Is Pattern Matching as expressive as Case Expression in Haskell?











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1
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Nomenclature



The term expressive in the question shall bear the same meaning as in the following sentence:




A Turing Machine is as expressive as Lambda Calculus.




Introduction



While learning Haskell, I had noticed that there are 2 ways to achieve the same effect, namely Pattern Matching and Case Expression. For example,



-- Pattern Matching
not True = False
not False = True

-- Case Expression
not x = case x of True -> False
False -> True


I am also fully aware that Pattern Matching is actually a form of syntax sugar that will be compiled into Case Expression.



Therefore, we can be very sure that every Pattern Matching expression can be converted to Case Expression.



Question



So, this is my question: Is the following statement true?




Every Case Expression can be re-written using Pattern Matching.




Regardless of the truthiness of the statement above, I would be glad if you could provide a formal proof to support your answer.



P/S



The motivation that drove me to seek answer for this question is because I'm currently designing my own language, which I wish to have as less feature as possible, but not too minimal like Lambda Calculus which only have 3 features.










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  • Pattern matching at the function head is compiled, more or less, to case expressions in the function body. Further, your use of case expressions involves pattern matching; pattern matching vs case expressions is a bit of an apples-to-oranges comparison.
    – pdexter
    yesterday










  • Note that Haskell-specific questions are off-topic here. However, pattern matching is a concept general enough that this question can be made on-topic, removing the Haskell-specific parts.
    – chi
    yesterday






  • 1




    You definitely don't want the meaning of "expressive" that makes Turing machines and the untyped lambda calculus equally "expressive". Haskell without pattern matching or Haskell without case statements are both Turing-complete and so would be equally as "expressive" by that meaning. Haskell without either is Turing-complete. It is very rare that you want to compare programming languages based on what functions they can compute. See On the expressive power of programming languages by Matthias Felleisen for an alternative.
    – Derek Elkins
    yesterday










  • @Derek Thanks for the white paper !
    – Wong Jia Hau
    yesterday















up vote
1
down vote

favorite












Nomenclature



The term expressive in the question shall bear the same meaning as in the following sentence:




A Turing Machine is as expressive as Lambda Calculus.




Introduction



While learning Haskell, I had noticed that there are 2 ways to achieve the same effect, namely Pattern Matching and Case Expression. For example,



-- Pattern Matching
not True = False
not False = True

-- Case Expression
not x = case x of True -> False
False -> True


I am also fully aware that Pattern Matching is actually a form of syntax sugar that will be compiled into Case Expression.



Therefore, we can be very sure that every Pattern Matching expression can be converted to Case Expression.



Question



So, this is my question: Is the following statement true?




Every Case Expression can be re-written using Pattern Matching.




Regardless of the truthiness of the statement above, I would be glad if you could provide a formal proof to support your answer.



P/S



The motivation that drove me to seek answer for this question is because I'm currently designing my own language, which I wish to have as less feature as possible, but not too minimal like Lambda Calculus which only have 3 features.










share|cite|improve this question
























  • Pattern matching at the function head is compiled, more or less, to case expressions in the function body. Further, your use of case expressions involves pattern matching; pattern matching vs case expressions is a bit of an apples-to-oranges comparison.
    – pdexter
    yesterday










  • Note that Haskell-specific questions are off-topic here. However, pattern matching is a concept general enough that this question can be made on-topic, removing the Haskell-specific parts.
    – chi
    yesterday






  • 1




    You definitely don't want the meaning of "expressive" that makes Turing machines and the untyped lambda calculus equally "expressive". Haskell without pattern matching or Haskell without case statements are both Turing-complete and so would be equally as "expressive" by that meaning. Haskell without either is Turing-complete. It is very rare that you want to compare programming languages based on what functions they can compute. See On the expressive power of programming languages by Matthias Felleisen for an alternative.
    – Derek Elkins
    yesterday










  • @Derek Thanks for the white paper !
    – Wong Jia Hau
    yesterday













up vote
1
down vote

favorite









up vote
1
down vote

favorite











Nomenclature



The term expressive in the question shall bear the same meaning as in the following sentence:




A Turing Machine is as expressive as Lambda Calculus.




