Fourier transform of “hyperbolically distorted” Gaussian / Bessel-type integrals











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Dear Math enthusiasts,



I'm trying to see if I can find an analytical expression for the Fourier transform of a Gaussian pulse $p(tau) = {rm e}^{-Btau^2}$ that is distorted by a hyperbolic distortion of the form $tau(t) = sqrt{t^2+a^2}-a$. What I mean is I look at the function $p(tau(t))$ and I try to transform this time $t$ to frequency.



This gives a Fourier integral of the following form $$G(omega) = int_{-infty}^infty {rm e}^{-Bleft(sqrt{t^2+a^2}-aright)^2} {rm e}^{-jmath omega t} {rm d}t.$$



Substituting the square-root doesn't help much, since it appears back when resubstituting $t$. I therefore tried to substitute $t = a sinh(x)$ instead. Assuming I didn't make a stupid mistake, this gives $$G(omega) = aint_{-infty}^infty {rm e}^{-Bleft(a cosh(x)-aright)^2} {rm e}^{-jmath omega a sinh(x)} cosh(x) {rm d}x.$$



From [*], eqn (2.3) I know that $int_{0}^infty {rm e}^{a cosh(x)} cosh(x) {rm d}x = K_0(a)$ where $K_0(a)$ is the modified Bessel function of the second kind. As the integrand is symmetric, it should be no problem to extend this to $(-infty,infty)$. But still I'm not sure this is enough to solve the integral. Mathematica has refused to give me anything, but it's possible I used it in a wrong way. I tried manipulating the exponent to bring everything to one hyperbolic trig function, but I failed.



Any hints how I can proceed?










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    up vote
    1
    down vote

    favorite












    Dear Math enthusiasts,



    I'm trying to see if I can find an analytical expression for the Fourier transform of a Gaussian pulse $p(tau) = {rm e}^{-Btau^2}$ that is distorted by a hyperbolic distortion of the form $tau(t) = sqrt{t^2+a^2}-a$. What I mean is I look at the function $p(tau(t))$ and I try to transform this time $t$ to frequency.



    This gives a Fourier integral of the following form $$G(omega) = int_{-infty}^infty {rm e}^{-Bleft(sqrt{t^2+a^2}-aright)^2} {rm e}^{-jmath omega t} {rm d}t.$$



    Substituting the square-root doesn't help much, since it appears back when resubstituting $t$. I therefore tried to substitute $t = a sinh(x)$ instead. Assuming I didn't make a stupid mistake, this gives $$G(omega) = aint_{-infty}^infty {rm e}^{-Bleft(a cosh(x)-aright)^2} {rm e}^{-jmath omega a sinh(x)} cosh(x) {rm d}x.$$



    From [*], eqn (2.3) I know that $int_{0}^infty {rm e}^{a cosh(x)} cosh(x) {rm d}x = K_0(a)$ where $K_0(a)$ is the modified Bessel function of the second kind. As the integrand is symmetric, it should be no problem to extend this to $(-infty,infty)$. But still I'm not sure this is enough to solve the integral. Mathematica has refused to give me anything, but it's possible I used it in a wrong way. I tried manipulating the exponent to bring everything to one hyperbolic trig function, but I failed.



    Any hints how I can proceed?










    share|cite|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Dear Math enthusiasts,



      I'm trying to see if I can find an analytical expression for the Fourier transform of a Gaussian pulse $p(tau) = {rm e}^{-Btau^2}$ that is distorted by a hyperbolic distortion of the form $tau(t) = sqrt{t^2+a^2}-a$. What I mean is I look at the function $p(tau(t))$ and I try to transform this time $t$ to frequency.



      This gives a Fourier integral of the following form $$G(omega) = int_{-infty}^infty {rm e}^{-Bleft(sqrt{t^2+a^2}-aright)^2} {rm e}^{-jmath omega t} {rm d}t.$$



      Substituting the square-root doesn't help much, since it appears back when resubstituting $t$. I therefore tried to substitute $t = a sinh(x)$ instead. Assuming I didn't make a stupid mistake, this gives $$G(omega) = aint_{-infty}^infty {rm e}^{-Bleft(a cosh(x)-aright)^2} {rm e}^{-jmath omega a sinh(x)} cosh(x) {rm d}x.$$



      From [*], eqn (2.3) I know that $int_{0}^infty {rm e}^{a cosh(x)} cosh(x) {rm d}x = K_0(a)$ where $K_0(a)$ is the modified Bessel function of the second kind. As the integrand is symmetric, it should be no problem to extend this to $(-infty,infty)$. But still I'm not sure this is enough to solve the integral. Mathematica has refused to give me anything, but it's possible I used it in a wrong way. I tried manipulating the exponent to bring everything to one hyperbolic trig function, but I failed.



      Any hints how I can proceed?










      share|cite|improve this question













      Dear Math enthusiasts,



      I'm trying to see if I can find an analytical expression for the Fourier transform of a Gaussian pulse $p(tau) = {rm e}^{-Btau^2}$ that is distorted by a hyperbolic distortion of the form $tau(t) = sqrt{t^2+a^2}-a$. What I mean is I look at the function $p(tau(t))$ and I try to transform this time $t$ to frequency.



      This gives a Fourier integral of the following form $$G(omega) = int_{-infty}^infty {rm e}^{-Bleft(sqrt{t^2+a^2}-aright)^2} {rm e}^{-jmath omega t} {rm d}t.$$



      Substituting the square-root doesn't help much, since it appears back when resubstituting $t$. I therefore tried to substitute $t = a sinh(x)$ instead. Assuming I didn't make a stupid mistake, this gives $$G(omega) = aint_{-infty}^infty {rm e}^{-Bleft(a cosh(x)-aright)^2} {rm e}^{-jmath omega a sinh(x)} cosh(x) {rm d}x.$$



      From [*], eqn (2.3) I know that $int_{0}^infty {rm e}^{a cosh(x)} cosh(x) {rm d}x = K_0(a)$ where $K_0(a)$ is the modified Bessel function of the second kind. As the integrand is symmetric, it should be no problem to extend this to $(-infty,infty)$. But still I'm not sure this is enough to solve the integral. Mathematica has refused to give me anything, but it's possible I used it in a wrong way. I tried manipulating the exponent to bring everything to one hyperbolic trig function, but I failed.



      Any hints how I can proceed?







      integration fourier-transform bessel-functions






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      asked Nov 16 at 12:30









      Florian

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