How to guess the end of pushdown automata by emptying the stack?
$begingroup$
Let language $L={sigma_1w_1csigma_2w_2c...sigma_nw_nc}$ where:
$$
1le n\
sigma_iin {a,b}\
w_iin {a,b}^+\
exists i:ile|w_i|
$$
and at least one condition from the two conditions below holds:
the first $i$ letters of $w_i$ form a different word from $(sigma_1sigma_2...sigma_i)^R$ OR $|w_i|=n$.
Build a pushdown automaton which receives $L$ by emptying its stack.
The solution of these two conditions separately is here: https://imgur.com/a/T9PiPgT.
As far as I understand in the automata for both condition 1 and condion 2 ($|w_i|=n$) essentially:
- We build an automaton which simply describes reading $sigma, w_i, c$ first.
- Then we guess the $w_i$ which is according to condition 1 or 2.
- Then we read the $sigma, c$ surrounding the guessed $w_i$ and the $w_i$ itself.
I'm new to pushdown automata, but it looks like a lot of automata could be solved in such a generic way:
- Read the words according to some logic described in the problem.
- guess some "good" word (by using $epsilon$ connection) and delete it from the stack.
Am I missing something?
Also I don't understand why we need $2$ cases in the solution for each condition. The solutions for each condition look almost identical.
Lastly, I don't understand why in the automaton for the condition $1$ in state $q_5$ we need to read the end of $w_i$ first, then read the "good" $w_i$. Why can't we read the "good" $w_i$ straight after the guess?
proof-explanation formal-languages automata
$endgroup$
add a comment |
$begingroup$
Let language $L={sigma_1w_1csigma_2w_2c...sigma_nw_nc}$ where:
$$
1le n\
sigma_iin {a,b}\
w_iin {a,b}^+\
exists i:ile|w_i|
$$
and at least one condition from the two conditions below holds:
the first $i$ letters of $w_i$ form a different word from $(sigma_1sigma_2...sigma_i)^R$ OR $|w_i|=n$.
Build a pushdown automaton which receives $L$ by emptying its stack.
The solution of these two conditions separately is here: https://imgur.com/a/T9PiPgT.
As far as I understand in the automata for both condition 1 and condion 2 ($|w_i|=n$) essentially:
- We build an automaton which simply describes reading $sigma, w_i, c$ first.
- Then we guess the $w_i$ which is according to condition 1 or 2.
- Then we read the $sigma, c$ surrounding the guessed $w_i$ and the $w_i$ itself.
I'm new to pushdown automata, but it looks like a lot of automata could be solved in such a generic way:
- Read the words according to some logic described in the problem.
- guess some "good" word (by using $epsilon$ connection) and delete it from the stack.
Am I missing something?
Also I don't understand why we need $2$ cases in the solution for each condition. The solutions for each condition look almost identical.
Lastly, I don't understand why in the automaton for the condition $1$ in state $q_5$ we need to read the end of $w_i$ first, then read the "good" $w_i$. Why can't we read the "good" $w_i$ straight after the guess?
proof-explanation formal-languages automata
$endgroup$
add a comment |
$begingroup$
Let language $L={sigma_1w_1csigma_2w_2c...sigma_nw_nc}$ where:
$$
1le n\
sigma_iin {a,b}\
w_iin {a,b}^+\
exists i:ile|w_i|
$$
and at least one condition from the two conditions below holds:
the first $i$ letters of $w_i$ form a different word from $(sigma_1sigma_2...sigma_i)^R$ OR $|w_i|=n$.
Build a pushdown automaton which receives $L$ by emptying its stack.
The solution of these two conditions separately is here: https://imgur.com/a/T9PiPgT.
As far as I understand in the automata for both condition 1 and condion 2 ($|w_i|=n$) essentially:
- We build an automaton which simply describes reading $sigma, w_i, c$ first.
- Then we guess the $w_i$ which is according to condition 1 or 2.
- Then we read the $sigma, c$ surrounding the guessed $w_i$ and the $w_i$ itself.
I'm new to pushdown automata, but it looks like a lot of automata could be solved in such a generic way:
- Read the words according to some logic described in the problem.
- guess some "good" word (by using $epsilon$ connection) and delete it from the stack.
Am I missing something?
Also I don't understand why we need $2$ cases in the solution for each condition. The solutions for each condition look almost identical.
Lastly, I don't understand why in the automaton for the condition $1$ in state $q_5$ we need to read the end of $w_i$ first, then read the "good" $w_i$. Why can't we read the "good" $w_i$ straight after the guess?
proof-explanation formal-languages automata
$endgroup$
Let language $L={sigma_1w_1csigma_2w_2c...sigma_nw_nc}$ where:
$$
1le n\
sigma_iin {a,b}\
w_iin {a,b}^+\
exists i:ile|w_i|
$$
and at least one condition from the two conditions below holds:
the first $i$ letters of $w_i$ form a different word from $(sigma_1sigma_2...sigma_i)^R$ OR $|w_i|=n$.
Build a pushdown automaton which receives $L$ by emptying its stack.
The solution of these two conditions separately is here: https://imgur.com/a/T9PiPgT.
As far as I understand in the automata for both condition 1 and condion 2 ($|w_i|=n$) essentially:
- We build an automaton which simply describes reading $sigma, w_i, c$ first.
- Then we guess the $w_i$ which is according to condition 1 or 2.
- Then we read the $sigma, c$ surrounding the guessed $w_i$ and the $w_i$ itself.
I'm new to pushdown automata, but it looks like a lot of automata could be solved in such a generic way:
- Read the words according to some logic described in the problem.
- guess some "good" word (by using $epsilon$ connection) and delete it from the stack.
Am I missing something?
Also I don't understand why we need $2$ cases in the solution for each condition. The solutions for each condition look almost identical.
Lastly, I don't understand why in the automaton for the condition $1$ in state $q_5$ we need to read the end of $w_i$ first, then read the "good" $w_i$. Why can't we read the "good" $w_i$ straight after the guess?
proof-explanation formal-languages automata
proof-explanation formal-languages automata
asked Dec 15 '18 at 8:41
YosYos
1,1631823
1,1631823
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3040276%2fhow-to-guess-the-end-of-pushdown-automata-by-emptying-the-stack%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3040276%2fhow-to-guess-the-end-of-pushdown-automata-by-emptying-the-stack%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown