Measure on Lie Algebra “induced” by Haar measure on U(n)











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On the unitary group $U(n)$, the Haar measure provides a suitable notion of uniformity for many applications. The Lie Group $U(n)$ is generated by the Hermitian matrices, i.e., I can write any $A in U(n)$ as $$A = exp(sum_{j,k=1}^n i a_{jk}Omega_{jk})$$
where $a_{jk}$ are real coefficients dependent on A and $Omega_{jk}$ are the standard basis elements of the Lie Algebra $mathfrak{u}(n) = {X in mathbb{C}^{n times n } | X^dagger = X}$.



My question is this: What is the measure "induced" on the Lie Algebra by the Haar measure on $U(n)$? Put another way: What measure on $mathbb{R}^{n times n}$ do I have to use to sample the $a_{jk}$ if I want the corresponding unitary matrices to be distributed according to the Haar measure?










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  • I do not quite understand what you want, more precisely what the expressions "sample the $a_{jk}$" and "distributed according to the Haar measure" mean exactly. Anyway, it seems that the discussion in the comments to this question is related: math.stackexchange.com/q/1383157/96384
    – Torsten Schoeneberg
    Nov 25 at 6:57






  • 1




    Thanks for your comments. I know how to sample random unitaries that are uniformly distributed w.r.t. the Haar measure (arxiv.org/abs/math-ph/0609050, and implemented in docs.scipy.org/doc/scipy/reference/generated/…). What I would like to do is sample $a_{jk}$ instead of the unitary itself (it's for a numerical application). However, I need to sample $a_{jk}$ in such a way that when I calculate the corresponding unitaries, they are distributed in the same way as if I had sampled them directly as described above. Hope this makes sense...
    – tomet
    Nov 25 at 7:16















up vote
1
down vote

favorite












On the unitary group $U(n)$, the Haar measure provides a suitable notion of uniformity for many applications. The Lie Group $U(n)$ is generated by the Hermitian matrices, i.e., I can write any $A in U(n)$ as $$A = exp(sum_{j,k=1}^n i a_{jk}Omega_{jk})$$
where $a_{jk}$ are real coefficients dependent on A and $Omega_{jk}$ are the standard basis elements of the Lie Algebra $mathfrak{u}(n) = {X in mathbb{C}^{n times n } | X^dagger = X}$.



My question is this: What is the measure "induced" on the Lie Algebra by the Haar measure on $U(n)$? Put another way: What measure on $mathbb{R}^{n times n}$ do I have to use to sample the $a_{jk}$ if I want the corresponding unitary matrices to be distributed according to the Haar measure?










share|cite|improve this question






















  • I do not quite understand what you want, more precisely what the expressions "sample the $a_{jk}$" and "distributed according to the Haar measure" mean exactly. Anyway, it seems that the discussion in the comments to this question is related: math.stackexchange.com/q/1383157/96384
    – Torsten Schoeneberg
    Nov 25 at 6:57






  • 1




    Thanks for your comments. I know how to sample random unitaries that are uniformly distributed w.r.t. the Haar measure (arxiv.org/abs/math-ph/0609050, and implemented in docs.scipy.org/doc/scipy/reference/generated/…). What I would like to do is sample $a_{jk}$ instead of the unitary itself (it's for a numerical application). However, I need to sample $a_{jk}$ in such a way that when I calculate the corresponding unitaries, they are distributed in the same way as if I had sampled them directly as described above. Hope this makes sense...
    – tomet
    Nov 25 at 7:16













up vote
1
down vote

favorite









up vote
1
down vote

favorite











On the unitary group $U(n)$, the Haar measure provides a suitable notion of uniformity for many applications. The Lie Group $U(n)$ is generated by the Hermitian matrices, i.e., I can write any $A in U(n)$ as $$A = exp(sum_{j,k=1}^n i a_{jk}Omega_{jk})$$
where $a_{jk}$ are real coefficients dependent on A and $Omega_{jk}$ are the standard basis elements of the Lie Algebra $mathfrak{u}(n) = {X in mathbb{C}^{n times n } | X^dagger = X}$.



