Using resultants to show extension of function fields of curves is algebraic.












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We are given two irreducible nonsingular plane curves, the zero sets of $f,gin bar{k}[x,y]$, with $bar{k}$ algebraically closed. We have an injective map given on algebras as $phi^*:C_frightarrow C_g$, and we want to show the the associated field extension $Quot(C_f)rightarrow Quot(C_g)$ is algebraic.



The problem is to express that $x,yin C_g$ are algebraic over $Quot(C_f)$, using resultants. The hint given is to use the resultants $Res_x(phi^*(u),phi^*(v))$ and $Res_y(phi^*(u),phi^*(v))$, where we are using $u,v$ to be $x,y$, but relabelling to avoid overloading notation, and emphasise they are coming from $C_f$.



I dont have a good feeling for how to prove things like this using resultants, they still seem a bit mysterious to me, so any additional intuition for how to think about resultants would be very welcome.



Note, I am aware of other ways to do this problem, I am specifically looking for a resultant based solution.










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    0












    $begingroup$


    We are given two irreducible nonsingular plane curves, the zero sets of $f,gin bar{k}[x,y]$, with $bar{k}$ algebraically closed. We have an injective map given on algebras as $phi^*:C_frightarrow C_g$, and we want to show the the associated field extension $Quot(C_f)rightarrow Quot(C_g)$ is algebraic.



    The problem is to express that $x,yin C_g$ are algebraic over $Quot(C_f)$, using resultants. The hint given is to use the resultants $Res_x(phi^*(u),phi^*(v))$ and $Res_y(phi^*(u),phi^*(v))$, where we are using $u,v$ to be $x,y$, but relabelling to avoid overloading notation, and emphasise they are coming from $C_f$.



    I dont have a good feeling for how to prove things like this using resultants, they still seem a bit mysterious to me, so any additional intuition for how to think about resultants would be very welcome.



    Note, I am aware of other ways to do this problem, I am specifically looking for a resultant based solution.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      We are given two irreducible nonsingular plane curves, the zero sets of $f,gin bar{k}[x,y]$, with $bar{k}$ algebraically closed. We have an injective map given on algebras as $phi^*:C_frightarrow C_g$, and we want to show the the associated field extension $Quot(C_f)rightarrow Quot(C_g)$ is algebraic.



      The problem is to express that $x,yin C_g$ are algebraic over $Quot(C_f)$, using resultants. The hint given is to use the resultants $Res_x(phi^*(u),phi^*(v))$ and $Res_y(phi^*(u),phi^*(v))$, where we are using $u,v$ to be $x,y$, but relabelling to avoid overloading notation, and emphasise they are coming from $C_f$.



      I dont have a good feeling for how to prove things like this using resultants, they still seem a bit mysterious to me, so any additional intuition for how to think about resultants would be very welcome.



      Note, I am aware of other ways to do this problem, I am specifically looking for a resultant based solution.










      share|cite|improve this question









      $endgroup$




      We are given two irreducible nonsingular plane curves, the zero sets of $f,gin bar{k}[x,y]$, with $bar{k}$ algebraically closed. We have an injective map given on algebras as $phi^*:C_frightarrow C_g$, and we want to show the the associated field extension $Quot(C_f)rightarrow Quot(C_g)$ is algebraic.



      The problem is to express that $x,yin C_g$ are algebraic over $Quot(C_f)$, using resultants. The hint given is to use the resultants $Res_x(phi^*(u),phi^*(v))$ and $Res_y(phi^*(u),phi^*(v))$, where we are using $u,v$ to be $x,y$, but relabelling to avoid overloading notation, and emphasise they are coming from $C_f$.



      I dont have a good feeling for how to prove things like this using resultants, they still seem a bit mysterious to me, so any additional intuition for how to think about resultants would be very welcome.



      Note, I am aware of other ways to do this problem, I am specifically looking for a resultant based solution.







      algebraic-geometry algebraic-curves resultant






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      asked Dec 13 '18 at 10:06









      user277182user277182

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