$|x-y|_{L^2}^2geq |x|_{L^2}^2-|y|_{L^2}^2$?











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Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}










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  • 1




    Is $(x-y)^2ge x^2-y^2$?
    – Lord Shark the Unknown
    yesterday






  • 1




    You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
    – Kavi Rama Murthy
    yesterday










  • @maxmilgram I think you didn't read the question correctly.
    – Kavi Rama Murthy
    yesterday










  • Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
    – CuriousCat
    yesterday










  • @kavi rama murthy you are absolutely right!
    – maxmilgram
    yesterday















up vote
-1
down vote

favorite












Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}










share|cite|improve this question


















  • 1




    Is $(x-y)^2ge x^2-y^2$?
    – Lord Shark the Unknown
    yesterday






  • 1




    You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
    – Kavi Rama Murthy
    yesterday










  • @maxmilgram I think you didn't read the question correctly.
    – Kavi Rama Murthy
    yesterday










  • Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
    – CuriousCat
    yesterday










  • @kavi rama murthy you are absolutely right!
    – maxmilgram
    yesterday













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}










share|cite|improve this question













Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}







inequality norm






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked yesterday









CuriousCat

342




342








  • 1




    Is $(x-y)^2ge x^2-y^2$?
    – Lord Shark the Unknown
    yesterday






  • 1




    You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
    – Kavi Rama Murthy
    yesterday










  • @maxmilgram I think you didn't read the question correctly.
    – Kavi Rama Murthy
    yesterday










  • Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
    – CuriousCat
    yesterday










  • @kavi rama murthy you are absolutely right!
    – maxmilgram
    yesterday














  • 1




    Is $(x-y)^2ge x^2-y^2$?
    – Lord Shark the Unknown
    yesterday






  • 1




    You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
    – Kavi Rama Murthy
    yesterday










  • @maxmilgram I think you didn't read the question correctly.
    – Kavi Rama Murthy
    yesterday










  • Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
    – CuriousCat
    yesterday










  • @kavi rama murthy you are absolutely right!
    – maxmilgram
    yesterday








1




1




Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday




Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday




1




1




You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday




You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday












@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday




@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday












Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday




Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday












@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday




@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday















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