Changing domain of solution in Integer Programming












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I'm given an inequality $a_1x_1 + a_2x_2 geq c_1$ where $a, c, x_1, x_2$ are integers and $x_1, x_2 text{ are either } 1 text{ or } 0$.



I'd like to construct another inequality $b_1y_1 + b_2y_2 geq c_2$ where $b, c, y_1, y_2$ are integers in range $[-k, k]$ in a way s.t. first inequality is satisfiable iff second inequality is satisfiable.



I've tried to map $x_1, x_2$ to $y_1, y_2$ via affine transformation but it doesn't seem like the right approach.



How should I approach this problem?










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  • $begingroup$
    I take it $k$ is fixed? Do you know anything about the signs of the symbols in the first constraint?
    $endgroup$
    – prubin
    Dec 18 '18 at 22:17










  • $begingroup$
    @prubin yes k is fixed. No assumption about the signs of coefficients.
    $endgroup$
    – SpiderRico
    Dec 18 '18 at 22:25










  • $begingroup$
    Also just to be clear, the domain requirement ${-k,dots,k}$ applies not just to the $y$ variables but also to the coefficients $b$ and $c_2$?
    $endgroup$
    – prubin
    Dec 20 '18 at 1:03










  • $begingroup$
    @prubin This is correct. In second inequality, range condition applies both to coefficients and variables.
    $endgroup$
    – SpiderRico
    Dec 21 '18 at 3:36
















0












$begingroup$


I'm given an inequality $a_1x_1 + a_2x_2 geq c_1$ where $a, c, x_1, x_2$ are integers and $x_1, x_2 text{ are either } 1 text{ or } 0$.



I'd like to construct another inequality $b_1y_1 + b_2y_2 geq c_2$ where $b, c, y_1, y_2$ are integers in range $[-k, k]$ in a way s.t. first inequality is satisfiable iff second inequality is satisfiable.



I've tried to map $x_1, x_2$ to $y_1, y_2$ via affine transformation but it doesn't seem like the right approach.



How should I approach this problem?










share|cite|improve this question









$endgroup$












  • $begingroup$
    I take it $k$ is fixed? Do you know anything about the signs of the symbols in the first constraint?
    $endgroup$
    – prubin
    Dec 18 '18 at 22:17










  • $begingroup$
    @prubin yes k is fixed. No assumption about the signs of coefficients.
    $endgroup$
    – SpiderRico
    Dec 18 '18 at 22:25










  • $begingroup$
    Also just to be clear, the domain requirement ${-k,dots,k}$ applies not just to the $y$ variables but also to the coefficients $b$ and $c_2$?
    $endgroup$
    – prubin
    Dec 20 '18 at 1:03










  • $begingroup$
    @prubin This is correct. In second inequality, range condition applies both to coefficients and variables.
    $endgroup$
    – SpiderRico
    Dec 21 '18 at 3:36














0












0








0





$begingroup$


I'm given an inequality $a_1x_1 + a_2x_2 geq c_1$ where $a, c, x_1, x_2$ are integers and $x_1, x_2 text{ are either } 1 text{ or } 0$.



I'd like to construct another inequality $b_1y_1 + b_2y_2 geq c_2$ where $b, c, y_1, y_2$ are integers in range $[-k, k]$ in a way s.t. first inequality is satisfiable iff second inequality is satisfiable.



I've tried to map $x_1, x_2$ to $y_1, y_2$ via affine transformation but it doesn't seem like the right approach.



How should I approach this problem?










share|cite|improve this question









$endgroup$




I'm given an inequality $a_1x_1 + a_2x_2 geq c_1$ where $a, c, x_1, x_2$ are integers and $x_1, x_2 text{ are either } 1 text{ or } 0$.



I'd like to construct another inequality $b_1y_1 + b_2y_2 geq c_2$ where $b, c, y_1, y_2$ are integers in range $[-k, k]$ in a way s.t. first inequality is satisfiable iff second inequality is satisfiable.



I've tried to map $x_1, x_2$ to $y_1, y_2$ via affine transformation but it doesn't seem like the right approach.



How should I approach this problem?







linear-algebra inequality integer-programming






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 18 '18 at 3:25









SpiderRicoSpiderRico

259111




259111












  • $begingroup$
    I take it $k$ is fixed? Do you know anything about the signs of the symbols in the first constraint?
    $endgroup$
    – prubin
    Dec 18 '18 at 22:17










  • $begingroup$
    @prubin yes k is fixed. No assumption about the signs of coefficients.
    $endgroup$
    – SpiderRico
    Dec 18 '18 at 22:25










  • $begingroup$
    Also just to be clear, the domain requirement ${-k,dots,k}$ applies not just to the $y$ variables but also to the coefficients $b$ and $c_2$?
    $endgroup$
    – prubin
    Dec 20 '18 at 1:03










  • $begingroup$
    @prubin This is correct. In second inequality, range condition applies both to coefficients and variables.
    $endgroup$
    – SpiderRico
    Dec 21 '18 at 3:36


















  • $begingroup$
    I take it $k$ is fixed? Do you know anything about the signs of the symbols in the first constraint?
    $endgroup$
    – prubin
    Dec 18 '18 at 22:17










  • $begingroup$
    @prubin yes k is fixed. No assumption about the signs of coefficients.
    $endgroup$
    – SpiderRico
    Dec 18 '18 at 22:25










  • $begingroup$
    Also just to be clear, the domain requirement ${-k,dots,k}$ applies not just to the $y$ variables but also to the coefficients $b$ and $c_2$?
    $endgroup$
    – prubin
    Dec 20 '18 at 1:03










  • $begingroup$
    @prubin This is correct. In second inequality, range condition applies both to coefficients and variables.
    $endgroup$
    – SpiderRico
    Dec 21 '18 at 3:36
















$begingroup$
I take it $k$ is fixed? Do you know anything about the signs of the symbols in the first constraint?
$endgroup$
– prubin
Dec 18 '18 at 22:17




$begingroup$
I take it $k$ is fixed? Do you know anything about the signs of the symbols in the first constraint?
$endgroup$
– prubin
Dec 18 '18 at 22:17












$begingroup$
@prubin yes k is fixed. No assumption about the signs of coefficients.
$endgroup$
– SpiderRico
Dec 18 '18 at 22:25




$begingroup$
@prubin yes k is fixed. No assumption about the signs of coefficients.
$endgroup$
– SpiderRico
Dec 18 '18 at 22:25












$begingroup$
Also just to be clear, the domain requirement ${-k,dots,k}$ applies not just to the $y$ variables but also to the coefficients $b$ and $c_2$?
$endgroup$
– prubin
Dec 20 '18 at 1:03




$begingroup$
Also just to be clear, the domain requirement ${-k,dots,k}$ applies not just to the $y$ variables but also to the coefficients $b$ and $c_2$?
$endgroup$
– prubin
Dec 20 '18 at 1:03












$begingroup$
@prubin This is correct. In second inequality, range condition applies both to coefficients and variables.
$endgroup$
– SpiderRico
Dec 21 '18 at 3:36




$begingroup$
@prubin This is correct. In second inequality, range condition applies both to coefficients and variables.
$endgroup$
– SpiderRico
Dec 21 '18 at 3:36










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