Surface Integral of a Cone












-1














I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?



Thanks
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  • Here's a MathJax tutorial :)
    – Shaun
    Nov 26 at 21:09










  • Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
    – Ted Shifrin
    Nov 26 at 21:34
















-1














I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?



Thanks
http://prntscr.com/lnbeur










share|cite|improve this question
























  • Here's a MathJax tutorial :)
    – Shaun
    Nov 26 at 21:09










  • Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
    – Ted Shifrin
    Nov 26 at 21:34














-1












-1








-1







I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?



Thanks
http://prntscr.com/lnbeur










share|cite|improve this question















I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?



Thanks
http://prntscr.com/lnbeur







surface-integrals divergence






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edited Nov 26 at 21:24

























asked Nov 26 at 21:07









Dominic Broadbent

11




11












  • Here's a MathJax tutorial :)
    – Shaun
    Nov 26 at 21:09










  • Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
    – Ted Shifrin
    Nov 26 at 21:34


















  • Here's a MathJax tutorial :)
    – Shaun
    Nov 26 at 21:09










  • Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
    – Ted Shifrin
    Nov 26 at 21:34
















Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09




Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09












Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34




Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34















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