Chemical composition of seawater
$begingroup$
Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.
If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?
The book which I am reading says which is confusing me:
... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.
water elements
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
$endgroup$
add a comment |
$begingroup$
Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.
If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?
The book which I am reading says which is confusing me:
... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.
water elements
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
$endgroup$
add a comment |
$begingroup$
Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.
If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?
The book which I am reading says which is confusing me:
... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.
water elements
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
$endgroup$
Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.
If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?
The book which I am reading says which is confusing me:
... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.
water elements
water elements
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
edited Dec 17 '18 at 20:32
andselisk
17.8k656117
17.8k656117
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
asked Dec 17 '18 at 19:10
AhmedAhmed
1264
1264
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
The book that you're reading is measuring by mass.
If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
$endgroup$
add a comment |
$begingroup$
As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:
begin{array}{llr}
hline
text{Element} & rho_i/pu{mg L-1} & omega/% \
hline
ce{O} & pu{8.57E5} & 85.8443 \
ce{H} & pu{1.08E5} & 10.8182 \
ce{Cl} & pu{1.94E4} & 1.9433 \
ce{Na} & pu{1.08E4} & 1.0818 \
ce{Mg} & pu{1.29E3} & 0.1292 \
ce{S} & pu{9.05E2} & 0.0907 \
ce{Ca} & pu{4.12E2} & 0.0413 \
ce{K} & pu{3.99E2} & 0.0400 \
ce{Br} & pu{6.73E1} & 0.0067 \
ce{C} & pu{2.80E1} & 0.0028 \
ce{Sr} & pu{7.9} & 0.0008 \
ce{B} & pu{4.44} & 0.0004 \
ce{Si} & pu{2.2} & 0.0002 \
ce{F} & pu{1.3} & 0.0001 \
ce{N} & pu{5.00E-1} & 0.0001 \
hline
end{array}
References
- Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
$endgroup$
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
add a comment |
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2 Answers
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2 Answers
2
active
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active
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$begingroup$
The book that you're reading is measuring by mass.
If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
$endgroup$
add a comment |
$begingroup$
The book that you're reading is measuring by mass.
If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
$endgroup$
add a comment |
$begingroup$
The book that you're reading is measuring by mass.
If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
$endgroup$
The book that you're reading is measuring by mass.
If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
answered Dec 17 '18 at 19:23
PJ RPJ R
1,007113
1,007113
add a comment |
add a comment |
$begingroup$
As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:
begin{array}{llr}
hline
text{Element} & rho_i/pu{mg L-1} & omega/% \
hline
ce{O} & pu{8.57E5} & 85.8443 \
ce{H} & pu{1.08E5} & 10.8182 \
ce{Cl} & pu{1.94E4} & 1.9433 \
ce{Na} & pu{1.08E4} & 1.0818 \
ce{Mg} & pu{1.29E3} & 0.1292 \
ce{S} & pu{9.05E2} & 0.0907 \
ce{Ca} & pu{4.12E2} & 0.0413 \
ce{K} & pu{3.99E2} & 0.0400 \
ce{Br} & pu{6.73E1} & 0.0067 \
ce{C} & pu{2.80E1} & 0.0028 \
ce{Sr} & pu{7.9} & 0.0008 \
ce{B} & pu{4.44} & 0.0004 \
ce{Si} & pu{2.2} & 0.0002 \
ce{F} & pu{1.3} & 0.0001 \
ce{N} & pu{5.00E-1} & 0.0001 \
hline
end{array}
References
- Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
$endgroup$
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
add a comment |
$begingroup$
As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:
begin{array}{llr}
hline
text{Element} & rho_i/pu{mg L-1} & omega/% \
hline
ce{O} & pu{8.57E5} & 85.8443 \
ce{H} & pu{1.08E5} & 10.8182 \
ce{Cl} & pu{1.94E4} & 1.9433 \
ce{Na} & pu{1.08E4} & 1.0818 \
ce{Mg} & pu{1.29E3} & 0.1292 \
ce{S} & pu{9.05E2} & 0.0907 \
ce{Ca} & pu{4.12E2} & 0.0413 \
ce{K} & pu{3.99E2} & 0.0400 \
ce{Br} & pu{6.73E1} & 0.0067 \
ce{C} & pu{2.80E1} & 0.0028 \
ce{Sr} & pu{7.9} & 0.0008 \
ce{B} & pu{4.44} & 0.0004 \
ce{Si} & pu{2.2} & 0.0002 \
ce{F} & pu{1.3} & 0.0001 \
ce{N} & pu{5.00E-1} & 0.0001 \
hline
end{array}
References
- Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
$endgroup$
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
add a comment |
$begingroup$
As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:
begin{array}{llr}
hline
text{Element} & rho_i/pu{mg L-1} & omega/% \
hline
ce{O} & pu{8.57E5} & 85.8443 \
ce{H} & pu{1.08E5} & 10.8182 \
ce{Cl} & pu{1.94E4} & 1.9433 \
ce{Na} & pu{1.08E4} & 1.0818 \
ce{Mg} & pu{1.29E3} & 0.1292 \
ce{S} & pu{9.05E2} & 0.0907 \
ce{Ca} & pu{4.12E2} & 0.0413 \
ce{K} & pu{3.99E2} & 0.0400 \
ce{Br} & pu{6.73E1} & 0.0067 \
ce{C} & pu{2.80E1} & 0.0028 \
ce{Sr} & pu{7.9} & 0.0008 \
ce{B} & pu{4.44} & 0.0004 \
ce{Si} & pu{2.2} & 0.0002 \
ce{F} & pu{1.3} & 0.0001 \
ce{N} & pu{5.00E-1} & 0.0001 \
hline
end{array}
References
- Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
$endgroup$
As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:
begin{array}{llr}
hline
text{Element} & rho_i/pu{mg L-1} & omega/% \
hline
ce{O} & pu{8.57E5} & 85.8443 \
ce{H} & pu{1.08E5} & 10.8182 \
ce{Cl} & pu{1.94E4} & 1.9433 \
ce{Na} & pu{1.08E4} & 1.0818 \
ce{Mg} & pu{1.29E3} & 0.1292 \
ce{S} & pu{9.05E2} & 0.0907 \
ce{Ca} & pu{4.12E2} & 0.0413 \
ce{K} & pu{3.99E2} & 0.0400 \
ce{Br} & pu{6.73E1} & 0.0067 \
ce{C} & pu{2.80E1} & 0.0028 \
ce{Sr} & pu{7.9} & 0.0008 \
ce{B} & pu{4.44} & 0.0004 \
ce{Si} & pu{2.2} & 0.0002 \
ce{F} & pu{1.3} & 0.0001 \
ce{N} & pu{5.00E-1} & 0.0001 \
hline
end{array}
References
- Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
edited Dec 17 '18 at 22:51
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
answered Dec 17 '18 at 20:29
andseliskandselisk
17.8k656117
17.8k656117
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
add a comment |
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
$begingroup$
You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
$endgroup$
– Mr Lister
Dec 18 '18 at 10:50
add a comment |
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