Introduction



While learning Haskell, I had noticed that there are 2 ways to achieve the same effect, namely Pattern Matching and Case Expression. For example,



-- Pattern Matching
not True = False
not False = True

-- Case Expression
not x = case x of True -> False
False -> True


I am also fully aware that Pattern Matching is actually a form of syntax sugar that will be compiled into Case Expression.



Therefore, we can be very sure that every Pattern Matching expression can be converted to Case Expression.



Question



So, this is my question: Is the following statement true?




Every Case Expression can be re-written using Pattern Matching.




Regardless of the truthiness of the statement above, I would be glad if you could provide a formal proof to support your answer.



P/S



The motivation that drove me to seek answer for this question is because I'm currently designing my own language, which I wish to have as less feature as possible, but not too minimal like Lambda Calculus which only have 3 features.










share|cite|improve this question















Nomenclature



The term expressive in the question shall bear the same meaning as in the following sentence:




A Turing Machine is as expressive as Lambda Calculus.




Introduction



While learning Haskell, I had noticed that there are 2 ways to achieve the same effect, namely Pattern Matching and Case Expression. For example,



-- Pattern Matching
not True = False
not False = True

-- Case Expression
not x = case x of True -> False
False -> True


I am also fully aware that Pattern Matching is actually a form of syntax sugar that will be compiled into Case Expression.



Therefore, we can be very sure that every Pattern Matching expression can be converted to Case Expression.



Question



So, this is my question: Is the following statement true?




Every Case Expression can be re-written using Pattern Matching.




Regardless of the truthiness of the statement above, I would be glad if you could provide a formal proof to support your answer.



P/S



The motivation that drove me to seek answer for this question is because I'm currently designing my own language, which I wish to have as less feature as possible, but not too minimal like Lambda Calculus which only have 3 features.







functional-programming haskell






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited yesterday

























asked yesterday









Wong Jia Hau

1605




1605












  • Pattern matching at the function head is compiled, more or less, to case expressions in the function body. Further, your use of case expressions involves pattern matching; pattern matching vs case expressions is a bit of an apples-to-oranges comparison.
    – pdexter
    yesterday










  • Note that Haskell-specific questions are off-topic here. However, pattern matching is a concept general enough that this question can be made on-topic, removing the Haskell-specific parts.
    – chi
    yesterday






  • 1




    You definitely don't want the meaning of "expressive" that makes Turing machines and the untyped lambda calculus equally "expressive". Haskell without pattern matching or Haskell without case statements are both Turing-complete and so would be equally as "expressive" by that meaning. Haskell without either is Turing-complete. It is very rare that you want to compare programming languages based on what functions they can compute. See On the expressive power of programming languages by Matthias Felleisen for an alternative.
    – Derek Elkins
    yesterday










  • @Derek Thanks for the white paper !
    – Wong Jia Hau
    yesterday


















  • Pattern matching at the function head is compiled, more or less, to case expressions in the function body. Further, your use of case expressions involves pattern matching; pattern matching vs case expressions is a bit of an apples-to-oranges comparison.
    – pdexter
    yesterday










  • Note that Haskell-specific questions are off-topic here. However, pattern matching is a concept general enough that this question can be made on-topic, removing the Haskell-specific parts.
    – chi
    yesterday






  • 1




    You definitely don't want the meaning of "expressive" that makes Turing machines and the untyped lambda calculus equally "expressive". Haskell without pattern matching or Haskell without case statements are both Turing-complete and so would be equally as "expressive" by that meaning. Haskell without either is Turing-complete. It is very rare that you want to compare programming languages based on what functions they can compute. See On the expressive power of programming languages by Matthias Felleisen for an alternative.
    – Derek Elkins
    yesterday










  • @Derek Thanks for the white paper !
    – Wong Jia Hau
    yesterday
















Pattern matching at the function head is compiled, more or less, to case expressions in the function body. Further, your use of case expressions involves pattern matching; pattern matching vs case expressions is a bit of an apples-to-oranges comparison.
– pdexter
yesterday




