Figuring magnitude and phase response
up vote
0
down vote
favorite
I've got a linear time-invariant system $$y[n]=frac{8}{9}y[n-1]+x[n]$$
which i transformed into a transfer function $$Y(z)=frac{8}{9}Y(z)*z^{-1}+X(z) =>frac{Y(z)}{X(z)}=frac{1}{1-frac{8}{9}*z^{-1}}=frac{z}{z-frac{8}{9}}$$
The pole is positive, which would make the system stabile. However, i am having some trouble getting the magnitude/phase responses |H(ω)| and θ(ω). How should i proceed with the system to figure these out? I've read about using the substitution for z as$$Y(z)=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}$$
or even continue to transform the exponentials to their cosine + sin forms, but i am not sure how i should proceed with them. I've thought of something like this:
$$|H(ω)|=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}=frac{sqrt{cos(ω)^2+sin(ω)^2}}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}=frac{1}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}$$
As an addition, how would the system change if i would to swap x[n] with a sin or a cosine of some value? I assume it would be the same path towards the responses but with different values.
signal-processing z-transform
add a comment |
up vote
0
down vote
favorite
I've got a linear time-invariant system $$y[n]=frac{8}{9}y[n-1]+x[n]$$
which i transformed into a transfer function $$Y(z)=frac{8}{9}Y(z)*z^{-1}+X(z) =>frac{Y(z)}{X(z)}=frac{1}{1-frac{8}{9}*z^{-1}}=frac{z}{z-frac{8}{9}}$$
The pole is positive, which would make the system stabile. However, i am having some trouble getting the magnitude/phase responses |H(ω)| and θ(ω). How should i proceed with the system to figure these out? I've read about using the substitution for z as$$Y(z)=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}$$
or even continue to transform the exponentials to their cosine + sin forms, but i am not sure how i should proceed with them. I've thought of something like this:
$$|H(ω)|=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}=frac{sqrt{cos(ω)^2+sin(ω)^2}}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}=frac{1}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}$$
As an addition, how would the system change if i would to swap x[n] with a sin or a cosine of some value? I assume it would be the same path towards the responses but with different values.
signal-processing z-transform
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've got a linear time-invariant system $$y[n]=frac{8}{9}y[n-1]+x[n]$$
which i transformed into a transfer function $$Y(z)=frac{8}{9}Y(z)*z^{-1}+X(z) =>frac{Y(z)}{X(z)}=frac{1}{1-frac{8}{9}*z^{-1}}=frac{z}{z-frac{8}{9}}$$
The pole is positive, which would make the system stabile. However, i am having some trouble getting the magnitude/phase responses |H(ω)| and θ(ω). How should i proceed with the system to figure these out? I've read about using the substitution for z as$$Y(z)=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}$$
or even continue to transform the exponentials to their cosine + sin forms, but i am not sure how i should proceed with them. I've thought of something like this:
$$|H(ω)|=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}=frac{sqrt{cos(ω)^2+sin(ω)^2}}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}=frac{1}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}$$
As an addition, how would the system change if i would to swap x[n] with a sin or a cosine of some value? I assume it would be the same path towards the responses but with different values.
signal-processing z-transform
I've got a linear time-invariant system $$y[n]=frac{8}{9}y[n-1]+x[n]$$
which i transformed into a transfer function $$Y(z)=frac{8}{9}Y(z)*z^{-1}+X(z) =>frac{Y(z)}{X(z)}=frac{1}{1-frac{8}{9}*z^{-1}}=frac{z}{z-frac{8}{9}}$$
The pole is positive, which would make the system stabile. However, i am having some trouble getting the magnitude/phase responses |H(ω)| and θ(ω). How should i proceed with the system to figure these out? I've read about using the substitution for z as$$Y(z)=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}$$
or even continue to transform the exponentials to their cosine + sin forms, but i am not sure how i should proceed with them. I've thought of something like this:
$$|H(ω)|=frac{z}{z-frac{8}{9}}=frac{e^{iw}}{e^{iw}-frac{8}{9}}=frac{sqrt{cos(ω)^2+sin(ω)^2}}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}=frac{1}{sqrt{(cos(ω)-frac{8}{9})^2+sin(ω)^2}}$$
As an addition, how would the system change if i would to swap x[n] with a sin or a cosine of some value? I assume it would be the same path towards the responses but with different values.
signal-processing z-transform
signal-processing z-transform
asked Nov 16 at 11:57
TootsieRoll
113
113
add a comment |
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3001052%2ffiguring-magnitude-and-phase-response%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown