Horizontal angular rotation speed
up vote
0
down vote
favorite
Below is the question I'm not sure I've properly solved.
A smooth bead of mass 100g is threaded on a light inextensible string of length 70 cm. The string has one end attached to a fixed point A and the other to a fixed point B 50 cm vertically below A. The bead moves in a horizontal circle about the line AB with a constant angular speed of $omega$ rad/s, and the string taut. If the bead is at a point C on the string with AC = 40 cm, find the value of $omega$ and the tension in the string.
Because its a 3-4-5 triangle, I found the horizontal rotation plane to be 0.18m above B, and therefore 0.32m below A. The radius is then 0.24m. I found this by extending AC to 6.25m. I then resolve the vertical and horizontal forces and found $omega$ to be 4.88 rad/s. I`m however not sure about this answer as books says 16.9, 4.9N.
Any help would be appreciated.
Here is an image to help.
geometry trigonometry physics
edited Nov 19 at 15:57
bob.sacamento
2,3941819
asked Nov 19 at 11:38
tas75
83
add a comment |
up vote
0
down vote
favorite
Below is the question I'm not sure I've properly solved.
A smooth bead of mass 100g is threaded on a light inextensible string of length 70 cm. The string has one end attached to a fixed point A and the other to a fixed point B 50 cm vertically below A. The bead moves in a horizontal circle about the line AB with a constant angular speed of $omega$ rad/s, and the string taut. If the bead is at a point C on the string with AC = 40 cm, find the value of $omega$ and the tension in the string.
Because its a 3-4-5 triangle, I found the horizontal rotation plane to be 0.18m above B, and therefore 0.32m below A. The radius is then 0.24m. I found this by extending AC to 6.25m. I then resolve the vertical and horizontal forces and found $omega$ to be 4.88 rad/s. I`m however not sure about this answer as books says 16.9, 4.9N.
Any help would be appreciated.
Here is an image to help.
geometry trigonometry physics
edited Nov 19 at 15:57
bob.sacamento
2,3941819
asked Nov 19 at 11:38
tas75
83
Could you add a picture or a more detailed description. I am especially stuck on this sentence "The bead moves in a horizontal circle about the line AB".
– maxmilgram
Nov 19 at 11:49
@maxmilgram, I hope that helps
– tas75
Nov 19 at 12:04
I don't get your answer or the answer in the book. I'll post my free body diagram in the answer because it won't post in the comments.
– Phil H
Nov 19 at 15:52
See revised answer, same as the book.
– Phil H
Nov 19 at 19:24
@Phil H, thanks for confirming the books answer
– tas75
Nov 19 at 20:12
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Below is the question I'm not sure I've properly solved.
A smooth bead of mass 100g is threaded on a light inextensible string of length 70 cm. The string has one end attached to a fixed point A and the other to a fixed point B 50 cm vertically below A. The bead moves in a horizontal circle about the line AB with a constant angular speed of $omega$ rad/s, and the string taut. If the bead is at a point C on the string with AC = 40 cm, find the value of $omega$ and the tension in the string.
Because its a 3-4-5 triangle, I found the horizontal rotation plane to be 0.18m above B, and therefore 0.32m below A. The radius is then 0.24m. I found this by extending AC to 6.25m. I then resolve the vertical and horizontal forces and found $omega$ to be 4.88 rad/s. I`m however not sure about this answer as books says 16.9, 4.9N.
Any help would be appreciated.
Here is an image to help.
geometry trigonometry physics
edited Nov 19 at 15:57
bob.sacamento
2,3941819
asked Nov 19 at 11:38
tas75
83
Below is the question I'm not sure I've properly solved.
A smooth bead of mass 100g is threaded on a light inextensible string of length 70 cm. The string has one end attached to a fixed point A and the other to a fixed point B 50 cm vertically below A. The bead moves in a horizontal circle about the line AB with a constant angular speed of $omega$ rad/s, and the string taut. If the bead is at a point C on the string with AC = 40 cm, find the value of $omega$ and the tension in the string.
Because its a 3-4-5 triangle, I found the horizontal rotation plane to be 0.18m above B, and therefore 0.32m below A. The radius is then 0.24m. I found this by extending AC to 6.25m. I then resolve the vertical and horizontal forces and found $omega$ to be 4.88 rad/s. I`m however not sure about this answer as books says 16.9, 4.9N.
Any help would be appreciated.
