.



documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=1,cap=round]
tikzset{axes/.style={}}
% The graphic
begin{scope}[style=axes]
draw[->] (-.5,0) -- (3,0) node[below] {$x$};
draw[->] (0,-.5)-- (0,3) node[left] {$y$};
draw (0.25,0.4) to [out=10,in=80] (1.5,2.5);
draw (1.5,2.5) to [out=-80, in=175] (2.75,.4);
%%%
end{scope}
end{tikzpicture}
end{document}


This outputs:



enter image description here



I am trying to achieve:



enter image description here



Note it is not exactly symmetric either but the head is cleaner.










share|improve this question

























  • What precisely do you want to achieve? (The top is tilted since you have in=80 and out=-80 instead of 90.)

    – marmot
    Nov 30 '18 at 14:30











  • @Marmot, I posted above what I am trying to achieve, I didn't think I'd have to ask a question on this but I also tried 90 and could not get the look I wanted.

    – MathScholar
    Nov 30 '18 at 15:09













  • How about draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5) to [out=-90, in=175] (2.75,.4);?

    – marmot
    Nov 30 '18 at 15:13
















8















This Cusp I made came out awkward and I can not fix it.



documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=1,cap=round]
tikzset{axes/.style={}}
% The graphic
begin{scope}[style=axes]
draw[->] (-.5,0) -- (3,0) node[below] {$x$};
draw[->] (0,-.5)-- (0,3) node[left] {$y$};
draw (0.25,0.4) to [out=10,in=80] (1.5,2.5);
draw (1.5,2.5) to [out=-80, in=175] (2.75,.4);
%%%
end{scope}
end{tikzpicture}
end{document}


This outputs:



enter image description here



I am trying to achieve:



enter image description here



Note it is not exactly symmetric either but the head is cleaner.










share|improve this question

























  • What precisely do you want to achieve? (The top is tilted since you have in=80 and out=-80 instead of 90.)

    – marmot
    Nov 30 '18 at 14:30











  • @Marmot, I posted above what I am trying to achieve, I didn't think I'd have to ask a question on this but I also tried 90 and could not get the look I wanted.

    – MathScholar
    Nov 30 '18 at 15:09













  • How about draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5) to [out=-90, in=175] (2.75,.4);?

    – marmot
    Nov 30 '18 at 15:13














8












8








8








This Cusp I made came out awkward and I can not fix it.



documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=1,cap=round]
tikzset{axes/.style={}}
% The graphic
begin{scope}[style=axes]
draw[->] (-.5,0) -- (3,0) node[below] {$x$};
draw[->] (0,-.5)-- (0,3) node[left] {$y$};
draw (0.25,0.4) to [out=10,in=80] (1.5,2.5);
draw (1.5,2.5) to [out=-80, in=175] (2.75,.4);
%%%
end{scope}
end{tikzpicture}
end{document}


This outputs:



enter image description here



I am trying to achieve:



enter image description here



Note it is not exactly symmetric either but the head is cleaner.










share|improve this question
















This Cusp I made came out awkward and I can not fix it.



documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=1,cap=round]
tikzset{axes/.style={}}
% The graphic
begin{scope}[style=axes]
draw[->] (-.5,0) -- (3,0) node[below] {$x$};
draw[->] (0,-.5)-- (0,3) node[left] {$y$};
draw (0.25,0.4) to [out=10,in=80] (1.5,2.5);
draw (1.5,2.5) to [out=-80, in=175] (2.75,.4);
%%%
end{scope}
end{tikzpicture}
end{document}


This outputs:



enter image description here



I am trying to achieve:



enter image description here



Note it is not exactly symmetric either but the head is cleaner.







tikz-pgf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 30 '18 at 15:08







MathScholar

















asked Nov 30 '18 at 14:19









MathScholarMathScholar

66918




66918













  • What precisely do you want to achieve? (The top is tilted since you have in=80 and out=-80 instead of 90.)

    – marmot
    Nov 30 '18 at 14:30











  • @Marmot, I posted above what I am trying to achieve, I didn't think I'd have to ask a question on this but I also tried 90 and could not get the look I wanted.

    – MathScholar
    Nov 30 '18 at 15:09













  • How about draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5) to [out=-90, in=175] (2.75,.4);?

