how to solve $dy/dx=(x-y-3)/(x+y+7)$ [closed]
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I'm trying to solve equations:
$(x-y-3)dx-(x+y+7)dy=0$
Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.
differential-equations
closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48
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If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
-3
down vote
favorite
I'm trying to solve equations:
$(x-y-3)dx-(x+y+7)dy=0$
Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.
differential-equations
closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn
If this question can be reworded to fit the rules in the help center, please edit the question.
Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11
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up vote
-3
down vote
favorite
up vote
-3
down vote
favorite
I'm trying to solve equations:
$(x-y-3)dx-(x+y+7)dy=0$
Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.
differential-equations
I'm trying to solve equations:
$(x-y-3)dx-(x+y+7)dy=0$
Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.
differential-equations
differential-equations
edited Nov 24 at 1:35
Key Flex
7,44941232
7,44941232
asked Nov 24 at 1:34
Student Bilad Al Rafidain
31
31
closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn
If this question can be reworded to fit the rules in the help center, please edit the question.
Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11
add a comment |
Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11
Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11
Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11
add a comment |
2 Answers
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$(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$
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$$(x-y-3)dx-(x+y+7)dy=0$$
$$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
$$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
Integrate
$$frac 12x^2-3x-xy-frac 12y^2-7y=K$$
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
$(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$
add a comment |
up vote
2
down vote
accepted
$(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
$(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$
$(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$
answered Nov 24 at 1:44
John_Wick
1,224111
1,224111
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$$(x-y-3)dx-(x+y+7)dy=0$$
$$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
$$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
Integrate
$$frac 12x^2-3x-xy-frac 12y^2-7y=K$$
add a comment |
up vote
0
down vote
$$(x-y-3)dx-(x+y+7)dy=0$$
$$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
$$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
Integrate
$$frac 12x^2-3x-xy-frac 12y^2-7y=K$$
add a comment |
up vote
0
down vote
up vote
0
down vote
$$(x-y-3)dx-(x+y+7)dy=0$$
$$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
$$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
Integrate
$$frac 12x^2-3x-xy-frac 12y^2-7y=K$$
$$(x-y-3)dx-(x+y+7)dy=0$$
$$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
$$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
Integrate
$$frac 12x^2-3x-xy-frac 12y^2-7y=K$$
answered Nov 24 at 2:52
Isham
12.7k3929
12.7k3929
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Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11