how to solve $dy/dx=(x-y-3)/(x+y+7)$ [closed]











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I'm trying to solve equations:



$(x-y-3)dx-(x+y+7)dy=0$



Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.










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closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
    – Seth
    Nov 24 at 2:11















up vote
-3
down vote

favorite
1












I'm trying to solve equations:



$(x-y-3)dx-(x+y+7)dy=0$



Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.










share|cite|improve this question















closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
    – Seth
    Nov 24 at 2:11













up vote
-3
down vote

favorite
1









up vote
-3
down vote

favorite
1






1





I'm trying to solve equations:



$(x-y-3)dx-(x+y+7)dy=0$



Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.










share|cite|improve this question















I'm trying to solve equations:



$(x-y-3)dx-(x+y+7)dy=0$



Please show how to complete the equation, so that it becomes exact. Thank you for help in advance.







differential-equations






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edited Nov 24 at 1:35









Key Flex

7,44941232




7,44941232










asked Nov 24 at 1:34









Student Bilad Al Rafidain

31




31




closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Shailesh, Key Flex, Nosrati, Leucippus, max_zorn Nov 24 at 3:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shailesh, Key Flex, Nosrati, Leucippus, max_zorn

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
    – Seth
    Nov 24 at 2:11


















  • Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
    – Seth
    Nov 24 at 2:11
















Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11




Use the substitution $X-Y=x-y-3$, $X+Y=x+y+7$ and then solve by normal methods
– Seth
Nov 24 at 2:11










2 Answers
2






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$(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$






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    $$(x-y-3)dx-(x+y+7)dy=0$$
    $$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
    $$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
    Integrate
    $$frac 12x^2-3x-xy-frac 12y^2-7y=K$$






    share|cite|improve this answer




























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      2
      down vote



      accepted










      $(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$






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        up vote
        2
        down vote



        accepted










        $(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$






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          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          $(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$






          share|cite|improve this answer












          $(x-y-3)dx-(x+y+7)dy=0Rightarrow (x-3)dx-(ydx+xdy)-(y+7)dy=0Rightarrow int (x-3)dx-int (ydx+xdy)-int(y+7)dy=c Rightarrow (x-3)^2/2-xy-(y+7)^2/2 =c.$







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          answered Nov 24 at 1:44









          John_Wick

          1,224111




          1,224111






















              up vote
              0
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              $$(x-y-3)dx-(x+y+7)dy=0$$
              $$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
              $$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
              Integrate
              $$frac 12x^2-3x-xy-frac 12y^2-7y=K$$






              share|cite|improve this answer

























                up vote
                0
                down vote













                $$(x-y-3)dx-(x+y+7)dy=0$$
                $$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
                $$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
                Integrate
                $$frac 12x^2-3x-xy-frac 12y^2-7y=K$$






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  $$(x-y-3)dx-(x+y+7)dy=0$$
                  $$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
                  $$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
                  Integrate
                  $$frac 12x^2-3x-xy-frac 12y^2-7y=K$$






                  share|cite|improve this answer












                  $$(x-y-3)dx-(x+y+7)dy=0$$
                  $$frac 12dx^2-3dx-ydx-xdy-frac 12dy^2-7dy=0$$
                  $$frac 12dx^2-3dx-dxy-frac 12dy^2-7dy=0$$
                  Integrate
                  $$frac 12x^2-3x-xy-frac 12y^2-7y=K$$







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 24 at 2:52









                  Isham

                  12.7k3929




                  12.7k3929















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