Modulo Arithmetic equations
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How to find the value of the unknown in the equations . I have tried finding the value y by equating the left hand side to the right hand side
$;20pmod 9 = ypmod6$, find the value of $y$
modular-arithmetic
edited Dec 8 '18 at 21:45
Bernard
121k740116
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
$endgroup$
add a comment |
$begingroup$
How to find the value of the unknown in the equations . I have tried finding the value y by equating the left hand side to the right hand side
$;20pmod 9 = ypmod6$, find the value of $y$
modular-arithmetic
edited Dec 8 '18 at 21:45
Bernard
121k740116
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
$endgroup$
$begingroup$
The equation makes no sense as written. Maybe you mean $,20bmod 9,=, ybmod 6$ ? Please clarify. Where does the equation come from?
$endgroup$
– Bill Dubuque
Dec 8 '18 at 22:33
add a comment |
$begingroup$
How to find the value of the unknown in the equations . I have tried finding the value y by equating the left hand side to the right hand side
$;20pmod 9 = ypmod6$, find the value of $y$
modular-arithmetic
edited Dec 8 '18 at 21:45
Bernard
121k740116
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
$endgroup$
How to find the value of the unknown in the equations . I have tried finding the value y by equating the left hand side to the right hand side
$;20pmod 9 = ypmod6$, find the value of $y$
modular-arithmetic
modular-arithmetic
edited Dec 8 '18 at 21:45
Bernard
121k740116
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
edited Dec 8 '18 at 21:45
Bernard
121k740116
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
edited Dec 8 '18 at 21:45
Bernard
121k740116
edited Dec 8 '18 at 21:45
Bernard
121k740116
edited Dec 8 '18 at 21:45
Bernard
121k740116
121k740116
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
asked Dec 8 '18 at 21:42
MickeyGeeMickeyGee
1
1
$begingroup$
The equation makes no sense as written. Maybe you mean $,20bmod 9,=, ybmod 6$ ? Please clarify. Where does the equation come from?
$endgroup$
– Bill Dubuque
Dec 8 '18 at 22:33
add a comment |
$begingroup$
The equation makes no sense as written. Maybe you mean $,20bmod 9,=, ybmod 6$ ? Please clarify. Where does the equation come from?
$endgroup$
– Bill Dubuque
Dec 8 '18 at 22:33
$begingroup$
The equation makes no sense as written. Maybe you mean $,20bmod 9,=, ybmod 6$ ? Please clarify. Where does the equation come from?
$endgroup$
– Bill Dubuque
Dec 8 '18 at 22:33
$begingroup$
The equation makes no sense as written. Maybe you mean $,20bmod 9,=, ybmod 6$ ? Please clarify. Where does the equation come from?
$endgroup$
– Bill Dubuque
Dec 8 '18 at 22:33
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Hint:
First of all, reduce the equation: as $20equiv 2mod 9$, the equation is
$$ˆymod 6= 2mod 9$$
Next, translate what it means in a concrete way: there exist $k,ellin mathbf Z$ such that
$$y+6k=2+9elliff y=2+9ell-6k.$$
Last: think of Bézout's identity.
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
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add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
votes
$begingroup$
Hint:
First of all, reduce the equation: as $20equiv 2mod 9$, the equation is
$$ˆymod 6= 2mod 9$$
Next, translate what it means in a concrete way: there exist $k,ellin mathbf Z$ such that
$$y+6k=2+9elliff y=2+9ell-6k.$$
Last: think of Bézout's identity.
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
$endgroup$
add a comment |
$begingroup$
Hint:
First of all, reduce the equation: as $20equiv 2mod 9$, the equation is
$$ˆymod 6= 2mod 9$$
Next, translate what it means in a concrete way: there exist $k,ellin mathbf Z$ such that
$$y+6k=2+9elliff y=2+9ell-6k.$$
Last: think of Bézout's identity.
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
$endgroup$
add a comment |
$begingroup$
Hint:
First of all, reduce the equation: as $20equiv 2mod 9$, the equation is
$$ˆymod 6= 2mod 9$$
Next, translate what it means in a concrete way: there exist $k,ellin mathbf Z$ such that
$$y+6k=2+9elliff y=2+9ell-6k.$$
Last: think of Bézout's identity.
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
$endgroup$
Hint:
First of all, reduce the equation: as $20equiv 2mod 9$, the equation is
$$ˆymod 6= 2mod 9$$
Next, translate what it means in a concrete way: there exist $k,ellin mathbf Z$ such that
$$y+6k=2+9elliff y=2+9ell-6k.$$
Last: think of Bézout's identity.
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
answered Dec 8 '18 at 21:53
BernardBernard
121k740116
121k740116
add a comment |
add a comment |
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$begingroup$
The equation makes no sense as written. Maybe you mean $,20bmod 9,=, ybmod 6$ ? Please clarify. Where does the equation come from?
$endgroup$
– Bill Dubuque
Dec 8 '18 at 22:33