Reverse direction of parametric equation
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For the graph $y = sqrt{x}$ the normal parametric equations would $x = t^2$ and $y = |t|$. However, the direction for that graph would be going from infinity to zero when $t leq 0$ and zero to infinity when $t geq 0$. I want that graph to go from zero to infinity when $tleq 0$ and infinity to zero when $t geq 0$. How do I reverse the direction of the parametric equations $x = t^2$ and $y = |t|$?
parametric
edited Jul 31 '13 at 23:21
Sigur
4,50811736
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
$endgroup$
add a comment |
$begingroup$
For the graph $y = sqrt{x}$ the normal parametric equations would $x = t^2$ and $y = |t|$. However, the direction for that graph would be going from infinity to zero when $t leq 0$ and zero to infinity when $t geq 0$. I want that graph to go from zero to infinity when $tleq 0$ and infinity to zero when $t geq 0$. How do I reverse the direction of the parametric equations $x = t^2$ and $y = |t|$?
parametric
edited Jul 31 '13 at 23:21
Sigur
4,50811736
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
$endgroup$
$begingroup$
"However, the direction for that graph would be going from infinity to zero when $tle0$". How do you figure that? $lim_{tto0}y=0$, and $lim_{tto-infty^+}y=infty$.
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– Ataraxia
Jul 31 '13 at 23:03
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If t = -10, then x = 100 and y = 10, but when t = 0, x = 0 and y = 0.
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– dirtysocks45
Jul 31 '13 at 23:09
$begingroup$
So in other words, you want $y=infty$ when $t=0$?
$endgroup$
– Ataraxia
Jul 31 '13 at 23:22
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I don't think you expressed your idea the right way.
$endgroup$
– Yves Daoust
May 30 '16 at 22:41
add a comment |
$begingroup$
For the graph $y = sqrt{x}$ the normal parametric equations would $x = t^2$ and $y = |t|$. However, the direction for that graph would be going from infinity to zero when $t leq 0$ and zero to infinity when $t geq 0$. I want that graph to go from zero to infinity when $tleq 0$ and infinity to zero when $t geq 0$. How do I reverse the direction of the parametric equations $x = t^2$ and $y = |t|$?
parametric
edited Jul 31 '13 at 23:21
Sigur
4,50811736
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
$endgroup$
For the graph $y = sqrt{x}$ the normal parametric equations would $x = t^2$ and $y = |t|$. However, the direction for that graph would be going from infinity to zero when $t leq 0$ and zero to infinity when $t geq 0$. I want that graph to go from zero to infinity when $tleq 0$ and infinity to zero when $t geq 0$. How do I reverse the direction of the parametric equations $x = t^2$ and $y = |t|$?
parametric
parametric
edited Jul 31 '13 at 23:21
Sigur
4,50811736
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
edited Jul 31 '13 at 23:21
Sigur
4,50811736
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
edited Jul 31 '13 at 23:21
Sigur
4,50811736
edited Jul 31 '13 at 23:21
Sigur
4,50811736
edited Jul 31 '13 at 23:21
Sigur
4,50811736
4,50811736
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
asked Jul 31 '13 at 22:56
dirtysocks45dirtysocks45
368212
368212
$begingroup$
"However, the direction for that graph would be going from infinity to zero when $tle0$". How do you figure that? $lim_{tto0}y=0$, and $lim_{tto-infty^+}y=infty$.
$endgroup$
– Ataraxia
Jul 31 '13 at 23:03
$begingroup$
If t = -10, then x = 100 and y = 10, but when t = 0, x = 0 and y = 0.
$endgroup$
– dirtysocks45
Jul 31 '13 at 23:09
$begingroup$
So in other words, you want $y=infty$ when $t=0$?
$endgroup$
– Ataraxia
Jul 31 '13 at 23:22
$begingroup$
I don't think you expressed your idea the right way.
$endgroup$
– Yves Daoust
May 30 '16 at 22:41
add a comment |
$begingroup$
"However, the direction for that graph would be going from infinity to zero when $tle0$". How do you figure that? $lim_{tto0}y=0$, and $lim_{tto-infty^+}y=infty$.