Pattern matching at the function head is compiled, more or less, to case expressions in the function body. Further, your use of case expressions involves pattern matching; pattern matching vs case expressions is a bit of an apples-to-oranges comparison.
– pdexter
yesterday












Note that Haskell-specific questions are off-topic here. However, pattern matching is a concept general enough that this question can be made on-topic, removing the Haskell-specific parts.
– chi
yesterday




Note that Haskell-specific questions are off-topic here. However, pattern matching is a concept general enough that this question can be made on-topic, removing the Haskell-specific parts.
– chi
yesterday




1




1




You definitely don't want the meaning of "expressive" that makes Turing machines and the untyped lambda calculus equally "expressive". Haskell without pattern matching or Haskell without case statements are both Turing-complete and so would be equally as "expressive" by that meaning. Haskell without either is Turing-complete. It is very rare that you want to compare programming languages based on what functions they can compute. See On the expressive power of programming languages by Matthias Felleisen for an alternative.
– Derek Elkins
yesterday




You definitely don't want the meaning of "expressive" that makes Turing machines and the untyped lambda calculus equally "expressive". Haskell without pattern matching or Haskell without case statements are both Turing-complete and so would be equally as "expressive" by that meaning. Haskell without either is Turing-complete. It is very rare that you want to compare programming languages based on what functions they can compute. See On the expressive power of programming languages by Matthias Felleisen for an alternative.
– Derek Elkins
yesterday












@Derek Thanks for the white paper !
– Wong Jia Hau
yesterday




@Derek Thanks for the white paper !
– Wong Jia Hau
yesterday










1 Answer
1






active

oldest

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up vote
4
down vote













The expression



case e of
p1 -> e1
p2 -> e2
...


can be rewritten as



let k p1 = e1
k p2 = e2
...
in k e


where k is a fresh identifier.



This translation assumes that the language has some way to define a local function by pattern matching (e.g. let).





If local functions can not be defined, there's always the possibility of lifting the definition to the top level. Indeed, any local definition



let f x1 ... xk = e in e'


having free variables v1 .. vn can be rewritten written as



(f -> e') (globalF v1 ... vn)


provided that we also define a global function



globalF v1 ... vn x1 ... xk = e


Note that globalF has no free variables, by construction. I believe it is sometimes called a "supercombinator".



This naturally extends to the case where x1 ... xk are patterns, and we have multiple defining equations for f / globalF.





For example,



case x of True  -> False
False -> True


cab be rewritten as



let f True  = False
f False = True
in f x





share|cite|improve this answer























  • Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
    – Wong Jia Hau
    yesterday












  • @WongJiaHau See the last edit for an example.
    – chi
    yesterday










  • Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
    – Wong Jia Hau
    yesterday










  • @WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
    – chi
    yesterday











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up vote
4
down vote













The expression



case e of
p1 -> e1
p2 -> e2
...


can be rewritten as



let k p1 = e1
k p2 = e2
...
in k e


where k is a fresh identifier.



This translation assumes that the language has some way to define a local function by pattern matching (e.g. let).





If local functions can not be defined, there's always the possibility of lifting the definition to the top level. Indeed, any local definition



let f x1 ... xk = e in e'


having free variables v1 .. vn can be rewritten written as



(f -> e') (globalF v1 ... vn)


provided that we also define a global function



globalF v1 ... vn x1 ... xk = e


Note that globalF has no free variables, by construction. I believe it is sometimes called a "supercombinator".



This naturally extends to the case where x1 ... xk are patterns, and we have multiple defining equations for f / globalF.





For example,



case x of True  -> False
False -> True


cab be rewritten as



let f True  = False
f False = True
in f x





share|cite|improve this answer























  • Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
    – Wong Jia Hau
    yesterday












  • @WongJiaHau See the last edit for an example.
    – chi
    yesterday










  • Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
    – Wong Jia Hau
    yesterday










  • @WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
    – chi
    yesterday















up vote
4
down vote













The expression



case e of
p1 -> e1
p2 -> e2
...


can be rewritten as



let k p1 = e1
k p2 = e2
...
in k e


where k is a fresh identifier.