My question is this: What is the measure "induced" on the Lie Algebra by the Haar measure on $U(n)$? Put another way: What measure on $mathbb{R}^{n times n}$ do I have to use to sample the $a_{jk}$ if I want the corresponding unitary matrices to be distributed according to the Haar measure?










share|cite|improve this question













On the unitary group $U(n)$, the Haar measure provides a suitable notion of uniformity for many applications. The Lie Group $U(n)$ is generated by the Hermitian matrices, i.e., I can write any $A in U(n)$ as $$A = exp(sum_{j,k=1}^n i a_{jk}Omega_{jk})$$
where $a_{jk}$ are real coefficients dependent on A and $Omega_{jk}$ are the standard basis elements of the Lie Algebra $mathfrak{u}(n) = {X in mathbb{C}^{n times n } | X^dagger = X}$.



My question is this: What is the measure "induced" on the Lie Algebra by the Haar measure on $U(n)$? Put another way: What measure on $mathbb{R}^{n times n}$ do I have to use to sample the $a_{jk}$ if I want the corresponding unitary matrices to be distributed according to the Haar measure?







measure-theory lie-groups lie-algebras haar-measure






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asked Nov 24 at 10:15









tomet

1495




1495












  • I do not quite understand what you want, more precisely what the expressions "sample the $a_{jk}$" and "distributed according to the Haar measure" mean exactly. Anyway, it seems that the discussion in the comments to this question is related: math.stackexchange.com/q/1383157/96384
    – Torsten Schoeneberg
    Nov 25 at 6:57






  • 1




    Thanks for your comments. I know how to sample random unitaries that are uniformly distributed w.r.t. the Haar measure (arxiv.org/abs/math-ph/0609050, and implemented in docs.scipy.org/doc/scipy/reference/generated/…). What I would like to do is sample $a_{jk}$ instead of the unitary itself (it's for a numerical application). However, I need to sample $a_{jk}$ in such a way that when I calculate the corresponding unitaries, they are distributed in the same way as if I had sampled them directly as described above. Hope this makes sense...
    – tomet
    Nov 25 at 7:16


















  • I do not quite understand what you want, more precisely what the expressions "sample the $a_{jk}$" and "distributed according to the Haar measure" mean exactly. Anyway, it seems that the discussion in the comments to this question is related: math.stackexchange.com/q/1383157/96384
    – Torsten Schoeneberg
    Nov 25 at 6:57






  • 1




    Thanks for your comments. I know how to sample random unitaries that are uniformly distributed w.r.t. the Haar measure (arxiv.org/abs/math-ph/0609050, and implemented in docs.scipy.org/doc/scipy/reference/generated/…). What I would like to do is sample $a_{jk}$ instead of the unitary itself (it's for a numerical application). However, I need to sample $a_{jk}$ in such a way that when I calculate the corresponding unitaries, they are distributed in the same way as if I had sampled them directly as described above. Hope this makes sense...
    – tomet
    Nov 25 at 7:16
















I do not quite understand what you want, more precisely what the expressions "sample the $a_{jk}$" and "distributed according to the Haar measure" mean exactly. Anyway, it seems that the discussion in the comments to this question is related: math.stackexchange.com/q/1383157/96384
– Torsten Schoeneberg
Nov 25 at 6:57




I do not quite understand what you want, more precisely what the expressions "sample the $a_{jk}$" and "distributed according to the Haar measure" mean exactly. Anyway, it seems that the discussion in the comments to this question is related: math.stackexchange.com/q/1383157/96384
– Torsten Schoeneberg
Nov 25 at 6:57




1




1




Thanks for your comments. I know how to sample random unitaries that are uniformly distributed w.r.t. the Haar measure (arxiv.org/abs/math-ph/0609050, and implemented in docs.scipy.org/doc/scipy/reference/generated/…). What I would like to do is sample $a_{jk}$ instead of the unitary itself (it's for a numerical application). However, I need to sample $a_{jk}$ in such a way that when I calculate the corresponding unitaries, they are distributed in the same way as if I had sampled them directly as described above. Hope this makes sense...
– tomet
Nov 25 at 7:16




Thanks for your comments. I know how to sample random unitaries that are uniformly distributed w.r.t. the Haar measure (arxiv.org/abs/math-ph/0609050, and implemented in docs.scipy.org/doc/scipy/reference/generated/…). What I would like to do is sample $a_{jk}$ instead of the unitary itself (it's for a numerical application). However, I need to sample $a_{jk}$ in such a way that when I calculate the corresponding unitaries, they are distributed in the same way as if I had sampled them directly as described above. Hope this makes sense...
– tomet
Nov 25 at 7:16















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