If “A”, “B”, “X”, and “R” respectively denote “divided by”, “added to”, “subtracted...












1












$begingroup$



If




  • "A" denotes "divided by"

  • "B" denotes "added to"

  • "X" denotes "subtracted from"

  • "R" denotes "multiplied by"


then
$$18R12A4X8B6;=;text{?}$$



$left(Aright)50 quadleft(Bright)102 quad left(Cright)45 quad left(Dright)32$




My Approach $Longrightarrow$ I tried it in two ways



First approach:
$$18timesleft[left(8+6right)-left(12div4right)right]=198$$



Second approach: $$18times12div4-8+6=40$$






arithmetic







share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    For example 6X4 would be 4-6 not 6-4, since x is "subtracted from".
    $endgroup$
    – coffeemath
    Dec 19 '18 at 6:26






  • 1




    $begingroup$
    What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:28








  • 3




    $begingroup$
    Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:35










  • $begingroup$
    @fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:40










  • $begingroup$
    @fleablood I agree
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:42
















1












$begingroup$



If




  • "A" denotes "divided by"

  • "B" denotes "added to"

  • "X" denotes "subtracted from"

  • "R" denotes "multiplied by"


then
$$18R12A4X8B6;=;text{?}$$



$left(Aright)50 quadleft(Bright)102 quad left(Cright)45 quad left(Dright)32$




My Approach $Longrightarrow$ I tried it in two ways



First approach:
$$18timesleft[left(8+6right)-left(12div4right)right]=198$$



Second approach: $$18times12div4-8+6=40$$






arithmetic







share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    For example 6X4 would be 4-6 not 6-4, since x is "subtracted from".
    $endgroup$
    – coffeemath
    Dec 19 '18 at 6:26






  • 1




    $begingroup$
    What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:28








  • 3




    $begingroup$
    Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:35










  • $begingroup$
    @fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:40










  • $begingroup$
    @fleablood I agree
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:42














1












1








1


0



$begingroup$



If




  • "A" denotes "divided by"

  • "B" denotes "added to"

  • "X" denotes "subtracted from"

  • "R" denotes "multiplied by"


then
$$18R12A4X8B6;=;text{?}$$



$left(Aright)50 quadleft(Bright)102 quad left(Cright)45 quad left(Dright)32$




My Approach $Longrightarrow$ I tried it in two ways



First approach:
$$18timesleft[left(8+6right)-left(12div4right)right]=198$$



Second approach: $$18times12div4-8+6=40$$






arithmetic







share|cite|improve this question











$endgroup$





If




  • "A" denotes "divided by"

  • "B" denotes "added to"

  • "X" denotes "subtracted from"

  • "R" denotes "multiplied by"


then
$$18R12A4X8B6;=;text{?}$$



$left(Aright)50 quadleft(Bright)102 quad left(Cright)45 quad left(Dright)32$




My Approach $Longrightarrow$ I tried it in two ways



First approach:
$$18timesleft[left(8+6right)-left(12div4right)right]=198$$



Second approach: $$18times12div4-8+6=40$$






arithmetic




arithmetic






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 19 '18 at 5:59









Blue

49.1k870156




49.1k870156










asked Dec 19 '18 at 5:50









Mohan SharmaMohan Sharma

564213




564213








  • 1




    $begingroup$
    For example 6X4 would be 4-6 not 6-4, since x is "subtracted from".
    $endgroup$
    – coffeemath
    Dec 19 '18 at 6:26






  • 1




    $begingroup$
    What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:28








  • 3




    $begingroup$
    Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:35










  • $begingroup$
    @fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:40










  • $begingroup$
    @fleablood I agree
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:42














  • 1




    $begingroup$
    For example 6X4 would be 4-6 not 6-4, since x is "subtracted from".
    $endgroup$
    – coffeemath
    Dec 19 '18 at 6:26






  • 1




    $begingroup$
    What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:28








  • 3




    $begingroup$
    Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception.
    $endgroup$
    – fleablood
    Dec 19 '18 at 6:35










  • $begingroup$
    @fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:40










  • $begingroup$
    @fleablood I agree
    $endgroup$
    – Mohan Sharma
    Dec 19 '18 at 6:42








1




1




$begingroup$
For example 6X4 would be 4-6 not 6-4, since x is "subtracted from".
$endgroup$
– coffeemath
Dec 19 '18 at 6:26




$begingroup$
For example 6X4 would be 4-6 not 6-4, since x is "subtracted from".
$endgroup$
– coffeemath
Dec 19 '18 at 6:26




1




1




$begingroup$
What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given.
$endgroup$
– fleablood
Dec 19 '18 at 6:28






$begingroup$
What were your instructions? Were you expected to do this from left to right? If not what were the rules. The answer can be anything you want depending on what rules you were given.
$endgroup$
– fleablood
Dec 19 '18 at 6:28






3




3




$begingroup$
Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception.
$endgroup$
– fleablood
Dec 19 '18 at 6:35




$begingroup$
Okay I'd do it, with coffemaths obeservation, as $18R12 = 18*12 = 216$. $216A4 = 216div 4 = 54$. And $54X8=8 -54 = -46$. And $-46B6 = -46+6 = -40$. I don't like to ever call a question a stupid question but for this I'll make an exception.
$endgroup$
– fleablood
Dec 19 '18 at 6:35












$begingroup$
@fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know
$endgroup$
– Mohan Sharma
Dec 19 '18 at 6:40




$begingroup$
@fleablood the question is from math magician compition.no more instructions are given .I have provided everything I know
$endgroup$
– Mohan Sharma
Dec 19 '18 at 6:40












$begingroup$
@fleablood I agree
$endgroup$
– Mohan Sharma
Dec 19 '18 at 6:42




$begingroup$
@fleablood I agree
$endgroup$
– Mohan Sharma
Dec 19 '18 at 6:42










1 Answer
1






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2












$begingroup$

18*12/4-8+6
=18*3-8+6
=54-8+6
=44+6
=50
Correct option is A






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
    $endgroup$
    – Anurag Sinha
    Dec 19 '18 at 15:03











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1 Answer
1






active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

18*12/4-8+6
=18*3-8+6
=54-8+6
=44+6
=50
Correct option is A






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
    $endgroup$
    – Anurag Sinha
    Dec 19 '18 at 15:03
















2












$begingroup$

18*12/4-8+6
=18*3-8+6
=54-8+6
=44+6
=50
Correct option is A






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
    $endgroup$
    – Anurag Sinha
    Dec 19 '18 at 15:03














2












2








2





$begingroup$

18*12/4-8+6
=18*3-8+6
=54-8+6
=44+6
=50
Correct option is A






share|cite|improve this answer









$endgroup$



18*12/4-8+6
=18*3-8+6
=54-8+6
=44+6
=50
Correct option is A







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 19 '18 at 8:20









Mayur SinghMayur Singh

361




361








  • 1




    $begingroup$
    How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
    $endgroup$
    – Anurag Sinha
    Dec 19 '18 at 15:03














  • 1




    $begingroup$
    How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
    $endgroup$
    – Anurag Sinha
    Dec 19 '18 at 15:03








1




1




$begingroup$
How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
$endgroup$
– Anurag Sinha
Dec 19 '18 at 15:03




$begingroup$
How is 54-8+6=44+6 ? Shouldn't it be 46 + 6??
$endgroup$
– Anurag Sinha
Dec 19 '18 at 15:03


















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