$|x-y|_{L^2}^2geq |x|_{L^2}^2-|y|_{L^2}^2$?
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Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}
inequality norm
|
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up vote
-1
down vote
favorite
Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}
inequality norm
1
Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday
1
You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday
@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday
Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday
@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday
|
show 3 more comments
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}
inequality norm
Is this true?
begin{equation}
|x-y|_{L^2(Omega)}^2geq |x|_{L^2(Omega)}^2-|y|_{L^2(Omega)}^2
end{equation}
inequality norm
inequality norm
asked yesterday
CuriousCat
342
342
1
Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday
1
You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday
@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday
Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday
@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday
|
show 3 more comments
1
Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday
1
You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday
@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday
Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday
@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday
1
1
Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday
Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday
1
1
You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday
You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday
@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday
@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday
Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday
Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday
@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday
@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday
|
show 3 more comments
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1
Is $(x-y)^2ge x^2-y^2$?
– Lord Shark the Unknown
yesterday
1
You have already been told in your previous post that the inequality does not hold even for real numbers. Why are you posting this question now?.
– Kavi Rama Murthy
yesterday
@maxmilgram I think you didn't read the question correctly.
– Kavi Rama Murthy
yesterday
Thank you I got it now. $(3-4)^2>0$ but $3^2-4^2<0$.
– CuriousCat
yesterday
@kavi rama murthy you are absolutely right!
– maxmilgram
yesterday