Find the volume of the solid bounded by the xy plane, the cylinder $x^{2} + y^{2}=4$, and the plane $z+y=4$.












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Find the volume of the solid bounded by the xy plane, the cylinder $x^{2} + y^{2}=4$, and the plane $z+y=4$.





If we draw the graph, then the integral will be calculated should be



$$ int_{0}^{2} int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx $$



This would give the volume of the solid in 1st quadrant which can also be obtained through



$$ int_{0}^{2} int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy $$



which would be equal to $4pi - frac83$. Both the above equations give the same result.



But if we try to find the volume of the entire solid formed by the three curves, then the results from the above equations(after changing the limits appropriately) don't match.
$$ int_{-2}^{2} 2int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx = 2(8pi-frac{16}{3})$$
$$ int_{-2}^{2} 2int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy = 16pi$$



why the results of the these two equations don't match? Is there some problem with the limits I've set or something else? Please help



PS: There is a similar question, but my query is different.










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    0












    $begingroup$


    Find the volume of the solid bounded by the xy plane, the cylinder $x^{2} + y^{2}=4$, and the plane $z+y=4$.





    If we draw the graph, then the integral will be calculated should be



    $$ int_{0}^{2} int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx $$



    This would give the volume of the solid in 1st quadrant which can also be obtained through



    $$ int_{0}^{2} int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy $$



    which would be equal to $4pi - frac83$. Both the above equations give the same result.



    But if we try to find the volume of the entire solid formed by the three curves, then the results from the above equations(after changing the limits appropriately) don't match.
    $$ int_{-2}^{2} 2int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx = 2(8pi-frac{16}{3})$$
    $$ int_{-2}^{2} 2int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy = 16pi$$



    why the results of the these two equations don't match? Is there some problem with the limits I've set or something else? Please help



    PS: There is a similar question, but my query is different.










    share|cite|improve this question











    $endgroup$















      0












      0








      0


      1



      $begingroup$


      Find the volume of the solid bounded by the xy plane, the cylinder $x^{2} + y^{2}=4$, and the plane $z+y=4$.





      If we draw the graph, then the integral will be calculated should be



      $$ int_{0}^{2} int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx $$



      This would give the volume of the solid in 1st quadrant which can also be obtained through



      $$ int_{0}^{2} int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy $$



      which would be equal to $4pi - frac83$. Both the above equations give the same result.



      But if we try to find the volume of the entire solid formed by the three curves, then the results from the above equations(after changing the limits appropriately) don't match.
      $$ int_{-2}^{2} 2int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx = 2(8pi-frac{16}{3})$$
      $$ int_{-2}^{2} 2int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy = 16pi$$



      why the results of the these two equations don't match? Is there some problem with the limits I've set or something else? Please help



      PS: There is a similar question, but my query is different.










      share|cite|improve this question











      $endgroup$




      Find the volume of the solid bounded by the xy plane, the cylinder $x^{2} + y^{2}=4$, and the plane $z+y=4$.





      If we draw the graph, then the integral will be calculated should be



      $$ int_{0}^{2} int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx $$



      This would give the volume of the solid in 1st quadrant which can also be obtained through



      $$ int_{0}^{2} int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy $$



      which would be equal to $4pi - frac83$. Both the above equations give the same result.



      But if we try to find the volume of the entire solid formed by the three curves, then the results from the above equations(after changing the limits appropriately) don't match.
      $$ int_{-2}^{2} 2int_{0}^{sqrt{4-x^{2}}} (4-y) : dy dx = 2(8pi-frac{16}{3})$$
      $$ int_{-2}^{2} 2int_{0}^{sqrt{4-y^{2}}} (4-y) : dx dy = 16pi$$



      why the results of the these two equations don't match? Is there some problem with the limits I've set or something else? Please help



      PS: There is a similar question, but my query is different.







      multiple-integral






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      edited Dec 23 '18 at 18:14







      Ajay Choudhary

















      asked Dec 23 '18 at 18:00









      Ajay ChoudharyAjay Choudhary

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          $begingroup$

          The limits of the second integral are wrong. It should be $$2int_0^2int_{-sqrt{4-y^{2}}}^{sqrt{4-y^{2}}} (4-y) : dx dy=4int_0^2int_0^{sqrt{4-y^{2}}} (4-y) : dx dy$$
          The answers match.






          share|cite|improve this answer











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            $begingroup$

            The limits of the second integral are wrong. It should be $$2int_0^2int_{-sqrt{4-y^{2}}}^{sqrt{4-y^{2}}} (4-y) : dx dy=4int_0^2int_0^{sqrt{4-y^{2}}} (4-y) : dx dy$$
            The answers match.






            share|cite|improve this answer











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              $begingroup$

              The limits of the second integral are wrong. It should be $$2int_0^2int_{-sqrt{4-y^{2}}}^{sqrt{4-y^{2}}} (4-y) : dx dy=4int_0^2int_0^{sqrt{4-y^{2}}} (4-y) : dx dy$$
              The answers match.






              share|cite|improve this answer











              $endgroup$
















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                $begingroup$

                The limits of the second integral are wrong. It should be $$2int_0^2int_{-sqrt{4-y^{2}}}^{sqrt{4-y^{2}}} (4-y) : dx dy=4int_0^2int_0^{sqrt{4-y^{2}}} (4-y) : dx dy$$
                The answers match.






                share|cite|improve this answer











                $endgroup$



                The limits of the second integral are wrong. It should be $$2int_0^2int_{-sqrt{4-y^{2}}}^{sqrt{4-y^{2}}} (4-y) : dx dy=4int_0^2int_0^{sqrt{4-y^{2}}} (4-y) : dx dy$$
                The answers match.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Dec 23 '18 at 18:19

























                answered Dec 23 '18 at 18:06









                Shubham JohriShubham Johri

                5,475818




                5,475818






























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