$1-r$ unit in ring with $r^n = 0$ [duplicate]











up vote
0
down vote

favorite













This question already has an answer here:




  • Units and Nilpotents

    3 answers




Let $R$ be a ring with $r in R$ and $r^n = 0$ for $n in mathbb{N}$. Show that $1-r$ is a unit in $R$.



I tried to use the geometric sum but I dont know how to proceed.










share|cite|improve this question













marked as duplicate by rschwieb abstract-algebra
Users with the  abstract-algebra badge can single-handedly close abstract-algebra questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 19 at 15:31


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • That technique works. Note that it is a finite sum by your assumption.
    – Randall
    Nov 19 at 15:27










  • I dont know how to apply this correctly to the task
    – Arjihad
    Nov 19 at 15:29










  • See also here.
    – Bill Dubuque
    Nov 19 at 15:56















up vote
0
down vote

favorite













This question already has an answer here:




  • Units and Nilpotents

    3 answers




Let $R$ be a ring with $r in R$ and $r^n = 0$ for $n in mathbb{N}$. Show that $1-r$ is a unit in $R$.



I tried to use the geometric sum but I dont know how to proceed.










share|cite|improve this question













marked as duplicate by rschwieb abstract-algebra
Users with the  abstract-algebra badge can single-handedly close abstract-algebra questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 19 at 15:31


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • That technique works. Note that it is a finite sum by your assumption.
    – Randall
    Nov 19 at 15:27










  • I dont know how to apply this correctly to the task
    – Arjihad
    Nov 19 at 15:29










  • See also here.
    – Bill Dubuque
    Nov 19 at 15:56













up vote
0
down vote

favorite









up vote
0
down vote

favorite












This question already has an answer here:




  • Units and Nilpotents

    3 answers




Let $R$ be a ring with $r in R$ and $r^n = 0$ for $n in mathbb{N}$. Show that $1-r$ is a unit in $R$.



I tried to use the geometric sum but I dont know how to proceed.










share|cite|improve this question














This question already has an answer here:




  • Units and Nilpotents

    3 answers




Let $R$ be a ring with $r in R$ and $r^n = 0$ for $n in mathbb{N}$. Show that $1-r$ is a unit in $R$.



I tried to use the geometric sum but I dont know how to proceed.





This question already has an answer here:




  • Units and Nilpotents

    3 answers








abstract-algebra ring-theory






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 19 at 15:27









Arjihad

374111




374111




marked as duplicate by rschwieb abstract-algebra
Users with the  abstract-algebra badge can single-handedly close abstract-algebra questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 19 at 15:31


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by rschwieb abstract-algebra
Users with the  abstract-algebra badge can single-handedly close abstract-algebra questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 19 at 15:31


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • That technique works. Note that it is a finite sum by your assumption.
    – Randall
    Nov 19 at 15:27










  • I dont know how to apply this correctly to the task
    – Arjihad
    Nov 19 at 15:29










  • See also here.
    – Bill Dubuque
    Nov 19 at 15:56


















  • That technique works. Note that it is a finite sum by your assumption.
    – Randall
    Nov 19 at 15:27










  • I dont know how to apply this correctly to the task
    – Arjihad
    Nov 19 at 15:29










  • See also here.
    – Bill Dubuque
    Nov 19 at 15:56
















That technique works. Note that it is a finite sum by your assumption.
– Randall
Nov 19 at 15:27




That technique works. Note that it is a finite sum by your assumption.
– Randall
Nov 19 at 15:27












I dont know how to apply this correctly to the task
– Arjihad
Nov 19 at 15:29




I dont know how to apply this correctly to the task
– Arjihad
Nov 19 at 15:29












See also here.
– Bill Dubuque
Nov 19 at 15:56




See also here.
– Bill Dubuque
Nov 19 at 15:56










1 Answer
1






active

oldest

votes

















up vote
3
down vote



accepted










We have $(1-r)(1+r+ldots+r^{n-1}) = 1$ if $r^n=0$.






share|cite|improve this answer

















  • 1




    This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
    – rschwieb
    Nov 19 at 15:32


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










We have $(1-r)(1+r+ldots+r^{n-1}) = 1$ if $r^n=0$.






share|cite|improve this answer

















  • 1




    This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
    – rschwieb
    Nov 19 at 15:32















up vote
3
down vote



accepted










We have $(1-r)(1+r+ldots+r^{n-1}) = 1$ if $r^n=0$.






share|cite|improve this answer

















  • 1




    This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
    – rschwieb
    Nov 19 at 15:32













up vote
3
down vote



accepted







up vote
3
down vote



accepted






We have $(1-r)(1+r+ldots+r^{n-1}) = 1$ if $r^n=0$.






share|cite|improve this answer












We have $(1-r)(1+r+ldots+r^{n-1}) = 1$ if $r^n=0$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 19 at 15:29









Wuestenfux

2,5921410




2,5921410








  • 1




    This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
    – rschwieb
    Nov 19 at 15:32














  • 1




    This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
    – rschwieb
    Nov 19 at 15:32








1




1




This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
– rschwieb
Nov 19 at 15:32




This is one of the most duplicated questions on the site. Please next time duplicate it as such instead of answering Thanks.
– rschwieb
Nov 19 at 15:32



Popular posts from this blog

Bundesstraße 106

Verónica Boquete

Ida-Boy-Ed-Garten