Show that the integral $int(xu - 3tu^2) dx$ is invariant for the $KdV$ equation.











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I have a problem solving the problem about showing the integral is invariant for the KdV equation.
The problem is as following:



Show that integral of $int(xu - 3tu^2) dx$ is invariant for the $KdV$ equation.



Can anyone help? I'm kind of stuck here...










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    Try defining $F(t)=int(xu - 3tu^2) dx$ and try to show that $F'(t)=0$. (You will need to insert the KdV and do some integration by parts.)
    – maxmilgram
    yesterday















up vote
1
down vote

favorite
1












I have a problem solving the problem about showing the integral is invariant for the KdV equation.
The problem is as following:



Show that integral of $int(xu - 3tu^2) dx$ is invariant for the $KdV$ equation.



Can anyone help? I'm kind of stuck here...










share|cite|improve this question









New contributor




Tommy Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    Welcome to MSE. Please read this text about how to ask a good question.
    – José Carlos Santos
    yesterday






  • 1




    Try defining $F(t)=int(xu - 3tu^2) dx$ and try to show that $F'(t)=0$. (You will need to insert the KdV and do some integration by parts.)
    – maxmilgram
    yesterday













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





I have a problem solving the problem about showing the integral is invariant for the KdV equation.
The problem is as following:



Show that integral of $int(xu - 3tu^2) dx$ is invariant for the $KdV$ equation.



Can anyone help? I'm kind of stuck here...










share|cite|improve this question









New contributor




Tommy Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I have a problem solving the problem about showing the integral is invariant for the KdV equation.
The problem is as following:



Show that integral of $int(xu - 3tu^2) dx$ is invariant for the $KdV$ equation.



Can anyone help? I'm kind of stuck here...







pde






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Tommy Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|cite|improve this question









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Tommy Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited yesterday









dmtri

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1,2181520






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asked yesterday









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Tommy Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Tommy Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    Welcome to MSE. Please read this text about how to ask a good question.
    – José Carlos Santos
    yesterday






  • 1




    Try defining $F(t)=int(xu - 3tu^2) dx$ and try to show that $F'(t)=0$. (You will need to insert the KdV and do some integration by parts.)
    – maxmilgram
    yesterday














  • 1




    Welcome to MSE. Please read this text about how to ask a good question.
    – José Carlos Santos
    yesterday






  • 1




    Try defining $F(t)=int(xu - 3tu^2) dx$ and try to show that $F'(t)=0$. (You will need to insert the KdV and do some integration by parts.)
    – maxmilgram
    yesterday








1




1




Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
yesterday




Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
yesterday




1




1




Try defining $F(t)=int(xu - 3tu^2) dx$ and try to show that $F'(t)=0$. (You will need to insert the KdV and do some integration by parts.)
– maxmilgram
yesterday




Try defining $F(t)=int(xu - 3tu^2) dx$ and try to show that $F'(t)=0$. (You will need to insert the KdV and do some integration by parts.)
– maxmilgram
yesterday















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