    – marmot
    Nov 30 '18 at 15:13



















  • What precisely do you want to achieve? (The top is tilted since you have in=80 and out=-80 instead of 90.)

    – marmot
    Nov 30 '18 at 14:30











  • @Marmot, I posted above what I am trying to achieve, I didn't think I'd have to ask a question on this but I also tried 90 and could not get the look I wanted.

    – MathScholar
    Nov 30 '18 at 15:09













  • How about draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5) to [out=-90, in=175] (2.75,.4);?

    – marmot
    Nov 30 '18 at 15:13

















What precisely do you want to achieve? (The top is tilted since you have in=80 and out=-80 instead of 90.)

– marmot
Nov 30 '18 at 14:30





What precisely do you want to achieve? (The top is tilted since you have in=80 and out=-80 instead of 90.)

– marmot
Nov 30 '18 at 14:30













@Marmot, I posted above what I am trying to achieve, I didn't think I'd have to ask a question on this but I also tried 90 and could not get the look I wanted.

– MathScholar
Nov 30 '18 at 15:09







@Marmot, I posted above what I am trying to achieve, I didn't think I'd have to ask a question on this but I also tried 90 and could not get the look I wanted.

– MathScholar
Nov 30 '18 at 15:09















How about draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5) to [out=-90, in=175] (2.75,.4);?

– marmot
Nov 30 '18 at 15:13





How about draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5) to [out=-90, in=175] (2.75,.4);?

– marmot
Nov 30 '18 at 15:13










3 Answers
3






active

oldest

votes


















7














I guess the sign of 80 in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is the culprit.



documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}[scale=1,cap=round]
tikzset{axes/.style={}}
% The graphic
begin{scope}[style=axes]
draw[->] (-.5,0) -- (3,0) node[below] {$x$};
draw[->] (0,-.5)-- (0,3) node[left] {$y$};
draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5)
to [out=-90, in=175] (2.75,.4);
draw[thin] (1.5,2.5) -- ++ (0.2,0.6) node[above]{$f'(a)$ does not exist};
draw (1.5,0.2) -- (1.5,-0.2) node[below]{$a$};
%%%
end{scope}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer





















  • 1





    marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

    – gusbrs
    Nov 30 '18 at 15:17













  • @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

    – marmot
    Nov 30 '18 at 15:20













  • @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

    – MathScholar
    Nov 30 '18 at 15:21











  • @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

    – marmot
    Nov 30 '18 at 15:22











  • Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

    – gusbrs
    Nov 30 '18 at 15:23



















4














Here is a solution using the pgfplots package, which extends tikz to include a wide variety of plotting options:



documentclass{article}
usepackage{pgfplots}
begin{document}
begin{tikzpicture}begin{axis}[xmin=0,xmax=1,ymin=0,xtick={0.5},xticklabels=$a$,axis lines=left,ymajorticks=false,xlabel=$x$,ylabel=$y$,clip=false]
addplot [domain=0.1:0.5] {0.1+x^2} node [pos=0.2,above left] {$f$};
addplot [domain=0.5:0.9] {0.1+(x-1)^2} node[pin={90: $f'(a)$ does not exist.} ] at (axis cs:0.5,0.35) {};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer
























  • @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

    – MathScholar
    Nov 30 '18 at 15:41





















2














A PSTricks solution just for comparison purposes.



documentclass[pstricks]{standalone}
usepackage{pst-plot,pst-plot}
deff#1{(x-#1)^2+1}
begin{document}
begin{pspicture}[algebraic,ticks=none,labels=none](-.4,-.5)(4.5,3.5)
psaxes{->}(0,0)(-.3,-.4)(4,3)[$x$,0][$y$,90]
psplot{1}{2}{f{1}}
psplot{2}{3}{f{3}}
psxTick[labelsep=1pt](2){a}
rput(2.2,3){rnode[b]{a}{$f'(a)$ does not exist}}
pcline[nodesep=2pt]{->}(a)(*2 {f{1}})
end{pspicture}
end{document}


enter image description here






share|improve this answer























    Your Answer








    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "85"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f462564%2fmaking-a-perfect-cusp-tikz%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    I guess the sign of 80 in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is the culprit.



