Convert seconds to minutes












1















I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}





bash awk







share|improve this question

























  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago


















1















I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}





bash awk







share|improve this question

























  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago
















1












1








1


0






I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}





bash awk







share|improve this question
















I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}





bash awk




bash awk






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago









αғsнιη

17.1k103069




17.1k103069










asked 7 hours ago









JoeJoe

173




173













  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago





















  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago



















Is this stackoverflow.com/q/13422743/4023950 what you need?

– αғsнιη
6 hours ago





Is this stackoverflow.com/q/13422743/4023950 what you need?

– αғsнιη
6 hours ago













Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

– bu5hman
6 hours ago







Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

– bu5hman
6 hours ago












1 Answer
1






active

oldest

votes


















5














This will help you:



sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }






$ sec2min 500

8:20

$ sec2min 1

0:01





share|improve this answer
























  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

    – RubberStamp
    2 hours ago












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5














This will help you:



sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }






$ sec2min 500

8:20

$ sec2min 1

0:01





share|improve this answer
























  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

    – RubberStamp
    2 hours ago
















5














This will help you:



sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }






$ sec2min 500

8:20

$ sec2min 1

0:01





share|improve this answer
























  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

    – RubberStamp
    2 hours ago














5












5








5







This will help you:



sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }






$ sec2min 500

8:20

$ sec2min 1

0:01





share|improve this answer













This will help you:



sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }






$ sec2min 500

8:20

$ sec2min 1

0:01






share|improve this answer












share|improve this answer



share|improve this answer










answered 6 hours ago









glenn jackmanglenn jackman

53k573114




53k573114













  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

    – RubberStamp
    2 hours ago



















  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

    – RubberStamp
    2 hours ago

















Thanks! That's working perfectly :)

– Joe
4 hours ago





Thanks! That's working perfectly :)

– Joe
4 hours ago













Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

– RubberStamp
2 hours ago





Here's the same operation using a second iteration of awk ... awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'

– RubberStamp
2 hours ago


















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