Simple Maths Riddle 5












13












$begingroup$


Here's a special one for you!




I am prime, I am composite



Sum my digits and half; I'll be perfect!



Don't multiply them, I won't yield a thing



But don't worry, it's only the beginning!




What am I?










share|improve this question









$endgroup$

















    13












    $begingroup$


    Here's a special one for you!




    I am prime, I am composite



    Sum my digits and half; I'll be perfect!



    Don't multiply them, I won't yield a thing



    But don't worry, it's only the beginning!




    What am I?










    share|improve this question









    $endgroup$















      13












      13








      13


      1



      $begingroup$


      Here's a special one for you!




      I am prime, I am composite



      Sum my digits and half; I'll be perfect!



      Don't multiply them, I won't yield a thing



      But don't worry, it's only the beginning!




      What am I?










      share|improve this question









      $endgroup$




      Here's a special one for you!




      I am prime, I am composite



      Sum my digits and half; I'll be perfect!



      Don't multiply them, I won't yield a thing



      But don't worry, it's only the beginning!




      What am I?







      riddle mathematics rhyme






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Dec 31 '18 at 14:13









      TheSimpliFireTheSimpliFire

      2,210532




      2,210532






















          3 Answers
          3






          active

          oldest

          votes


















          14












          $begingroup$

          Hoping this is good




          $2019$




          I am prime, I am composite




          Prime as in beginning and composite as $2019 = 3cdot673$




          Sum my digits and half; I'll be perfect!




          $2 + 0 + 1 + 9 = 12$, then $12/2 = 6$




          Don't multiply them, I won't yield a thing




          $2 cdot 0 cdot 1 cdot 9 = 0$




          But don't worry, it's only the beginning!




          Happening around the world today!







          share|improve this answer









          $endgroup$









          • 1




            $begingroup$
            This must be the answer!
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:59










          • $begingroup$
            Yes, you got it! Prime can also mean importance, and it is so for a new year :)
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 15:00






          • 2




            $begingroup$
            Would the wording "Sum my digits and halve" be better?
            $endgroup$
            – greenturtle3141
            Jan 1 at 22:23



















          2












          $begingroup$

          I'm thinking it might be




          $39$

          $(3+9)/2=6$, a perfect number as its factors sum to the number itself: $1+2+3=6$

          $3$ is prime and $9$ is composite


          Multiplying them won't yield just a thing, it yields $3times 9=27$ things


          I am a bit hung up on this but perhaps $39$ is the beginning of a sequence where these rules hold true (i.e., it's the smallest number produced by these rules). Or perhaps it's the first two of this series: $3^1, 3^2, 3^3, cdots$







          share|improve this answer











          $endgroup$









          • 2




            $begingroup$
            (3+8)/2 is not 6, but 5.5
            $endgroup$
            – SPK.z
            Dec 31 '18 at 14:46










          • $begingroup$
            Nope, unfortunately, but good attempt!
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:47






          • 1




            $begingroup$
            @SPK.z I can't believe I made that mistake. I'll edit.
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:48





















          2












          $begingroup$

          Partial:



          Are you




          1?




          I am prime, I am composite




          Some say 1 is prime, some say it is composite




          Sum my digits and half; I'll be perfect!




          ? Perfect number? Perhaps not




          Don't multiply them, I won't yield a thing




          any n*1 yield n




          But don't worry, it's only the beginning!




          beginning of natural numbers







          share|improve this answer











          $endgroup$













          • $begingroup$
            Nope (1 isn't conventionally a perfect number) ;P
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:48






          • 2




            $begingroup$
            Technically 1 is neither prime nor composite.
            $endgroup$
            – tilper
            Dec 31 '18 at 15:44






          • 1




            $begingroup$
            To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
            $endgroup$
            – Eevee Trainer
            Jan 1 at 10:56














          Your Answer








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          3 Answers
          3






          active

          oldest

          votes








          3 Answers
          3






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          14












          $begingroup$

          Hoping this is good




          $2019$




          I am prime, I am composite




          Prime as in beginning and composite as $2019 = 3cdot673$




          Sum my digits and half; I'll be perfect!




          $2 + 0 + 1 + 9 = 12$, then $12/2 = 6$




          Don't multiply them, I won't yield a thing




          $2 cdot 0 cdot 1 cdot 9 = 0$




          But don't worry, it's only the beginning!




