Proving $Atimes(Bcup C)=(Atimes B)cup(Atimes C)$












1












$begingroup$


Prove that $Atimes(Bcup C)=(Atimes B)cup(Atimes C)$



My Try:



$(x,y)in Atimes(Bcup C) $



$xin A$ and $yin(Bcup C)$



$(xin A$ and $yin B)$ or $(xin A$ and $yin C)$



$(x,y)in Atimes B$ or $(x,y)in Atimes C$



$(x,y)in (Atimes B)cup(Atimes C)$



$(x,y)in (Atimes B)cup(Atimes C)$



So, I proved $Atimes(Bcap C)subset(Atimes B)cup(Atimes C)$



My question: Do I also need to prove $(Atimes B)cup(Atimes C)subset Atimes(Bcap C)?$










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$endgroup$








  • 1




    $begingroup$
    Of course you do
    $endgroup$
    – tommy1996q
    Dec 2 '18 at 19:10






  • 1




    $begingroup$
    Yes you do. To prove equality you have to prove $xin A iff xin B$, which means $xin A Rightarrow xin B wedge xin B Rightarrow xin A$
    $endgroup$
    – NL1992
    Dec 2 '18 at 19:10
















1












$begingroup$


Prove that $Atimes(Bcup C)=(Atimes B)cup(Atimes C)$



My Try:



$(x,y)in Atimes(Bcup C) $



$xin A$ and $yin(Bcup C)$



$(xin A$ and $yin B)$ or $(xin A$ and $yin C)$



$(x,y)in Atimes B$ or $(x,y)in Atimes C$



$(x,y)in (Atimes B)cup(Atimes C)$



$(x,y)in (Atimes B)cup(Atimes C)$



So, I proved $Atimes(Bcap C)subset(Atimes B)cup(Atimes C)$



My question: Do I also need to prove $(Atimes B)cup(Atimes C)subset Atimes(Bcap C)?$










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Of course you do
    $endgroup$
    – tommy1996q
    Dec 2 '18 at 19:10






  • 1




    $begingroup$
    Yes you do. To prove equality you have to prove $xin A iff xin B$, which means $xin A Rightarrow xin B wedge xin B Rightarrow xin A$
    $endgroup$
    – NL1992
    Dec 2 '18 at 19:10














1












1








1





$begingroup$


Prove that $Atimes(Bcup C)=(Atimes B)cup(Atimes C)$



My Try:



$(x,y)in Atimes(Bcup C) $



$xin A$ and $yin(Bcup C)$



$(xin A$ and $yin B)$ or $(xin A$ and $yin C)$



$(x,y)in Atimes B$ or $(x,y)in Atimes C$



$(x,y)in (Atimes B)cup(Atimes C)$



$(x,y)in (Atimes B)cup(Atimes C)$



So, I proved $Atimes(Bcap C)subset(Atimes B)cup(Atimes C)$



My question: Do I also need to prove $(Atimes B)cup(Atimes C)subset Atimes(Bcap C)?$










share|cite|improve this question









$endgroup$




Prove that $Atimes(Bcup C)=(Atimes B)cup(Atimes C)$



My Try:



$(x,y)in Atimes(Bcup C) $



$xin A$ and $yin(Bcup C)$



$(xin A$ and $yin B)$ or $(xin A$ and $yin C)$



$(x,y)in Atimes B$ or $(x,y)in Atimes C$



$(x,y)in (Atimes B)cup(Atimes C)$



$(x,y)in (Atimes B)cup(Atimes C)$



So, I proved $Atimes(Bcap C)subset(Atimes B)cup(Atimes C)$



My question: Do I also need to prove $(Atimes B)cup(Atimes C)subset Atimes(Bcap C)?$







discrete-mathematics proof-verification elementary-set-theory logic






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asked Dec 2 '18 at 19:08









user982787user982787

1117




1117








  • 1




    $begingroup$
    Of course you do
    $endgroup$
    – tommy1996q
    Dec 2 '18 at 19:10






  • 1




    $begingroup$
    Yes you do. To prove equality you have to prove $xin A iff xin B$, which means $xin A Rightarrow xin B wedge xin B Rightarrow xin A$
    $endgroup$
    – NL1992
    Dec 2 '18 at 19:10














  • 1




    $begingroup$
    Of course you do
    $endgroup$
    – tommy1996q
    Dec 2 '18 at 19:10






  • 1




    $begingroup$
    Yes you do. To prove equality you have to prove $xin A iff xin B$, which means $xin A Rightarrow xin B wedge xin B Rightarrow xin A$
    $endgroup$
    – NL1992
    Dec 2 '18 at 19:10








