Solve for a value (Trig question)












0












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The question is phrased as, in the triangle $xyz$, $cos(x)=sin(z)$. If $x=3j-19$ and $z=5j-15$, what is the value of $j$?



Firstly, I'm not quite sure if the variables refer to the side length or the angle measurements.



I'm sure there's an identity that will solve this question in 1 step but I'm not sure which one it would be. I want to use sine law but that seems to only give me $$frac{sin(x)}{3j-19}=frac{cos(x)}{5j-15}$$



which doesn't seem helpful?










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  • $begingroup$
    Are $x$ and $z$ in degree or radian?
    $endgroup$
    – Mythomorphic
    Dec 24 '18 at 8:33
















0












$begingroup$


The question is phrased as, in the triangle $xyz$, $cos(x)=sin(z)$. If $x=3j-19$ and $z=5j-15$, what is the value of $j$?



Firstly, I'm not quite sure if the variables refer to the side length or the angle measurements.



I'm sure there's an identity that will solve this question in 1 step but I'm not sure which one it would be. I want to use sine law but that seems to only give me $$frac{sin(x)}{3j-19}=frac{cos(x)}{5j-15}$$



which doesn't seem helpful?










share|cite|improve this question











$endgroup$












  • $begingroup$
    Are $x$ and $z$ in degree or radian?
    $endgroup$
    – Mythomorphic
    Dec 24 '18 at 8:33














0












0








0





$begingroup$


The question is phrased as, in the triangle $xyz$, $cos(x)=sin(z)$. If $x=3j-19$ and $z=5j-15$, what is the value of $j$?



Firstly, I'm not quite sure if the variables refer to the side length or the angle measurements.



I'm sure there's an identity that will solve this question in 1 step but I'm not sure which one it would be. I want to use sine law but that seems to only give me $$frac{sin(x)}{3j-19}=frac{cos(x)}{5j-15}$$



which doesn't seem helpful?










share|cite|improve this question











$endgroup$




The question is phrased as, in the triangle $xyz$, $cos(x)=sin(z)$. If $x=3j-19$ and $z=5j-15$, what is the value of $j$?



Firstly, I'm not quite sure if the variables refer to the side length or the angle measurements.



I'm sure there's an identity that will solve this question in 1 step but I'm not sure which one it would be. I want to use sine law but that seems to only give me $$frac{sin(x)}{3j-19}=frac{cos(x)}{5j-15}$$



which doesn't seem helpful?







trigonometry






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share|cite|improve this question













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edited Dec 24 '18 at 8:31









Mythomorphic

5,3491834




5,3491834










asked Dec 24 '18 at 8:23









SatSat

405




405












  • $begingroup$
    Are $x$ and $z$ in degree or radian?
    $endgroup$
    – Mythomorphic
    Dec 24 '18 at 8:33


















  • $begingroup$
    Are $x$ and $z$ in degree or radian?
    $endgroup$
    – Mythomorphic
    Dec 24 '18 at 8:33
















$begingroup$
Are $x$ and $z$ in degree or radian?
$endgroup$
– Mythomorphic
Dec 24 '18 at 8:33




$begingroup$
Are $x$ and $z$ in degree or radian?
$endgroup$
– Mythomorphic
Dec 24 '18 at 8:33










2 Answers
2






active

oldest

votes


















3












$begingroup$

Usually, angles and sides are distinguishable by capital and lowercase letters. Here, $x$ and $y$ refer to angle measures.



Recalling $cos theta = sin (90-theta)$ in the first quadrant, you can conclude $cos x = sin z$ if $x+z = 90$, resulting in




$$3j-19+(5j-15) = 90 iff 8j-34 = 90 iff 8j = 124 iff j = 15.5$$







share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yes, that's it. I knew there was some identity that I was missing.
    $endgroup$
    – Sat
    Dec 24 '18 at 8:43



















1












$begingroup$

Hint:



Use the identity



$$cos(90^circ-A)=sin A$$






share|cite|improve this answer









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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3












    $begingroup$

    Usually, angles and sides are distinguishable by capital and lowercase letters. Here, $x$ and $y$ refer to angle measures.



    Recalling $cos theta = sin (90-theta)$ in the first quadrant, you can conclude $cos x = sin z$ if $x+z = 90$, resulting in




    $$3j-19+(5j-15) = 90 iff 8j-34 = 90 iff 8j = 124 iff j = 15.5$$







    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Yes, that's it. I knew there was some identity that I was missing.
      $endgroup$
      – Sat
      Dec 24 '18 at 8:43
















    3












    $begingroup$

    Usually, angles and sides are distinguishable by capital and lowercase letters. Here, $x$ and $y$ refer to angle measures.



    Recalling $cos theta = sin (90-theta)$ in the first quadrant, you can conclude $cos x = sin z$ if $x+z = 90$, resulting in




    $$3j-19+(5j-15) = 90 iff 8j-34 = 90 iff 8j = 124 iff j = 15.5$$







    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Yes, that's it. I knew there was some identity that I was missing.
      $endgroup$
      – Sat
      Dec 24 '18 at 8:43














    3












    3








    3





    $begingroup$

    Usually, angles and sides are distinguishable by capital and lowercase letters. Here, $x$ and $y$ refer to angle measures.



    Recalling $cos theta = sin (90-theta)$ in the first quadrant, you can conclude $cos x = sin z$ if $x+z = 90$, resulting in




    $$3j-19+(5j-15) = 90 iff 8j-34 = 90 iff 8j = 124 iff j = 15.5$$







    share|cite|improve this answer









    $endgroup$



    Usually, angles and sides are distinguishable by capital and lowercase letters. Here, $x$ and $y$ refer to angle measures.



    Recalling $cos theta = sin (90-theta)$ in the first quadrant, you can conclude $cos x = sin z$ if $x+z = 90$, resulting in




    $$3j-19+(5j-15) = 90 iff 8j-34 = 90 iff 8j = 124 iff j = 15.5$$








    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Dec 24 '18 at 8:38









    KM101KM101

    6,0901525




    6,0901525












    • $begingroup$
      Yes, that's it. I knew there was some identity that I was missing.
      $endgroup$
      – Sat
      Dec 24 '18 at 8:43


















    • $begingroup$
      Yes, that's it. I knew there was some identity that I was missing.
      $endgroup$
      – Sat
      Dec 24 '18 at 8:43
















    $begingroup$
    Yes, that's it. I knew there was some identity that I was missing.
    $endgroup$
    – Sat
    Dec 24 '18 at 8:43




    $begingroup$
    Yes, that's it. I knew there was some identity that I was missing.
    $endgroup$
    – Sat
    Dec 24 '18 at 8:43











    1












    $begingroup$

    Hint:



    Use the identity



    $$cos(90^circ-A)=sin A$$






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Hint:



      Use the identity



      $$cos(90^circ-A)=sin A$$






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Hint:



        Use the identity



        $$cos(90^circ-A)=sin A$$






        share|cite|improve this answer









        $endgroup$



        Hint:



        Use the identity



        $$cos(90^circ-A)=sin A$$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 24 '18 at 8:36









        MythomorphicMythomorphic

        5,3491834




        5,3491834






























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