Congruences and probability












0














Suppose that $6x equiv 10y pmod{14}$. Which of the following are guaranteed to be true?



(a) $3x equiv 5y pmod{14}$: True



(b) $6x equiv 10y pmod{7}$: True



(c) $3x equiv 5y pmod{7}$: True



(d) $6x equiv 10y pmod{28}$: False



Am I right?










share|cite|improve this question




















  • 2




    any reasoning for reaching the conclusion?
    – Siong Thye Goh
    Nov 28 '18 at 3:10






  • 2




    $b,c,d$ have correct answers. You need to check if $(a)$ is written correctly, because $3x-5y$ is half of $6x-10y$, so the latter being a multiple of $14$ would not imply that half of it is a multiple of $14$,right?
    – астон вілла олоф мэллбэрг
    Nov 28 '18 at 3:29












  • Please explain your reasoning rather than simply posting proposed answers. That might help you discover any errors you have made. It also helps us identify any errors you may have made. Also, please read this tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Nov 28 '18 at 10:37










  • note that $6cdot 7equiv 10cdot 0 pmod{14}$ does not imply $3cdot 7 equiv 5cdot 0 pmod{14}$, so $a)$ is false.
    – farruhota
    Nov 28 '18 at 14:14










  • Thank you for help!
    – Laura1999
    Nov 28 '18 at 23:27
















0














Suppose that $6x equiv 10y pmod{14}$. Which of the following are guaranteed to be true?



(a) $3x equiv 5y pmod{14}$: True



(b) $6x equiv 10y pmod{7}$: True



(c) $3x equiv 5y pmod{7}$: True



(d) $6x equiv 10y pmod{28}$: False



Am I right?










share|cite|improve this question




















  • 2




    any reasoning for reaching the conclusion?
    – Siong Thye Goh
    Nov 28 '18 at 3:10






  • 2




    $b,c,d$ have correct answers. You need to check if $(a)$ is written correctly, because $3x-5y$ is half of $6x-10y$, so the latter being a multiple of $14$ would not imply that half of it is a multiple of $14$,right?
    – астон вілла олоф мэллбэрг
    Nov 28 '18 at 3:29












  • Please explain your reasoning rather than simply posting proposed answers. That might help you discover any errors you have made. It also helps us identify any errors you may have made. Also, please read this tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Nov 28 '18 at 10:37










  • note that $6cdot 7equiv 10cdot 0 pmod{14}$ does not imply $3cdot 7 equiv 5cdot 0 pmod{14}$, so $a)$ is false.
    – farruhota
    Nov 28 '18 at 14:14










  • Thank you for help!
    – Laura1999
    Nov 28 '18 at 23:27














0












0








0







Suppose that $6x equiv 10y pmod{14}$. Which of the following are guaranteed to be true?



(a) $3x equiv 5y pmod{14}$: True



(b) $6x equiv 10y pmod{7}$: True



(c) $3x equiv 5y pmod{7}$: True



(d) $6x equiv 10y pmod{28}$: False



Am I right?










share|cite|improve this question















Suppose that $6x equiv 10y pmod{14}$. Which of the following are guaranteed to be true?



(a) $3x equiv 5y pmod{14}$: True



(b) $6x equiv 10y pmod{7}$: True



(c) $3x equiv 5y pmod{7}$: True



(d) $6x equiv 10y pmod{28}$: False



Am I right?







elementary-number-theory discrete-mathematics modular-arithmetic






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 28 '18 at 10:35









N. F. Taussig

43.6k93355




43.6k93355










asked Nov 28 '18 at 3:09









Laura1999

202




202








  • 2




    any reasoning for reaching the conclusion?
    – Siong Thye Goh
    Nov 28 '18 at 3:10






  • 2




    $b,c,d$ have correct answers. You need to check if $(a)$ is written correctly, because $3x-5y$ is half of $6x-10y$, so the latter being a multiple of $14$ would not imply that half of it is a multiple of $14$,right?
    – астон вілла олоф мэллбэрг
    Nov 28 '18 at 3:29












  • Please explain your reasoning rather than simply posting proposed answers. That might help you discover any errors you have made. It also helps us identify any errors you may have made. Also, please read this tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Nov 28 '18 at 10:37










  • note that $6cdot 7equiv 10cdot 0 pmod{14}$ does not imply $3cdot 7 equiv 5cdot 0 pmod{14}$, so $a)$ is false.
    – farruhota
    Nov 28 '18 at 14:14










  • Thank you for help!
    – Laura1999
    Nov 28 '18 at 23:27














  • 2




    any reasoning for reaching the conclusion?
    – Siong Thye Goh
    Nov 28 '18 at 3:10






  • 2




    $b,c,d$ have correct answers. You need to check if $(a)$ is written correctly, because $3x-5y$ is half of $6x-10y$, so the latter being a multiple of $14$ would not imply that half of it is a multiple of $14$,right?
    – астон вілла олоф мэллбэрг
    Nov 28 '18 at 3:29












  • Please explain your reasoning rather than simply posting proposed answers. That might help you discover any errors you have made. It also helps us identify any errors you may have made. Also, please read this tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Nov 28 '18 at 10:37










  • note that $6cdot 7equiv 10cdot 0 pmod{14}$ does not imply $3cdot 7 equiv 5cdot 0 pmod{14}$, so $a)$ is false.
    – farruhota
    Nov 28 '18 at 14:14










  • Thank you for help!
    – Laura1999
    Nov 28 '18 at 23:27








2




2




any reasoning for reaching the conclusion?
– Siong Thye Goh
Nov 28 '18 at 3:10




any reasoning for reaching the conclusion?
– Siong Thye Goh
Nov 28 '18 at 3:10




2




2




$b,c,d$ have correct answers. You need to check if $(a)$ is written correctly, because $3x-5y$ is half of $6x-10y$, so the latter being a multiple of $14$ would not imply that half of it is a multiple of $14$,right?
– астон вілла олоф мэллбэрг
Nov 28 '18 at 3:29






$b,c,d$ have correct answers. You need to check if $(a)$ is written correctly, because $3x-5y$ is half of $6x-10y$, so the latter being a multiple of $14$ would not imply that half of it is a multiple of $14$,right?
– астон вілла олоф мэллбэрг
Nov 28 '18 at 3:29














Please explain your reasoning rather than simply posting proposed answers. That might help you discover any errors you have made. It also helps us identify any errors you may have made. Also, please read this tutorial, which explains how to typeset mathematics on this site.
– N. F. Taussig
Nov 28 '18 at 10:37




Please explain your reasoning rather than simply posting proposed answers. That might help you discover any errors you have made. It also helps us identify any errors you may have made. Also, please read this tutorial, which explains how to typeset mathematics on this site.
– N. F. Taussig
Nov 28 '18 at 10:37












note that $6cdot 7equiv 10cdot 0 pmod{14}$ does not imply $3cdot 7 equiv 5cdot 0 pmod{14}$, so $a)$ is false.
– farruhota
Nov 28 '18 at 14:14




note that $6cdot 7equiv 10cdot 0 pmod{14}$ does not imply $3cdot 7 equiv 5cdot 0 pmod{14}$, so $a)$ is false.
– farruhota
Nov 28 '18 at 14:14












Thank you for help!
– Laura1999
Nov 28 '18 at 23:27




Thank you for help!
– Laura1999
Nov 28 '18 at 23:27










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