$endgroup$
– Ataraxia
Jul 31 '13 at 23:03
$begingroup$
If t = -10, then x = 100 and y = 10, but when t = 0, x = 0 and y = 0.
$endgroup$
– dirtysocks45
Jul 31 '13 at 23:09
$begingroup$
So in other words, you want $y=infty$ when $t=0$?
$endgroup$
– Ataraxia
Jul 31 '13 at 23:22
$begingroup$
I don't think you expressed your idea the right way.
$endgroup$
– Yves Daoust
May 30 '16 at 22:41
$begingroup$
"However, the direction for that graph would be going from infinity to zero when $tle0$". How do you figure that? $lim_{tto0}y=0$, and $lim_{tto-infty^+}y=infty$.
$endgroup$
– Ataraxia
Jul 31 '13 at 23:03
$begingroup$
"However, the direction for that graph would be going from infinity to zero when $tle0$". How do you figure that? $lim_{tto0}y=0$, and $lim_{tto-infty^+}y=infty$.
$endgroup$
– Ataraxia
Jul 31 '13 at 23:03
$begingroup$
If t = -10, then x = 100 and y = 10, but when t = 0, x = 0 and y = 0.
$endgroup$
– dirtysocks45
Jul 31 '13 at 23:09
$begingroup$
If t = -10, then x = 100 and y = 10, but when t = 0, x = 0 and y = 0.
$endgroup$
– dirtysocks45
Jul 31 '13 at 23:09
$begingroup$
So in other words, you want $y=infty$ when $t=0$?
$endgroup$
– Ataraxia
Jul 31 '13 at 23:22
$begingroup$
So in other words, you want $y=infty$ when $t=0$?
$endgroup$
– Ataraxia
Jul 31 '13 at 23:22
$begingroup$
I don't think you expressed your idea the right way.
$endgroup$
– Yves Daoust
May 30 '16 at 22:41
$begingroup$
I don't think you expressed your idea the right way.
$endgroup$
– Yves Daoust
May 30 '16 at 22:41
add a comment |
1 Answer
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$begingroup$
Reciprocals might meet your needs, so try $x = t^{-2}$ and $y = left|t^{-1}right|$ and consider what this might mean (if anything) for $t=0$.
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
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add a comment |
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1 Answer
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$begingroup$
Reciprocals might meet your needs, so try $x = t^{-2}$ and $y = left|t^{-1}right|$ and consider what this might mean (if anything) for $t=0$.
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
$endgroup$
add a comment |
$begingroup$
Reciprocals might meet your needs, so try $x = t^{-2}$ and $y = left|t^{-1}right|$ and consider what this might mean (if anything) for $t=0$.
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
$endgroup$
add a comment |
$begingroup$
Reciprocals might meet your needs, so try $x = t^{-2}$ and $y = left|t^{-1}right|$ and consider what this might mean (if anything) for $t=0$.
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
$endgroup$
Reciprocals might meet your needs, so try $x = t^{-2}$ and $y = left|t^{-1}right|$ and consider what this might mean (if anything) for $t=0$.
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
answered Jul 31 '13 at 23:46
HenryHenry
100k480167
100k480167
add a comment |
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$begingroup$
"However, the direction for that graph would be going from infinity to zero when $tle0$". How do you figure that? $lim_{tto0}y=0$, and $lim_{tto-infty^+}y=infty$.
$endgroup$
– Ataraxia
Jul 31 '13 at 23:03
$begingroup$
If t = -10, then x = 100 and y = 10, but when t = 0, x = 0 and y = 0.
$endgroup$
– dirtysocks45
Jul 31 '13 at 23:09
$begingroup$
So in other words, you want $y=infty$ when $t=0$?
$endgroup$
– Ataraxia
Jul 31 '13 at 23:22
$begingroup$
I don't think you expressed your idea the right way.
$endgroup$
– Yves Daoust
May 30 '16 at 22:41