    documentclass{article}
    usepackage{tikz}
    begin{document}
    begin{tikzpicture}[scale=1,cap=round]
    tikzset{axes/.style={}}
    % The graphic
    begin{scope}[style=axes]
    draw[->] (-.5,0) -- (3,0) node[below] {$x$};
    draw[->] (0,-.5)-- (0,3) node[left] {$y$};
    draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5)
    to [out=-90, in=175] (2.75,.4);
    draw[thin] (1.5,2.5) -- ++ (0.2,0.6) node[above]{$f'(a)$ does not exist};
    draw (1.5,0.2) -- (1.5,-0.2) node[below]{$a$};
    %%%
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer





















    • 1





      marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

      – gusbrs
      Nov 30 '18 at 15:17













    • @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

      – marmot
      Nov 30 '18 at 15:20













    • @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

      – MathScholar
      Nov 30 '18 at 15:21











    • @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

      – marmot
      Nov 30 '18 at 15:22











    • Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

      – gusbrs
      Nov 30 '18 at 15:23
















    7














    I guess the sign of 80 in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is the culprit.



    documentclass{article}
    usepackage{tikz}
    begin{document}
    begin{tikzpicture}[scale=1,cap=round]
    tikzset{axes/.style={}}
    % The graphic
    begin{scope}[style=axes]
    draw[->] (-.5,0) -- (3,0) node[below] {$x$};
    draw[->] (0,-.5)-- (0,3) node[left] {$y$};
    draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5)
    to [out=-90, in=175] (2.75,.4);
    draw[thin] (1.5,2.5) -- ++ (0.2,0.6) node[above]{$f'(a)$ does not exist};
    draw (1.5,0.2) -- (1.5,-0.2) node[below]{$a$};
    %%%
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer





















    • 1





      marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

      – gusbrs
      Nov 30 '18 at 15:17













    • @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

      – marmot
      Nov 30 '18 at 15:20













    • @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

      – MathScholar
      Nov 30 '18 at 15:21











    • @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

      – marmot
      Nov 30 '18 at 15:22











    • Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

      – gusbrs
      Nov 30 '18 at 15:23














    7












    7








    7







    I guess the sign of 80 in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is the culprit.



    documentclass{article}
    usepackage{tikz}
    begin{document}
    begin{tikzpicture}[scale=1,cap=round]
    tikzset{axes/.style={}}
    % The graphic
    begin{scope}[style=axes]
    draw[->] (-.5,0) -- (3,0) node[below] {$x$};
    draw[->] (0,-.5)-- (0,3) node[left] {$y$};
    draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5)
    to [out=-90, in=175] (2.75,.4);
    draw[thin] (1.5,2.5) -- ++ (0.2,0.6) node[above]{$f'(a)$ does not exist};
    draw (1.5,0.2) -- (1.5,-0.2) node[below]{$a$};
    %%%
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer















    I guess the sign of 80 in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is the culprit.



    documentclass{article}
    usepackage{tikz}
    begin{document}
    begin{tikzpicture}[scale=1,cap=round]
    tikzset{axes/.style={}}
    % The graphic
    begin{scope}[style=axes]
    draw[->] (-.5,0) -- (3,0) node[below] {$x$};
    draw[->] (0,-.5)-- (0,3) node[left] {$y$};
    draw[thick] (0.25,0.4) to [out=10,in=-90] (1.5,2.5)
    to [out=-90, in=175] (2.75,.4);
    draw[thin] (1.5,2.5) -- ++ (0.2,0.6) node[above]{$f'(a)$ does not exist};
    draw (1.5,0.2) -- (1.5,-0.2) node[below]{$a$};
    %%%
    end{scope}
    end{tikzpicture}
    end{document}


    enter image description here







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 30 '18 at 15:24

























    answered Nov 30 '18 at 15:16









    marmotmarmot

    90.9k4104196




    90.9k4104196








    • 1





      marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

      – gusbrs
      Nov 30 '18 at 15:17













    • @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

      – marmot
      Nov 30 '18 at 15:20













    • @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

      – MathScholar
      Nov 30 '18 at 15:21











    • @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

      – marmot
      Nov 30 '18 at 15:22











    • Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

      – gusbrs
      Nov 30 '18 at 15:23














    • 1





      marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

      – gusbrs
      Nov 30 '18 at 15:17













    • @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

      – marmot
      Nov 30 '18 at 15:20













    • @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

      – MathScholar
      Nov 30 '18 at 15:21











    • @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

      – marmot
      Nov 30 '18 at 15:22











    • Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

      – gusbrs
      Nov 30 '18 at 15:23








    1




    1





    marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

    – gusbrs
    Nov 30 '18 at 15:17







    marmot, why does it have to be 90? (Side note $f'(a)$ does not exist).

