Dynamics $delta x(t)=delta x(0) e^{lambda t}$ of Henon Attractor












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$begingroup$


Recall the question I asked before:
Linearized perturbation dynamics of Henon Attractor



So, I have the following separation dynamics for Henon attractor ($a = 1.4. b = 0.3$) $$delta x(t)=delta x(0) e^{lambda t},$$



where $lambda = 0.42$ is a Lyapunov exponent. Since $e^{lambda}>1$, so the difference of separation will increase exponentially.



However, the following is what I do in MATLAB, I choose two initial conditions: $$x(0) = begin{bmatrix} 0 \ 0 end{bmatrix}, x'(0) = begin{bmatrix} 0.1 \ 0.1 end{bmatrix}.$$ It is easily calculated (by the Henon dynamical system) that $$x(1) = begin{bmatrix} 1 \ 0 end{bmatrix}, x'(1) = begin{bmatrix} 1.086 \ 0.03 end{bmatrix}.$$



It seems that the difference of separation (distance) decreases.



The following picture is simulated in MATLAB.
enter image description here




My question is why the simulated result is different from the theoretical prediction $delta x(t)=delta x(0) e^{lambda t}$. Do I misunderstand something?











share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    Recall the question I asked before:
    Linearized perturbation dynamics of Henon Attractor



    So, I have the following separation dynamics for Henon attractor ($a = 1.4. b = 0.3$) $$delta x(t)=delta x(0) e^{lambda t},$$



    where $lambda = 0.42$ is a Lyapunov exponent. Since $e^{lambda}>1$, so the difference of separation will increase exponentially.



    However, the following is what I do in MATLAB, I choose two initial conditions: $$x(0) = begin{bmatrix} 0 \ 0 end{bmatrix}, x'(0) = begin{bmatrix} 0.1 \ 0.1 end{bmatrix}.$$ It is easily calculated (by the Henon dynamical system) that $$x(1) = begin{bmatrix} 1 \ 0 end{bmatrix}, x'(1) = begin{bmatrix} 1.086 \ 0.03 end{bmatrix}.$$



    It seems that the difference of separation (distance) decreases.



    The following picture is simulated in MATLAB.
    enter image description here




    My question is why the simulated result is different from the theoretical prediction $delta x(t)=delta x(0) e^{lambda t}$. Do I misunderstand something?











    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Recall the question I asked before:
      Linearized perturbation dynamics of Henon Attractor



      So, I have the following separation dynamics for Henon attractor ($a = 1.4. b = 0.3$) $$delta x(t)=delta x(0) e^{lambda t},$$



      where $lambda = 0.42$ is a Lyapunov exponent. Since $e^{lambda}>1$, so the difference of separation will increase exponentially.



      However, the following is what I do in MATLAB, I choose two initial conditions: $$x(0) = begin{bmatrix} 0 \ 0 end{bmatrix}, x'(0) = begin{bmatrix} 0.1 \ 0.1 end{bmatrix}.$$ It is easily calculated (by the Henon dynamical system) that $$x(1) = begin{bmatrix} 1 \ 0 end{bmatrix}, x'(1) = begin{bmatrix} 1.086 \ 0.03 end{bmatrix}.$$



      It seems that the difference of separation (distance) decreases.



      The following picture is simulated in MATLAB.
      enter image description here




      My question is why the simulated result is different from the theoretical prediction $delta x(t)=delta x(0) e^{lambda t}$. Do I misunderstand something?











      share|cite|improve this question











      $endgroup$




      Recall the question I asked before:
      Linearized perturbation dynamics of Henon Attractor



      So, I have the following separation dynamics for Henon attractor ($a = 1.4. b = 0.3$) $$delta x(t)=delta x(0) e^{lambda t},$$



      where $lambda = 0.42$ is a Lyapunov exponent. Since $e^{lambda}>1$, so the difference of separation will increase exponentially.



      However, the following is what I do in MATLAB, I choose two initial conditions: $$x(0) = begin{bmatrix} 0 \ 0 end{bmatrix}, x'(0) = begin{bmatrix} 0.1 \ 0.1 end{bmatrix}.$$ It is easily calculated (by the Henon dynamical system) that $$x(1) = begin{bmatrix} 1 \ 0 end{bmatrix}, x'(1) = begin{bmatrix} 1.086 \ 0.03 end{bmatrix}.$$



      It seems that the difference of separation (distance) decreases.



      The following picture is simulated in MATLAB.
      enter image description here




      My question is why the simulated result is different from the theoretical prediction $delta x(t)=delta x(0) e^{lambda t}$. Do I misunderstand something?








      dynamical-systems chaos-theory stability-theory






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




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      edited Dec 6 '18 at 6:45







      sleeve chen

















      asked Dec 1 '18 at 21:42









      sleeve chensleeve chen

      3,07141852




      3,07141852






















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