This translation assumes that the language has some way to define a local function by pattern matching (e.g. let).





If local functions can not be defined, there's always the possibility of lifting the definition to the top level. Indeed, any local definition



let f x1 ... xk = e in e'


having free variables v1 .. vn can be rewritten written as



(f -> e') (globalF v1 ... vn)


provided that we also define a global function



globalF v1 ... vn x1 ... xk = e


Note that globalF has no free variables, by construction. I believe it is sometimes called a "supercombinator".



This naturally extends to the case where x1 ... xk are patterns, and we have multiple defining equations for f / globalF.





For example,



case x of True  -> False
False -> True


cab be rewritten as



let f True  = False
f False = True
in f x





share|cite|improve this answer























  • Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
    – Wong Jia Hau
    yesterday












  • @WongJiaHau See the last edit for an example.
    – chi
    yesterday










  • Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
    – Wong Jia Hau
    yesterday










  • @WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
    – chi
    yesterday













up vote
4
down vote










up vote
4
down vote









The expression



case e of
p1 -> e1
p2 -> e2
...


can be rewritten as



let k p1 = e1
k p2 = e2
...
in k e


where k is a fresh identifier.



This translation assumes that the language has some way to define a local function by pattern matching (e.g. let).





If local functions can not be defined, there's always the possibility of lifting the definition to the top level. Indeed, any local definition



let f x1 ... xk = e in e'


having free variables v1 .. vn can be rewritten written as



(f -> e') (globalF v1 ... vn)


provided that we also define a global function



globalF v1 ... vn x1 ... xk = e


Note that globalF has no free variables, by construction. I believe it is sometimes called a "supercombinator".



This naturally extends to the case where x1 ... xk are patterns, and we have multiple defining equations for f / globalF.





For example,



case x of True  -> False
False -> True


cab be rewritten as



let f True  = False
f False = True
in f x





share|cite|improve this answer














The expression



case e of
p1 -> e1
p2 -> e2
...


can be rewritten as



let k p1 = e1
k p2 = e2
...
in k e


where k is a fresh identifier.



This translation assumes that the language has some way to define a local function by pattern matching (e.g. let).





If local functions can not be defined, there's always the possibility of lifting the definition to the top level. Indeed, any local definition



let f x1 ... xk = e in e'


having free variables v1 .. vn can be rewritten written as



(f -> e') (globalF v1 ... vn)


provided that we also define a global function



globalF v1 ... vn x1 ... xk = e


Note that globalF has no free variables, by construction. I believe it is sometimes called a "supercombinator".



This naturally extends to the case where x1 ... xk are patterns, and we have multiple defining equations for f / globalF.





For example,



case x of True  -> False
False -> True


cab be rewritten as



let f True  = False
f False = True
in f x






share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited yesterday

























answered yesterday









chi

11.2k1629




11.2k1629












  • Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
    – Wong Jia Hau
    yesterday












  • @WongJiaHau See the last edit for an example.
    – chi
    yesterday










  • Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
    – Wong Jia Hau
    yesterday










  • @WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
    – chi
    yesterday


















  • Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
    – Wong Jia Hau
    yesterday












  • @WongJiaHau See the last edit for an example.
    – chi
    yesterday










  • Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
    – Wong Jia Hau
    yesterday










  • @WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
    – chi
    yesterday
















Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
– Wong Jia Hau
yesterday






Apologies I don’t really understand how this answers my question ? Do you mind to be more concise ? For example provide your stance upon the statement I thrown out?
– Wong Jia Hau
yesterday














@WongJiaHau See the last edit for an example.
– chi
yesterday




@WongJiaHau See the last edit for an example.
– chi
yesterday












Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
– Wong Jia Hau
yesterday




Thanks, but does that mean any other Case Expression can be rewritten eith pattern matching ? For example, how would you write the definition of fmap using only Pattern Matching?
– Wong Jia Hau
yesterday












@WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
– chi
yesterday




@WongJiaHau Above I showed how to translate any case into a let expression. You should be able to apply it to any case expression.
– chi
yesterday


















 

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