          Happening around the world today!







          share|improve this answer









          $endgroup$









          • 1




            $begingroup$
            This must be the answer!
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:59










          • $begingroup$
            Yes, you got it! Prime can also mean importance, and it is so for a new year :)
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 15:00






          • 2




            $begingroup$
            Would the wording "Sum my digits and halve" be better?
            $endgroup$
            – greenturtle3141
            Jan 1 at 22:23
















          14












          $begingroup$

          Hoping this is good




          $2019$




          I am prime, I am composite




          Prime as in beginning and composite as $2019 = 3cdot673$




          Sum my digits and half; I'll be perfect!




          $2 + 0 + 1 + 9 = 12$, then $12/2 = 6$




          Don't multiply them, I won't yield a thing




          $2 cdot 0 cdot 1 cdot 9 = 0$




          But don't worry, it's only the beginning!




          Happening around the world today!







          share|improve this answer









          $endgroup$









          • 1




            $begingroup$
            This must be the answer!
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:59










          • $begingroup$
            Yes, you got it! Prime can also mean importance, and it is so for a new year :)
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 15:00






          • 2




            $begingroup$
            Would the wording "Sum my digits and halve" be better?
            $endgroup$
            – greenturtle3141
            Jan 1 at 22:23














          14












          14








          14





          $begingroup$

          Hoping this is good




          $2019$




          I am prime, I am composite




          Prime as in beginning and composite as $2019 = 3cdot673$




          Sum my digits and half; I'll be perfect!




          $2 + 0 + 1 + 9 = 12$, then $12/2 = 6$




          Don't multiply them, I won't yield a thing




          $2 cdot 0 cdot 1 cdot 9 = 0$




          But don't worry, it's only the beginning!




          Happening around the world today!







          share|improve this answer









          $endgroup$



          Hoping this is good




          $2019$




          I am prime, I am composite




          Prime as in beginning and composite as $2019 = 3cdot673$




          Sum my digits and half; I'll be perfect!




          $2 + 0 + 1 + 9 = 12$, then $12/2 = 6$




          Don't multiply them, I won't yield a thing




          $2 cdot 0 cdot 1 cdot 9 = 0$




          But don't worry, it's only the beginning!




          Happening around the world today!








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Dec 31 '18 at 14:58









          TomTom

          36.6k3132209




          36.6k3132209








          • 1




            $begingroup$
            This must be the answer!
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:59










          • $begingroup$
            Yes, you got it! Prime can also mean importance, and it is so for a new year :)
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 15:00






          • 2




            $begingroup$
            Would the wording "Sum my digits and halve" be better?
            $endgroup$
            – greenturtle3141
            Jan 1 at 22:23














          • 1




            $begingroup$
            This must be the answer!
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:59










          • $begingroup$
            Yes, you got it! Prime can also mean importance, and it is so for a new year :)
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 15:00






          • 2




            $begingroup$
            Would the wording "Sum my digits and halve" be better?
            $endgroup$
            – greenturtle3141
            Jan 1 at 22:23








          1




          1




          $begingroup$
          This must be the answer!
          $endgroup$
          – Matt Cremeens
          Dec 31 '18 at 14:59




          $begingroup$
          This must be the answer!
          $endgroup$
          – Matt Cremeens
          Dec 31 '18 at 14:59












          $begingroup$
          Yes, you got it! Prime can also mean importance, and it is so for a new year :)
          $endgroup$
          – TheSimpliFire
          Dec 31 '18 at 15:00




          $begingroup$
          Yes, you got it! Prime can also mean importance, and it is so for a new year :)
          $endgroup$
          – TheSimpliFire
          Dec 31 '18 at 15:00




          2




          2




          $begingroup$
          Would the wording "Sum my digits and halve" be better?
          $endgroup$
          – greenturtle3141
          Jan 1 at 22:23




          $begingroup$
          Would the wording "Sum my digits and halve" be better?
          $endgroup$
          – greenturtle3141
          Jan 1 at 22:23











          2












          $begingroup$

          I'm thinking it might be




          $39$

          $(3+9)/2=6$, a perfect number as its factors sum to the number itself: $1+2+3=6$

          $3$ is prime and $9$ is composite


          Multiplying them won't yield just a thing, it yields $3times 9=27$ things


          I am a bit hung up on this but perhaps $39$ is the beginning of a sequence where these rules hold true (i.e., it's the smallest number produced by these rules). Or perhaps it's the first two of this series: $3^1, 3^2, 3^3, cdots$







          share|improve this answer











          $endgroup$









          • 2




            $begingroup$
            (3+8)/2 is not 6, but 5.5
            $endgroup$
            – SPK.z
            Dec 31 '18 at 14:46










