find the probability that the final reading will be under 20 seconds, exponential or poission?
$begingroup$
I have used poission and exponential distrubution, I got same results but I am not sure which one is true.
"Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."
Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99
for exponential distrubution,
P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
and again I got approximately %99, which one is true?
Sorry for bad english and bad notations I'm new here, thanks.
probability probability-theory probability-distributions
$endgroup$
add a comment |
$begingroup$
I have used poission and exponential distrubution, I got same results but I am not sure which one is true.
"Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."
Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99
for exponential distrubution,
P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
and again I got approximately %99, which one is true?
Sorry for bad english and bad notations I'm new here, thanks.
probability probability-theory probability-distributions
$endgroup$
add a comment |
$begingroup$
I have used poission and exponential distrubution, I got same results but I am not sure which one is true.
"Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."
Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99
for exponential distrubution,
P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
and again I got approximately %99, which one is true?
Sorry for bad english and bad notations I'm new here, thanks.
probability probability-theory probability-distributions
$endgroup$
I have used poission and exponential distrubution, I got same results but I am not sure which one is true.
"Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."
Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99
for exponential distrubution,
P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
and again I got approximately %99, which one is true?
Sorry for bad english and bad notations I'm new here, thanks.
probability probability-theory probability-distributions
probability probability-theory probability-distributions
edited Dec 30 '18 at 8:07
Emre Akcan
asked Dec 29 '18 at 16:20
Emre AkcanEmre Akcan
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12
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