Computing series exactly












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$begingroup$


Using the formula $sum^{infty}_{n=0} {x^n} = frac{1}{1-x}$
take the derivative of both sides with respect to the variable x to find a new formula for another series. Use this formula to compute exactly the series:



$sum^{infty}_{n=0} frac{n}{3^n} = frac{1}{3}+frac{2}{9} + frac{3}{27} + frac{4}{81}$



What is this question asking me to do? I don't know of a way to take the derivative of $sum^{infty}_{n=0} {x^n}$, but that is probably just my lack of experience. I am sorry for the lack of attempt to answer this question, I am completely lost.










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  • 1




    $begingroup$
    $sum_{n=0}^infty x^n=1+x+x^2+x^3+cdots$. Can you differentiate $1$? Can you differentiate $x$? Can you differentiate $x^2$? Can you differentiate $x^3,ldots$? Can you add up the results?
    $endgroup$
    – Lord Shark the Unknown
    Dec 20 '18 at 18:17
















0












$begingroup$


Using the formula $sum^{infty}_{n=0} {x^n} = frac{1}{1-x}$
take the derivative of both sides with respect to the variable x to find a new formula for another series. Use this formula to compute exactly the series:



$sum^{infty}_{n=0} frac{n}{3^n} = frac{1}{3}+frac{2}{9} + frac{3}{27} + frac{4}{81}$



What is this question asking me to do? I don't know of a way to take the derivative of $sum^{infty}_{n=0} {x^n}$, but that is probably just my lack of experience. I am sorry for the lack of attempt to answer this question, I am completely lost.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    $sum_{n=0}^infty x^n=1+x+x^2+x^3+cdots$. Can you differentiate $1$? Can you differentiate $x$? Can you differentiate $x^2$? Can you differentiate $x^3,ldots$? Can you add up the results?
    $endgroup$
    – Lord Shark the Unknown
    Dec 20 '18 at 18:17














0












0








0





$begingroup$


Using the formula $sum^{infty}_{n=0} {x^n} = frac{1}{1-x}$
take the derivative of both sides with respect to the variable x to find a new formula for another series. Use this formula to compute exactly the series:



$sum^{infty}_{n=0} frac{n}{3^n} = frac{1}{3}+frac{2}{9} + frac{3}{27} + frac{4}{81}$



What is this question asking me to do? I don't know of a way to take the derivative of $sum^{infty}_{n=0} {x^n}$, but that is probably just my lack of experience. I am sorry for the lack of attempt to answer this question, I am completely lost.










share|cite|improve this question











$endgroup$




Using the formula $sum^{infty}_{n=0} {x^n} = frac{1}{1-x}$
take the derivative of both sides with respect to the variable x to find a new formula for another series. Use this formula to compute exactly the series:



$sum^{infty}_{n=0} frac{n}{3^n} = frac{1}{3}+frac{2}{9} + frac{3}{27} + frac{4}{81}$



What is this question asking me to do? I don't know of a way to take the derivative of $sum^{infty}_{n=0} {x^n}$, but that is probably just my lack of experience. I am sorry for the lack of attempt to answer this question, I am completely lost.







calculus sequences-and-series taylor-expansion






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edited Dec 20 '18 at 18:18









Foobaz John

22.8k41452




22.8k41452










asked Dec 20 '18 at 18:14









ElijahElijah

626




626








  • 1




    $begingroup$
    $sum_{n=0}^infty x^n=1+x+x^2+x^3+cdots$. Can you differentiate $1$? Can you differentiate $x$? Can you differentiate $x^2$? Can you differentiate $x^3,ldots$? Can you add up the results?
    $endgroup$
    – Lord Shark the Unknown
    Dec 20 '18 at 18:17














  • 1




    $begingroup$
    $sum_{n=0}^infty x^n=1+x+x^2+x^3+cdots$. Can you differentiate $1$? Can you differentiate $x$? Can you differentiate $x^2$? Can you differentiate $x^3,ldots$? Can you add up the results?
    $endgroup$
    – Lord Shark the Unknown
    Dec 20 '18 at 18:17








1




1




$begingroup$
$sum_{n=0}^infty x^n=1+x+x^2+x^3+cdots$. Can you differentiate $1$? Can you differentiate $x$? Can you differentiate $x^2$? Can you differentiate $x^3,ldots$? Can you add up the results?
$endgroup$
– Lord Shark the Unknown
Dec 20 '18 at 18:17




$begingroup$
$sum_{n=0}^infty x^n=1+x+x^2+x^3+cdots$. Can you differentiate $1$? Can you differentiate $x$? Can you differentiate $x^2$? Can you differentiate $x^3,ldots$? Can you add up the results?
$endgroup$
– Lord Shark the Unknown
Dec 20 '18 at 18:17










1 Answer
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$begingroup$

Note that term by term differentiation followed by multiplication by $x$ gives us that
$$
frac{x}{(1-x)^2}=xDleft(frac{1}{1-x}right)=xsum_{n=0}^infty nx^{n-1}=sum_{n=0}^infty nx^{n} quad (|x|<1).
$$






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    1 Answer
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    $begingroup$

    Note that term by term differentiation followed by multiplication by $x$ gives us that
    $$
    frac{x}{(1-x)^2}=xDleft(frac{1}{1-x}right)=xsum_{n=0}^infty nx^{n-1}=sum_{n=0}^infty nx^{n} quad (|x|<1).
    $$






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Note that term by term differentiation followed by multiplication by $x$ gives us that
      $$
      frac{x}{(1-x)^2}=xDleft(frac{1}{1-x}right)=xsum_{n=0}^infty nx^{n-1}=sum_{n=0}^infty nx^{n} quad (|x|<1).
      $$






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Note that term by term differentiation followed by multiplication by $x$ gives us that
        $$
        frac{x}{(1-x)^2}=xDleft(frac{1}{1-x}right)=xsum_{n=0}^infty nx^{n-1}=sum_{n=0}^infty nx^{n} quad (|x|<1).
        $$






        share|cite|improve this answer









        $endgroup$



        Note that term by term differentiation followed by multiplication by $x$ gives us that
        $$
        frac{x}{(1-x)^2}=xDleft(frac{1}{1-x}right)=xsum_{n=0}^infty nx^{n-1}=sum_{n=0}^infty nx^{n} quad (|x|<1).
        $$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 20 '18 at 18:17









        Foobaz JohnFoobaz John

        22.8k41452




        22.8k41452






























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