Combinatorics problem based on Ferrers graph












1












$begingroup$


Need help with this proof using Ferrers' graph or otherwise.



Show that the number of partitions of $r+k$ into $k$ parts is equal to




  1. The number of partitions of $r + {k+1 choose 2}$ into $ k $ distinct parts

  2. The number of partitions of $r$ into parts of size at most $k$










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$endgroup$

















    1












    $begingroup$


    Need help with this proof using Ferrers' graph or otherwise.



    Show that the number of partitions of $r+k$ into $k$ parts is equal to




    1. The number of partitions of $r + {k+1 choose 2}$ into $ k $ distinct parts

    2. The number of partitions of $r$ into parts of size at most $k$










    share|cite|improve this question











    $endgroup$















      1












      1








      1


      1



      $begingroup$


      Need help with this proof using Ferrers' graph or otherwise.



      Show that the number of partitions of $r+k$ into $k$ parts is equal to




      1. The number of partitions of $r + {k+1 choose 2}$ into $ k $ distinct parts

      2. The number of partitions of $r$ into parts of size at most $k$










      share|cite|improve this question











      $endgroup$




      Need help with this proof using Ferrers' graph or otherwise.



      Show that the number of partitions of $r+k$ into $k$ parts is equal to




      1. The number of partitions of $r + {k+1 choose 2}$ into $ k $ distinct parts

      2. The number of partitions of $r$ into parts of size at most $k$







      combinatorics integer-partitions






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      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Oct 12 '12 at 21:14









      MJD

      47.4k29214396




      47.4k29214396










      asked Oct 12 '12 at 20:24









      NeelNeel

      61




      61






















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          $begingroup$

          (i) Take the diagram of an arbitrary partition of $r+k$ into $k$ parts, then add $0$ to the smallest part, add $1$ to the second smallest part, add $2$ to the third, $ldots$ add $(k-1)$ to the largest part and what have you got?



          (ii) Take the diagram of an arbitrary partition of of $r+k$ into $k$ parts, then subtract $1$ from each part and what have you got? Now reflect it so rows become columns and columns become rows and what have you got?






          share|cite|improve this answer









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          • $begingroup$
            Very nice hint.
            $endgroup$
            – Brian M. Scott
            Oct 13 '12 at 4:11











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          $begingroup$

          (i) Take the diagram of an arbitrary partition of $r+k$ into $k$ parts, then add $0$ to the smallest part, add $1$ to the second smallest part, add $2$ to the third, $ldots$ add $(k-1)$ to the largest part and what have you got?



          (ii) Take the diagram of an arbitrary partition of of $r+k$ into $k$ parts, then subtract $1$ from each part and what have you got? Now reflect it so rows become columns and columns become rows and what have you got?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Very nice hint.
            $endgroup$
            – Brian M. Scott
            Oct 13 '12 at 4:11
















          1












          $begingroup$

          (i) Take the diagram of an arbitrary partition of $r+k$ into $k$ parts, then add $0$ to the smallest part, add $1$ to the second smallest part, add $2$ to the third, $ldots$ add $(k-1)$ to the largest part and what have you got?



          (ii) Take the diagram of an arbitrary partition of of $r+k$ into $k$ parts, then subtract $1$ from each part and what have you got? Now reflect it so rows become columns and columns become rows and what have you got?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Very nice hint.
            $endgroup$
            – Brian M. Scott
            Oct 13 '12 at 4:11














          1












          1








          1





          $begingroup$

          (i) Take the diagram of an arbitrary partition of $r+k$ into $k$ parts, then add $0$ to the smallest part, add $1$ to the second smallest part, add $2$ to the third, $ldots$ add $(k-1)$ to the largest part and what have you got?



          (ii) Take the diagram of an arbitrary partition of of $r+k$ into $k$ parts, then subtract $1$ from each part and what have you got? Now reflect it so rows become columns and columns become rows and what have you got?






          share|cite|improve this answer









          $endgroup$



          (i) Take the diagram of an arbitrary partition of $r+k$ into $k$ parts, then add $0$ to the smallest part, add $1$ to the second smallest part, add $2$ to the third, $ldots$ add $(k-1)$ to the largest part and what have you got?



          (ii) Take the diagram of an arbitrary partition of of $r+k$ into $k$ parts, then subtract $1$ from each part and what have you got? Now reflect it so rows become columns and columns become rows and what have you got?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Oct 12 '12 at 20:46









          HenryHenry

          100k481167




          100k481167












          • $begingroup$
            Very nice hint.
            $endgroup$
            – Brian M. Scott
            Oct 13 '12 at 4:11


















          • $begingroup$
            Very nice hint.
            $endgroup$
            – Brian M. Scott
            Oct 13 '12 at 4:11
















          $begingroup$
          Very nice hint.
          $endgroup$
          – Brian M. Scott
          Oct 13 '12 at 4:11




          $begingroup$
          Very nice hint.
          $endgroup$
          – Brian M. Scott
          Oct 13 '12 at 4:11


















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