Here is an image to help.
geometry trigonometry physics
geometry trigonometry physics
edited Nov 19 at 15:57
bob.sacamento
2,3941819
asked Nov 19 at 11:38
tas75
83
edited Nov 19 at 15:57
bob.sacamento
2,3941819
asked Nov 19 at 11:38
tas75
83
edited Nov 19 at 15:57
bob.sacamento
2,3941819
edited Nov 19 at 15:57
bob.sacamento
2,3941819
edited Nov 19 at 15:57
bob.sacamento
2,3941819
2,3941819
asked Nov 19 at 11:38
tas75
83
asked Nov 19 at 11:38
tas75
83
asked Nov 19 at 11:38
tas75
83
83
Could you add a picture or a more detailed description. I am especially stuck on this sentence "The bead moves in a horizontal circle about the line AB".
– maxmilgram
Nov 19 at 11:49
@maxmilgram, I hope that helps
– tas75
Nov 19 at 12:04
I don't get your answer or the answer in the book. I'll post my free body diagram in the answer because it won't post in the comments.
– Phil H
Nov 19 at 15:52
See revised answer, same as the book.
– Phil H
Nov 19 at 19:24
@Phil H, thanks for confirming the books answer
– tas75
Nov 19 at 20:12
add a comment |
Could you add a picture or a more detailed description. I am especially stuck on this sentence "The bead moves in a horizontal circle about the line AB".
– maxmilgram
Nov 19 at 11:49
@maxmilgram, I hope that helps
– tas75
Nov 19 at 12:04
I don't get your answer or the answer in the book. I'll post my free body diagram in the answer because it won't post in the comments.
– Phil H
Nov 19 at 15:52
See revised answer, same as the book.
– Phil H
Nov 19 at 19:24
@Phil H, thanks for confirming the books answer
– tas75
Nov 19 at 20:12
Could you add a picture or a more detailed description. I am especially stuck on this sentence "The bead moves in a horizontal circle about the line AB".
– maxmilgram
Nov 19 at 11:49
Could you add a picture or a more detailed description. I am especially stuck on this sentence "The bead moves in a horizontal circle about the line AB".
– maxmilgram
Nov 19 at 11:49
@maxmilgram, I hope that helps
– tas75
Nov 19 at 12:04
@maxmilgram, I hope that helps
– tas75
Nov 19 at 12:04
I don't get your answer or the answer in the book. I'll post my free body diagram in the answer because it won't post in the comments.
– Phil H
Nov 19 at 15:52
I don't get your answer or the answer in the book. I'll post my free body diagram in the answer because it won't post in the comments.
– Phil H
Nov 19 at 15:52
See revised answer, same as the book.
– Phil H
Nov 19 at 19:24
See revised answer, same as the book.
– Phil H
Nov 19 at 19:24
@Phil H, thanks for confirming the books answer
– tas75
Nov 19 at 20:12
@Phil H, thanks for confirming the books answer
– tas75
Nov 19 at 20:12
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
Edit: I had the resultant of the strings at the wrong angle. Now corrected I get the same result as the book.
This should be a comment but a diagram won't post to the comments. Take a look and see if you agree.
answered Nov 19 at 15:56
Phil H
3,8882312
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Edit: I had the resultant of the strings at the wrong angle. Now corrected I get the same result as the book.
This should be a comment but a diagram won't post to the comments. Take a look and see if you agree.
answered Nov 19 at 15:56
Phil H
3,8882312
add a comment |
up vote
0
down vote
accepted
Edit: I had the resultant of the strings at the wrong angle. Now corrected I get the same result as the book.
This should be a comment but a diagram won't post to the comments. Take a look and see if you agree.
answered Nov 19 at 15:56
Phil H
3,8882312
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Edit: I had the resultant of the strings at the wrong angle. Now corrected I get the same result as the book.
This should be a comment but a diagram won't post to the comments. Take a look and see if you agree.
answered Nov 19 at 15:56
Phil H
3,8882312
Edit: I had the resultant of the strings at the wrong angle. Now corrected I get the same result as the book.
This should be a comment but a diagram won't post to the comments. Take a look and see if you agree.
answered Nov 19 at 15:56
Phil H
3,8882312
edited Nov 19 at 19:23
answered Nov 19 at 15:56
Phil H
3,8882312
answered Nov 19 at 15:56
Phil H
3,8882312
answered Nov 19 at 15:56
Phil H
3,8882312
3,8882312
add a comment |
add a comment |
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3004817%2fhorizontal-angular-rotation-speed%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Could you add a picture or a more detailed description. I am especially stuck on this sentence "The bead moves in a horizontal circle about the line AB".
– maxmilgram
Nov 19 at 11:49
@maxmilgram, I hope that helps
– tas75
Nov 19 at 12:04
I don't get your answer or the answer in the book. I'll post my free body diagram in the answer because it won't post in the comments.
– Phil H
Nov 19 at 15:52
See revised answer, same as the book.
– Phil H
Nov 19 at 19:24
@Phil H, thanks for confirming the books answer
– tas75
Nov 19 at 20:12