Surface Integral of a Cone
I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?
Thanks
http://prntscr.com/lnbeur
surface-integrals divergence
add a comment |
I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?
Thanks
http://prntscr.com/lnbeur
surface-integrals divergence
Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09
Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34
add a comment |
I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?
Thanks
http://prntscr.com/lnbeur
surface-integrals divergence
I've been staring at Q1b) for ages, I've tried using cylindrical co-ordinates. But I keep on ending up with the area of the top circle being (pi * h3) /2 which is obviously wrong so I can't possibly be doing the curved bit right either.. I've attempted part c) and got pi*h^3 + 2 * pi * h2 which seems more correct but that cubic part is wrong I think. Would love some help pointing me in the right direction as I'm not really even sure what they're asking me. Am I trying to find the surface area?
Thanks
http://prntscr.com/lnbeur
surface-integrals divergence
surface-integrals divergence
edited Nov 26 at 21:24
asked Nov 26 at 21:07
Dominic Broadbent
11
11
Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09
Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34
add a comment |
Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09
Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34
Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09
Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09
Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34
Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34
add a comment |
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Here's a MathJax tutorial :)
– Shaun
Nov 26 at 21:09
Welcome to MSE. Unfortunately, we aren't mind-readers, so you're going to have to type up your work (hopefully, using some MathJax) so that we can see what you're doing. Otherwise, we can't guess how to comment.
– Ted Shifrin
Nov 26 at 21:34