    – gusbrs
    Nov 30 '18 at 15:17















    @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

    – marmot
    Nov 30 '18 at 15:20







    @gusbrs Well, that's how I interpreted "Note it is not exactly symmetric either but the head is cleaner.". I thought the OP wants to have it symmetric. (And thanks for the note!)

    – marmot
    Nov 30 '18 at 15:20















    @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

    – MathScholar
    Nov 30 '18 at 15:21





    @Marmot, that works but I thought I tried that. Eyes playing tricks on me. Not sure exactly what we changed Thanks Marmot!

    – MathScholar
    Nov 30 '18 at 15:21













    @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

    – marmot
    Nov 30 '18 at 15:22





    @MathScholar I guess the sign of in in draw (0.25,0.4) to [out=10,in=80] (1.5,2.5); is crucial. I have a - there.

    – marmot
    Nov 30 '18 at 15:22













    Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

    – gusbrs
    Nov 30 '18 at 15:23





    Well, conceptually, we could still have side derivatives (is this how this is said in english?...) reaching "a" at 80 degrees and the derivative in a would not exist. The graphic would be symmetric like this. But the question is why doesn't tikz accept it?

    – gusbrs
    Nov 30 '18 at 15:23











    4














    Here is a solution using the pgfplots package, which extends tikz to include a wide variety of plotting options:



    documentclass{article}
    usepackage{pgfplots}
    begin{document}
    begin{tikzpicture}begin{axis}[xmin=0,xmax=1,ymin=0,xtick={0.5},xticklabels=$a$,axis lines=left,ymajorticks=false,xlabel=$x$,ylabel=$y$,clip=false]
    addplot [domain=0.1:0.5] {0.1+x^2} node [pos=0.2,above left] {$f$};
    addplot [domain=0.5:0.9] {0.1+(x-1)^2} node[pin={90: $f'(a)$ does not exist.} ] at (axis cs:0.5,0.35) {};
    end{axis}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer
























    • @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

      – MathScholar
      Nov 30 '18 at 15:41


















    4














    Here is a solution using the pgfplots package, which extends tikz to include a wide variety of plotting options:



    documentclass{article}
    usepackage{pgfplots}
    begin{document}
    begin{tikzpicture}begin{axis}[xmin=0,xmax=1,ymin=0,xtick={0.5},xticklabels=$a$,axis lines=left,ymajorticks=false,xlabel=$x$,ylabel=$y$,clip=false]
    addplot [domain=0.1:0.5] {0.1+x^2} node [pos=0.2,above left] {$f$};
    addplot [domain=0.5:0.9] {0.1+(x-1)^2} node[pin={90: $f'(a)$ does not exist.} ] at (axis cs:0.5,0.35) {};
    end{axis}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer
























    • @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

      – MathScholar
      Nov 30 '18 at 15:41
















    4












    4








    4







    Here is a solution using the pgfplots package, which extends tikz to include a wide variety of plotting options:



    documentclass{article}
    usepackage{pgfplots}
    begin{document}
    begin{tikzpicture}begin{axis}[xmin=0,xmax=1,ymin=0,xtick={0.5},xticklabels=$a$,axis lines=left,ymajorticks=false,xlabel=$x$,ylabel=$y$,clip=false]
    addplot [domain=0.1:0.5] {0.1+x^2} node [pos=0.2,above left] {$f$};
    addplot [domain=0.5:0.9] {0.1+(x-1)^2} node[pin={90: $f'(a)$ does not exist.} ] at (axis cs:0.5,0.35) {};
    end{axis}
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer













    Here is a solution using the pgfplots package, which extends tikz to include a wide variety of plotting options:



    documentclass{article}
    usepackage{pgfplots}
    begin{document}
    begin{tikzpicture}begin{axis}[xmin=0,xmax=1,ymin=0,xtick={0.5},xticklabels=$a$,axis lines=left,ymajorticks=false,xlabel=$x$,ylabel=$y$,clip=false]
    addplot [domain=0.1:0.5] {0.1+x^2} node [pos=0.2,above left] {$f$};
    addplot [domain=0.5:0.9] {0.1+(x-1)^2} node[pin={90: $f'(a)$ does not exist.} ] at (axis cs:0.5,0.35) {};
    end{axis}
    end{tikzpicture}
    end{document}


    enter image description here







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 30 '18 at 15:32









    UbiquitousUbiquitous

    1,6661020




    1,6661020













    • @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

      – MathScholar
      Nov 30 '18 at 15:41





















    • @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

      – MathScholar
      Nov 30 '18 at 15:41



















    @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

    – MathScholar
    Nov 30 '18 at 15:41







    @Ubiquitos Thank you for your answer. I needed a corner with a more vertical right and left tangent, but someone else will find this very useful to them. Thanks for sharing

    – MathScholar
    Nov 30 '18 at 15:41













    2














    A PSTricks solution just for comparison purposes.



    documentclass[pstricks]{standalone}
    usepackage{pst-plot,pst-plot}
    deff#1{(x-#1)^2+1}
    begin{document}
    begin{pspicture}[algebraic,ticks=none,labels=none](-.4,-.5)(4.5,3.5)
    psaxes{->}(0,0)(-.3,-.4)(4,3)[$x$,0][$y$,90]
    psplot{1}{2}{f{1}}
    psplot{2}{3}{f{3}}
    psxTick[labelsep=1pt](2){a}
    rput(2.2,3){rnode[b]{a}{$f'(a)$ does not exist}}
    pcline[nodesep=2pt]{->}(a)(*2 {f{1}})
    end{pspicture}
    end{document}


    enter image description here






    share|improve this answer




























      2














      A PSTricks solution just for comparison purposes.



      documentclass[pstricks]{standalone}
      usepackage{pst-plot,pst-plot}
      deff#1{(x-#1)^2+1}
      begin{document}
      begin{pspicture}[algebraic,ticks=none,labels=none](-.4,-.5)(4.5,3.5)
      psaxes{->}(0,0)(-.3,-.4)(4,3)[$x$,0][$y$,90]
      psplot{1}{2}{f{1}}
      psplot{2}{3}{f{3}}
      psxTick[labelsep=1pt](2){a}
      rput(2.2,3){rnode[b]{a}{$f'(a)$ does not exist}}
      pcline[nodesep=2pt]{->}(a)(*2 {f{1}})
      end{pspicture}
      end{document}


      enter image description here






      share|improve this answer


























        2












        2








        2







        A PSTricks solution just for comparison purposes.



        documentclass[pstricks]{standalone}
        usepackage{pst-plot,pst-plot}
        deff#1{(x-#1)^2+1}
        begin{document}
        begin{pspicture}[algebraic,ticks=none,labels=none](-.4,-.5)(4.5,3.5)
        psaxes{->}(0,0)(-.3,-.4)(4,3)[$x$,0][$y$,90]
        psplot{1}{2}{f{1}}
        psplot{2}{3}{f{3}}
        psxTick[labelsep=1pt](2){a}
        rput(2.2,3){rnode[b]{a}{$f'(a)$ does not exist}}
        pcline[nodesep=2pt]{->}(a)(*2 {f{1}})
        end{pspicture}
        end{document}


        enter image description here






        share|improve this answer













        A PSTricks solution just for comparison purposes.



        documentclass[pstricks]{standalone}
        usepackage{pst-plot,pst-plot}
        deff#1{(x-#1)^2+1}
        begin{document}
        begin{pspicture}[algebraic,ticks=none,labels=none](-.4,-.5)(4.5,3.5)
        psaxes{->}(0,0)(-.3,-.4)(4,3)[$x$,0][$y$,90]
        psplot{1}{2}{f{1}}
        psplot{2}{3}{f{3}}
        psxTick[labelsep=1pt](2){a}
        rput(2.2,3){rnode[b]{a}{$f'(a)$ does not exist}}
        pcline[nodesep=2pt]{->}(a)(*2 {f{1}})
        end{pspicture}
        end{document}


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 30 '18 at 16:54









        God Must Be CrazyGod Must Be Crazy

        6,07011039




        6,07011039






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f462564%2fmaking-a-perfect-cusp-tikz%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Bundesstraße 106

            Verónica Boquete

            Ida-Boy-Ed-Garten