          • $begingroup$
            Nope, unfortunately, but good attempt!
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:47






          • 1




            $begingroup$
            @SPK.z I can't believe I made that mistake. I'll edit.
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:48


















          2












          $begingroup$

          I'm thinking it might be




          $39$

          $(3+9)/2=6$, a perfect number as its factors sum to the number itself: $1+2+3=6$

          $3$ is prime and $9$ is composite


          Multiplying them won't yield just a thing, it yields $3times 9=27$ things


          I am a bit hung up on this but perhaps $39$ is the beginning of a sequence where these rules hold true (i.e., it's the smallest number produced by these rules). Or perhaps it's the first two of this series: $3^1, 3^2, 3^3, cdots$







          share|improve this answer











          $endgroup$









          • 2




            $begingroup$
            (3+8)/2 is not 6, but 5.5
            $endgroup$
            – SPK.z
            Dec 31 '18 at 14:46










          • $begingroup$
            Nope, unfortunately, but good attempt!
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:47






          • 1




            $begingroup$
            @SPK.z I can't believe I made that mistake. I'll edit.
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:48
















          2












          2








          2





          $begingroup$

          I'm thinking it might be




          $39$

          $(3+9)/2=6$, a perfect number as its factors sum to the number itself: $1+2+3=6$

          $3$ is prime and $9$ is composite


          Multiplying them won't yield just a thing, it yields $3times 9=27$ things


          I am a bit hung up on this but perhaps $39$ is the beginning of a sequence where these rules hold true (i.e., it's the smallest number produced by these rules). Or perhaps it's the first two of this series: $3^1, 3^2, 3^3, cdots$







          share|improve this answer











          $endgroup$



          I'm thinking it might be




          $39$

          $(3+9)/2=6$, a perfect number as its factors sum to the number itself: $1+2+3=6$

          $3$ is prime and $9$ is composite


          Multiplying them won't yield just a thing, it yields $3times 9=27$ things


          I am a bit hung up on this but perhaps $39$ is the beginning of a sequence where these rules hold true (i.e., it's the smallest number produced by these rules). Or perhaps it's the first two of this series: $3^1, 3^2, 3^3, cdots$








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Dec 31 '18 at 15:39









          TheSimpliFire

          2,210532




          2,210532










          answered Dec 31 '18 at 14:44









          Matt CremeensMatt Cremeens

          23229




          23229








          • 2




            $begingroup$
            (3+8)/2 is not 6, but 5.5
            $endgroup$
            – SPK.z
            Dec 31 '18 at 14:46










          • $begingroup$
            Nope, unfortunately, but good attempt!
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:47






          • 1




            $begingroup$
            @SPK.z I can't believe I made that mistake. I'll edit.
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:48
















          • 2




            $begingroup$
            (3+8)/2 is not 6, but 5.5
            $endgroup$
            – SPK.z
            Dec 31 '18 at 14:46










          • $begingroup$
            Nope, unfortunately, but good attempt!
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:47






          • 1




            $begingroup$
            @SPK.z I can't believe I made that mistake. I'll edit.
            $endgroup$
            – Matt Cremeens
            Dec 31 '18 at 14:48










          2




          2




          $begingroup$
          (3+8)/2 is not 6, but 5.5
          $endgroup$
          – SPK.z
          Dec 31 '18 at 14:46




          $begingroup$
          (3+8)/2 is not 6, but 5.5
          $endgroup$
          – SPK.z
          Dec 31 '18 at 14:46












          $begingroup$
          Nope, unfortunately, but good attempt!
          $endgroup$
          – TheSimpliFire
          Dec 31 '18 at 14:47




          $begingroup$
          Nope, unfortunately, but good attempt!
          $endgroup$
          – TheSimpliFire
          Dec 31 '18 at 14:47




          1




          1




          $begingroup$
          @SPK.z I can't believe I made that mistake. I'll edit.
          $endgroup$
          – Matt Cremeens
          Dec 31 '18 at 14:48






          $begingroup$
          @SPK.z I can't believe I made that mistake. I'll edit.
          $endgroup$
          – Matt Cremeens
          Dec 31 '18 at 14:48













          2












          $begingroup$

          Partial:



          Are you




          1?




