find the probability that the final reading will be under 20 seconds, exponential or poission?












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$begingroup$


I have used poission and exponential distrubution, I got same results but I am not sure which one is true.



"Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."



Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99



for exponential distrubution,
P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
and again I got approximately %99, which one is true?



Sorry for bad english and bad notations I'm new here, thanks.










share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    I have used poission and exponential distrubution, I got same results but I am not sure which one is true.



    "Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."



    Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99



    for exponential distrubution,
    P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
    and again I got approximately %99, which one is true?



    Sorry for bad english and bad notations I'm new here, thanks.










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I have used poission and exponential distrubution, I got same results but I am not sure which one is true.



      "Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."



      Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99



      for exponential distrubution,
      P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
      and again I got approximately %99, which one is true?



      Sorry for bad english and bad notations I'm new here, thanks.










      share|cite|improve this question











      $endgroup$




      I have used poission and exponential distrubution, I got same results but I am not sure which one is true.



      "Particles arrive independently at a detector at the average rate of 3 per second, you are timing how long it takes from the last arrival to the next arrival. The reading on the stopwatch is past 7 seconds already find the probability that the final reading will be under 20 seconds."



      Firstly I got the sum of all values to (P=7) to (P=20) with poission distrubution formula. I got approximately %99



      for exponential distrubution,
      P(X<20 | X> 7) = P(x<13) after that I integrate 0 to 13 the 3e^(-3t)
      and again I got approximately %99, which one is true?



      Sorry for bad english and bad notations I'm new here, thanks.







      probability probability-theory probability-distributions






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Dec 30 '18 at 8:07







      Emre Akcan

















      asked Dec 29 '18 at 16:20









      Emre AkcanEmre Akcan

      12




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