Rank of differential at a given point is a local minimum
up vote
0
down vote
favorite
I have the following exercise I`m struggling with :
Let $fin C^1(mathbb{R}^n,mathbb{R}^m)$, and $a in mathbb{R}^n$, I need to show that $rk(D_f(x))geq rk(D_f(a))$ for some neighbourhood of $a$.
I first tried looking at non-trivial linear combinations of $nabla f_i(x)$ but it didnt get me anywhere.
I also tried defining $Ker_x = {vin mathbb{R}^n | D_f(x)v=0}$, and tried showing $Ker_xsubset Ker_a$:
Let $xin B(a,delta$), and $vin Ker_x$,
$$|D_f(a)v|=|D_f(a)v-D_f(x)v+D_f(x)v|leq|D_f(a)v-D_f(x)v| +|D_f(x)v|=|D_f(a)v-D_f(x)v|leqepsilon|v|$$
Where the last inequality is from the continuity of $D_f(x)$.The problem is however, $delta$ is not fixed if I want $|D_f(a)v|=0$ so I can`t see how to find a neighbourhood of $a$ out of these inequalities.
I`ll be glad if anyone can either help me fix my solution or suggest another way of approching this problem.
calculus real-analysis
add a comment |
up vote
0
down vote
favorite
I have the following exercise I`m struggling with :
Let $fin C^1(mathbb{R}^n,mathbb{R}^m)$, and $a in mathbb{R}^n$, I need to show that $rk(D_f(x))geq rk(D_f(a))$ for some neighbourhood of $a$.
I first tried looking at non-trivial linear combinations of $nabla f_i(x)$ but it didnt get me anywhere.
I also tried defining $Ker_x = {vin mathbb{R}^n | D_f(x)v=0}$, and tried showing $Ker_xsubset Ker_a$:
Let $xin B(a,delta$), and $vin Ker_x$,
$$|D_f(a)v|=|D_f(a)v-D_f(x)v+D_f(x)v|leq|D_f(a)v-D_f(x)v| +|D_f(x)v|=|D_f(a)v-D_f(x)v|leqepsilon|v|$$
Where the last inequality is from the continuity of $D_f(x)$.The problem is however, $delta$ is not fixed if I want $|D_f(a)v|=0$ so I can`t see how to find a neighbourhood of $a$ out of these inequalities.
I`ll be glad if anyone can either help me fix my solution or suggest another way of approching this problem.
calculus real-analysis
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have the following exercise I`m struggling with :
Let $fin C^1(mathbb{R}^n,mathbb{R}^m)$, and $a in mathbb{R}^n$, I need to show that $rk(D_f(x))geq rk(D_f(a))$ for some neighbourhood of $a$.
I first tried looking at non-trivial linear combinations of $nabla f_i(x)$ but it didnt get me anywhere.
I also tried defining $Ker_x = {vin mathbb{R}^n | D_f(x)v=0}$, and tried showing $Ker_xsubset Ker_a$:
Let $xin B(a,delta$), and $vin Ker_x$,
$$|D_f(a)v|=|D_f(a)v-D_f(x)v+D_f(x)v|leq|D_f(a)v-D_f(x)v| +|D_f(x)v|=|D_f(a)v-D_f(x)v|leqepsilon|v|$$
Where the last inequality is from the continuity of $D_f(x)$.The problem is however, $delta$ is not fixed if I want $|D_f(a)v|=0$ so I can`t see how to find a neighbourhood of $a$ out of these inequalities.
I`ll be glad if anyone can either help me fix my solution or suggest another way of approching this problem.
calculus real-analysis
I have the following exercise I`m struggling with :
Let $fin C^1(mathbb{R}^n,mathbb{R}^m)$, and $a in mathbb{R}^n$, I need to show that $rk(D_f(x))geq rk(D_f(a))$ for some neighbourhood of $a$.
I first tried looking at non-trivial linear combinations of $nabla f_i(x)$ but it didnt get me anywhere.
I also tried defining $Ker_x = {vin mathbb{R}^n | D_f(x)v=0}$, and tried showing $Ker_xsubset Ker_a$:
Let $xin B(a,delta$), and $vin Ker_x$,
$$|D_f(a)v|=|D_f(a)v-D_f(x)v+D_f(x)v|leq|D_f(a)v-D_f(x)v| +|D_f(x)v|=|D_f(a)v-D_f(x)v|leqepsilon|v|$$
Where the last inequality is from the continuity of $D_f(x)$.The problem is however, $delta$ is not fixed if I want $|D_f(a)v|=0$ so I can`t see how to find a neighbourhood of $a$ out of these inequalities.
I`ll be glad if anyone can either help me fix my solution or suggest another way of approching this problem.
calculus real-analysis
calculus real-analysis
asked Nov 16 at 11:57
Sar
48811
48811
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
If $rk(D_f(a))=p$, this is equivalent to saying that there exists a $ptimes p$-minor $A_p(x)$ (submatrix) of $D_f(x)$ such that $g(a)=det(A_p(a))neq 0$, since $f$ is $C^1$, $D_f$ and henceforth $g$ are continuous,.Let $I$ be an open interval containing $det(A_p(a)$, but not $0$, $g^{-1}(I)$ is an open subset containing $a$.
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
If $rk(D_f(a))=p$, this is equivalent to saying that there exists a $ptimes p$-minor $A_p(x)$ (submatrix) of $D_f(x)$ such that $g(a)=det(A_p(a))neq 0$, since $f$ is $C^1$, $D_f$ and henceforth $g$ are continuous,.Let $I$ be an open interval containing $det(A_p(a)$, but not $0$, $g^{-1}(I)$ is an open subset containing $a$.
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
add a comment |
up vote
1
down vote
accepted
If $rk(D_f(a))=p$, this is equivalent to saying that there exists a $ptimes p$-minor $A_p(x)$ (submatrix) of $D_f(x)$ such that $g(a)=det(A_p(a))neq 0$, since $f$ is $C^1$, $D_f$ and henceforth $g$ are continuous,.Let $I$ be an open interval containing $det(A_p(a)$, but not $0$, $g^{-1}(I)$ is an open subset containing $a$.
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
If $rk(D_f(a))=p$, this is equivalent to saying that there exists a $ptimes p$-minor $A_p(x)$ (submatrix) of $D_f(x)$ such that $g(a)=det(A_p(a))neq 0$, since $f$ is $C^1$, $D_f$ and henceforth $g$ are continuous,.Let $I$ be an open interval containing $det(A_p(a)$, but not $0$, $g^{-1}(I)$ is an open subset containing $a$.
If $rk(D_f(a))=p$, this is equivalent to saying that there exists a $ptimes p$-minor $A_p(x)$ (submatrix) of $D_f(x)$ such that $g(a)=det(A_p(a))neq 0$, since $f$ is $C^1$, $D_f$ and henceforth $g$ are continuous,.Let $I$ be an open interval containing $det(A_p(a)$, but not $0$, $g^{-1}(I)$ is an open subset containing $a$.
answered Nov 16 at 13:09
Tsemo Aristide
54.3k11344
54.3k11344
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
add a comment |
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
That's just a great idea. Thank you !
– Sar
Nov 16 at 14:35
add a comment |
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3001053%2frank-of-differential-at-a-given-point-is-a-local-minimum%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown