What is the inverse of X modulo $1 + X + X^2 + X^3 + X^4$? [duplicate]
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This question already has an answer here:
Let $theta$ be a root of $p(x)=x^3+9x+6$, find the inverse of $1+theta$ in $mathbb{Q(theta)}$
2 answers
What is the inverse of X modulo $1 + X + X^2 + X^3 + X^4$?
Is there any open softwares to calculate such things easily?
ring-theory inverse irreducible-polynomials
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
asked Dec 4 '18 at 9:23
malleamallea
29919
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marked as duplicate by Saad, GNUSupporter 8964民主女神 地下教會, jgon, Bill Dubuque ring-theory
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Dec 4 '18 at 15:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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-1
$begingroup$
This question already has an answer here:
Let $theta$ be a root of $p(x)=x^3+9x+6$, find the inverse of $1+theta$ in $mathbb{Q(theta)}$
2 answers
What is the inverse of X modulo $1 + X + X^2 + X^3 + X^4$?
Is there any open softwares to calculate such things easily?
ring-theory inverse irreducible-polynomials
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
asked Dec 4 '18 at 9:23
malleamallea
29919
$endgroup$
marked as duplicate by Saad, GNUSupporter 8964民主女神 地下教會, jgon, Bill Dubuque ring-theory
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Dec 4 '18 at 15:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
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Hint $bmod, 1+xf!:, (-f)xequiv 1 $
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– Bill Dubuque
Dec 4 '18 at 14:40
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-1
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-1
$begingroup$
This question already has an answer here:
Let $theta$ be a root of $p(x)=x^3+9x+6$, find the inverse of $1+theta$ in $mathbb{Q(theta)}$
2 answers
What is the inverse of X modulo $1 + X + X^2 + X^3 + X^4$?
Is there any open softwares to calculate such things easily?
ring-theory inverse irreducible-polynomials
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
asked Dec 4 '18 at 9:23
malleamallea
29919
$endgroup$
This question already has an answer here:
Let $theta$ be a root of $p(x)=x^3+9x+6$, find the inverse of $1+theta$ in $mathbb{Q(theta)}$
2 answers
What is the inverse of X modulo $1 + X + X^2 + X^3 + X^4$?
Is there any open softwares to calculate such things easily?
This question already has an answer here:
Let $theta$ be a root of $p(x)=x^3+9x+6$, find the inverse of $1+theta$ in $mathbb{Q(theta)}$
2 answers
ring-theory inverse irreducible-polynomials
ring-theory inverse irreducible-polynomials
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
asked Dec 4 '18 at 9:23
malleamallea
29919
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
asked Dec 4 '18 at 9:23
malleamallea
29919
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
edited Dec 4 '18 at 9:26
José Carlos Santos
157k22126227
157k22126227
asked Dec 4 '18 at 9:23
malleamallea
29919
asked Dec 4 '18 at 9:23
malleamallea
29919
asked Dec 4 '18 at 9:23
malleamallea
29919
29919
marked as duplicate by Saad, GNUSupporter 8964民主女神 地下教會, jgon, Bill Dubuque ring-theory
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Dec 4 '18 at 15:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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Dec 4 '18 at 15:25
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
$begingroup$
Hint $bmod, 1+xf!:, (-f)xequiv 1 $
$endgroup$
– Bill Dubuque
Dec 4 '18 at 14:40
add a comment |
1
$begingroup$
Hint $bmod, 1+xf!:, (-f)xequiv 1 $
$endgroup$
– Bill Dubuque
Dec 4 '18 at 14:40
1
1
$begingroup$
Hint $bmod, 1+xf!:, (-f)xequiv 1 $
$endgroup$
– Bill Dubuque
Dec 4 '18 at 14:40
$begingroup$
Hint $bmod, 1+xf!:, (-f)xequiv 1 $
$endgroup$
– Bill Dubuque
Dec 4 '18 at 14:40
add a comment |
1 Answer
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Hint: $1+X+X^2+X^3+X^4=1+X(1+X+X^2+X^3)$.
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
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Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
$begingroup$
Hint: $1+X+X^2+X^3+X^4=1+X(1+X+X^2+X^3)$.
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
$endgroup$
$begingroup$
Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
add a comment |
1
$begingroup$
Hint: $1+X+X^2+X^3+X^4=1+X(1+X+X^2+X^3)$.
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
$endgroup$
$begingroup$
Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
add a comment |
1
1
1
$begingroup$
Hint: $1+X+X^2+X^3+X^4=1+X(1+X+X^2+X^3)$.
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
$endgroup$
Hint: $1+X+X^2+X^3+X^4=1+X(1+X+X^2+X^3)$.
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
answered Dec 4 '18 at 9:25
José Carlos SantosJosé Carlos Santos
157k22126227
157k22126227
$begingroup$
Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
add a comment |
$begingroup$
Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
$begingroup$
Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
$begingroup$
Got it! Thank you very much :)
$endgroup$
– mallea
Dec 4 '18 at 13:33
add a comment |
1
$begingroup$
Hint $bmod, 1+xf!:, (-f)xequiv 1 $
$endgroup$
– Bill Dubuque
Dec 4 '18 at 14:40