1




1




$begingroup$
Of course you do
$endgroup$
– tommy1996q
Dec 2 '18 at 19:10




$begingroup$
Of course you do
$endgroup$
– tommy1996q
Dec 2 '18 at 19:10




1




1




$begingroup$
Yes you do. To prove equality you have to prove $xin A iff xin B$, which means $xin A Rightarrow xin B wedge xin B Rightarrow xin A$
$endgroup$
– NL1992
Dec 2 '18 at 19:10




$begingroup$
Yes you do. To prove equality you have to prove $xin A iff xin B$, which means $xin A Rightarrow xin B wedge xin B Rightarrow xin A$
$endgroup$
– NL1992
Dec 2 '18 at 19:10










1 Answer
1






active

oldest

votes


















3












$begingroup$

Just write $iff$ arrows between the statements.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Where and what is it meant to write $iff$ ?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:30






  • 1




    $begingroup$
    @user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:32










  • $begingroup$
    If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:36






  • 2




    $begingroup$
    @user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:59










  • $begingroup$
    Just add "... and vice versa, as all implications are biconditional."
    $endgroup$
    – Graham Kemp
    Dec 2 '18 at 21:40











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Just write $iff$ arrows between the statements.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Where and what is it meant to write $iff$ ?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:30






  • 1




    $begingroup$
    @user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:32










  • $begingroup$
    If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:36






  • 2




    $begingroup$
    @user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:59










  • $begingroup$
    Just add "... and vice versa, as all implications are biconditional."
    $endgroup$
    – Graham Kemp
    Dec 2 '18 at 21:40
















3












$begingroup$

Just write $iff$ arrows between the statements.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Where and what is it meant to write $iff$ ?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:30






  • 1




    $begingroup$
    @user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:32










  • $begingroup$
    If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:36






  • 2




    $begingroup$
    @user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:59










  • $begingroup$
    Just add "... and vice versa, as all implications are biconditional."
    $endgroup$
    – Graham Kemp
    Dec 2 '18 at 21:40














3












3








3





$begingroup$

Just write $iff$ arrows between the statements.






share|cite|improve this answer









$endgroup$



Just write $iff$ arrows between the statements.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 2 '18 at 19:10









J.G.J.G.

24.4k22539




24.4k22539












  • $begingroup$
    Where and what is it meant to write $iff$ ?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:30






  • 1




    $begingroup$
    @user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:32










  • $begingroup$
    If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:36






  • 2




    $begingroup$
    @user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:59










  • $begingroup$
    Just add "... and vice versa, as all implications are biconditional."
    $endgroup$
    – Graham Kemp
    Dec 2 '18 at 21:40


















  • $begingroup$
    Where and what is it meant to write $iff$ ?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:30






  • 1




    $begingroup$
    @user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:32










  • $begingroup$
    If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
    $endgroup$
    – user982787
    Dec 2 '18 at 19:36






  • 2




    $begingroup$
    @user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
    $endgroup$
    – J.G.
    Dec 2 '18 at 19:59










  • $begingroup$
    Just add "... and vice versa, as all implications are biconditional."
    $endgroup$
    – Graham Kemp
    Dec 2 '18 at 21:40
















$begingroup$
Where and what is it meant to write $iff$ ?
$endgroup$
– user982787
Dec 2 '18 at 19:30




$begingroup$
Where and what is it meant to write $iff$ ?
$endgroup$
– user982787
Dec 2 '18 at 19:30




1




1




$begingroup$
@user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
$endgroup$
– J.G.
Dec 2 '18 at 19:32




$begingroup$
@user982787 You need to emphasize each of your lines is true iff the other is, so you can just place $iff$ at the beginning of each line (except the first one).
$endgroup$
– J.G.
Dec 2 '18 at 19:32












$begingroup$
If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
$endgroup$
– user982787
Dec 2 '18 at 19:36




$begingroup$
If I place $iff$, then I need not prove $(A×B)∪(A×C)⊂A×(B∩C)$ this right?
$endgroup$
– user982787
Dec 2 '18 at 19:36




2




2




$begingroup$
@user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
$endgroup$
– J.G.
Dec 2 '18 at 19:59




$begingroup$
@user982787 When as in a proof like this all inferences can be made validly in both directions, you get both proof directions for the price of one write-up.
$endgroup$
– J.G.
Dec 2 '18 at 19:59












$begingroup$
Just add "... and vice versa, as all implications are biconditional."
$endgroup$
– Graham Kemp
Dec 2 '18 at 21:40




$begingroup$
Just add "... and vice versa, as all implications are biconditional."
$endgroup$
– Graham Kemp
Dec 2 '18 at 21:40


















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