Proving Ratios And Proportions
$begingroup$
Help me solve this problem!
I have tried it many times but nothing appeared.
This is the question:
If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).
ratio
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add a comment |
$begingroup$
Help me solve this problem!
I have tried it many times but nothing appeared.
This is the question:
If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).
ratio
$endgroup$
add a comment |
$begingroup$
Help me solve this problem!
I have tried it many times but nothing appeared.
This is the question:
If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).
ratio
$endgroup$
Help me solve this problem!
I have tried it many times but nothing appeared.
This is the question:
If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).
ratio
ratio
asked Oct 16 '14 at 11:02
Wilson Royce Ong KingWilson Royce Ong King
1
1
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1 Answer
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$begingroup$
Let $$frac ab=frac cd=frac ef=k$$
$implies Xa+Yc+Ze=k(Xb+Yd+Zd)$
$endgroup$
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
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– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Let $$frac ab=frac cd=frac ef=k$$
$implies Xa+Yc+Ze=k(Xb+Yd+Zd)$
$endgroup$
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
$endgroup$
– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
add a comment |
$begingroup$
Let $$frac ab=frac cd=frac ef=k$$
$implies Xa+Yc+Ze=k(Xb+Yd+Zd)$
$endgroup$
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
$endgroup$
– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
add a comment |
$begingroup$
Let $$frac ab=frac cd=frac ef=k$$
$implies Xa+Yc+Ze=k(Xb+Yd+Zd)$
$endgroup$
Let $$frac ab=frac cd=frac ef=k$$
$implies Xa+Yc+Ze=k(Xb+Yd+Zd)$
answered Oct 16 '14 at 11:04
lab bhattacharjeelab bhattacharjee
229k15159280
229k15159280
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
$endgroup$
– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
add a comment |
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
$endgroup$
– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
$endgroup$
– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
$endgroup$
– Wilson Royce Ong King
Oct 16 '14 at 11:09
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
$begingroup$
@WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
$endgroup$
– lab bhattacharjee
Oct 16 '14 at 11:16
add a comment |
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