          I am prime, I am composite




          Some say 1 is prime, some say it is composite




          Sum my digits and half; I'll be perfect!




          ? Perfect number? Perhaps not




          Don't multiply them, I won't yield a thing




          any n*1 yield n




          But don't worry, it's only the beginning!




          beginning of natural numbers







          share|improve this answer











          $endgroup$













          • $begingroup$
            Nope (1 isn't conventionally a perfect number) ;P
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:48






          • 2




            $begingroup$
            Technically 1 is neither prime nor composite.
            $endgroup$
            – tilper
            Dec 31 '18 at 15:44






          • 1




            $begingroup$
            To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
            $endgroup$
            – Eevee Trainer
            Jan 1 at 10:56


















          2












          $begingroup$

          Partial:



          Are you




          1?




          I am prime, I am composite




          Some say 1 is prime, some say it is composite




          Sum my digits and half; I'll be perfect!




          ? Perfect number? Perhaps not




          Don't multiply them, I won't yield a thing




          any n*1 yield n




          But don't worry, it's only the beginning!




          beginning of natural numbers







          share|improve this answer











          $endgroup$













          • $begingroup$
            Nope (1 isn't conventionally a perfect number) ;P
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:48






          • 2




            $begingroup$
            Technically 1 is neither prime nor composite.
            $endgroup$
            – tilper
            Dec 31 '18 at 15:44






          • 1




            $begingroup$
            To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
            $endgroup$
            – Eevee Trainer
            Jan 1 at 10:56
















          2












          2








          2





          $begingroup$

          Partial:



          Are you




          1?




          I am prime, I am composite




          Some say 1 is prime, some say it is composite




          Sum my digits and half; I'll be perfect!




          ? Perfect number? Perhaps not




          Don't multiply them, I won't yield a thing




          any n*1 yield n




          But don't worry, it's only the beginning!




          beginning of natural numbers







          share|improve this answer











          $endgroup$



          Partial:



          Are you




          1?




          I am prime, I am composite




          Some say 1 is prime, some say it is composite




          Sum my digits and half; I'll be perfect!




          ? Perfect number? Perhaps not




          Don't multiply them, I won't yield a thing




          any n*1 yield n




          But don't worry, it's only the beginning!




          beginning of natural numbers








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 1 at 11:25

























          answered Dec 31 '18 at 14:35









          Omega KryptonOmega Krypton

          5,5792849




          5,5792849












          • $begingroup$
            Nope (1 isn't conventionally a perfect number) ;P
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:48






          • 2




            $begingroup$
            Technically 1 is neither prime nor composite.
            $endgroup$
            – tilper
            Dec 31 '18 at 15:44






          • 1




            $begingroup$
            To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
            $endgroup$
            – Eevee Trainer
            Jan 1 at 10:56




















          • $begingroup$
            Nope (1 isn't conventionally a perfect number) ;P
            $endgroup$
            – TheSimpliFire
            Dec 31 '18 at 14:48






          • 2




            $begingroup$
            Technically 1 is neither prime nor composite.
            $endgroup$
            – tilper
            Dec 31 '18 at 15:44






          • 1




            $begingroup$
            To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
            $endgroup$
            – Eevee Trainer
            Jan 1 at 10:56


















          $begingroup$
          Nope (1 isn't conventionally a perfect number) ;P
          $endgroup$
          – TheSimpliFire
          Dec 31 '18 at 14:48




          $begingroup$
          Nope (1 isn't conventionally a perfect number) ;P
          $endgroup$
          – TheSimpliFire
          Dec 31 '18 at 14:48




          2




          2




          $begingroup$
          Technically 1 is neither prime nor composite.
          $endgroup$
          – tilper
          Dec 31 '18 at 15:44




          $begingroup$
          Technically 1 is neither prime nor composite.
          $endgroup$
          – tilper
          Dec 31 '18 at 15:44




          1




          1




          $begingroup$
          To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
          $endgroup$
          – Eevee Trainer
          Jan 1 at 10:56






          $begingroup$
          To note, a "perfect number" is a number whose factors sum to twice that number, or one whose factors (excluding itself) sum to the number itself.
          $endgroup$
          – Eevee Trainer
          Jan 1 at 10:56




















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