Find correct corresponding point to extend line












0












$begingroup$


I tried this at stackoverflow but was told it's more of a geometry problem than programming. So here goes.



I have two non parallel lines(XA and YB) which I need to extend to a curved line piece(PQ). The lines are made of arrays of (x,y) points. A is the last point in XA line and B is the last point in YB line. P and Q are the edge points of the curve.



![enter image description here



Now, I need to extend point A to P and point B to Q. Is there a way I can find the correct corresponding point of PQ curve so that A->P and B->Q and not A->Q and B->P, in the latter case the extended lines would intersect, that shouldn't happen.



Previously I had tried a simple boolean, but it was incorrect.



What I tried;



if(abs(A.x() - P.x()) < abs(B.x() - P.x())
// extend A to P
// extend B to Q
else
// extend A to Q
// extend B to P


The above wouldn't work for the image shown below, as then line A would be extended to point Q and line B to P (extension drawn in red).



![![enter image description here



Any help would be appreciated.










share|cite|improve this question









$endgroup$












  • $begingroup$
    Maybe you can try using the y-coordinate instead of the x-coordinate?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 11:26










  • $begingroup$
    That woudn't work either. The Y can vary as well. I think the best solution would be to find if the AP and BQ intesect.. but I'm not sure on how to check that..
    $endgroup$
    – Madz
    Dec 17 '18 at 11:30










  • $begingroup$
    Does my answer below help?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 12:28
















0












$begingroup$


I tried this at stackoverflow but was told it's more of a geometry problem than programming. So here goes.



I have two non parallel lines(XA and YB) which I need to extend to a curved line piece(PQ). The lines are made of arrays of (x,y) points. A is the last point in XA line and B is the last point in YB line. P and Q are the edge points of the curve.



![enter image description here



Now, I need to extend point A to P and point B to Q. Is there a way I can find the correct corresponding point of PQ curve so that A->P and B->Q and not A->Q and B->P, in the latter case the extended lines would intersect, that shouldn't happen.



Previously I had tried a simple boolean, but it was incorrect.



What I tried;



if(abs(A.x() - P.x()) < abs(B.x() - P.x())
// extend A to P
// extend B to Q
else
// extend A to Q
// extend B to P


The above wouldn't work for the image shown below, as then line A would be extended to point Q and line B to P (extension drawn in red).



![![enter image description here



Any help would be appreciated.










share|cite|improve this question









$endgroup$












  • $begingroup$
    Maybe you can try using the y-coordinate instead of the x-coordinate?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 11:26










  • $begingroup$
    That woudn't work either. The Y can vary as well. I think the best solution would be to find if the AP and BQ intesect.. but I'm not sure on how to check that..
    $endgroup$
    – Madz
    Dec 17 '18 at 11:30










  • $begingroup$
    Does my answer below help?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 12:28














0












0








0





$begingroup$


I tried this at stackoverflow but was told it's more of a geometry problem than programming. So here goes.



I have two non parallel lines(XA and YB) which I need to extend to a curved line piece(PQ). The lines are made of arrays of (x,y) points. A is the last point in XA line and B is the last point in YB line. P and Q are the edge points of the curve.



![enter image description here



Now, I need to extend point A to P and point B to Q. Is there a way I can find the correct corresponding point of PQ curve so that A->P and B->Q and not A->Q and B->P, in the latter case the extended lines would intersect, that shouldn't happen.



Previously I had tried a simple boolean, but it was incorrect.



What I tried;



if(abs(A.x() - P.x()) < abs(B.x() - P.x())
// extend A to P
// extend B to Q
else
// extend A to Q
// extend B to P


The above wouldn't work for the image shown below, as then line A would be extended to point Q and line B to P (extension drawn in red).



![![enter image description here



Any help would be appreciated.










share|cite|improve this question









$endgroup$




I tried this at stackoverflow but was told it's more of a geometry problem than programming. So here goes.



I have two non parallel lines(XA and YB) which I need to extend to a curved line piece(PQ). The lines are made of arrays of (x,y) points. A is the last point in XA line and B is the last point in YB line. P and Q are the edge points of the curve.



![enter image description here



Now, I need to extend point A to P and point B to Q. Is there a way I can find the correct corresponding point of PQ curve so that A->P and B->Q and not A->Q and B->P, in the latter case the extended lines would intersect, that shouldn't happen.



Previously I had tried a simple boolean, but it was incorrect.



What I tried;



if(abs(A.x() - P.x()) < abs(B.x() - P.x())
// extend A to P
// extend B to Q
else
// extend A to Q
// extend B to P


The above wouldn't work for the image shown below, as then line A would be extended to point Q and line B to P (extension drawn in red).



![![enter image description here



Any help would be appreciated.







geometry






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 17 '18 at 11:18









MadzMadz

1225




1225












  • $begingroup$
    Maybe you can try using the y-coordinate instead of the x-coordinate?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 11:26










  • $begingroup$
    That woudn't work either. The Y can vary as well. I think the best solution would be to find if the AP and BQ intesect.. but I'm not sure on how to check that..
    $endgroup$
    – Madz
    Dec 17 '18 at 11:30










  • $begingroup$
    Does my answer below help?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 12:28


















  • $begingroup$
    Maybe you can try using the y-coordinate instead of the x-coordinate?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 11:26










  • $begingroup$
    That woudn't work either. The Y can vary as well. I think the best solution would be to find if the AP and BQ intesect.. but I'm not sure on how to check that..
    $endgroup$
    – Madz
    Dec 17 '18 at 11:30










  • $begingroup$
    Does my answer below help?
    $endgroup$
    – Math Girl
    Dec 17 '18 at 12:28
















$begingroup$
Maybe you can try using the y-coordinate instead of the x-coordinate?
$endgroup$
– Math Girl
Dec 17 '18 at 11:26




$begingroup$
Maybe you can try using the y-coordinate instead of the x-coordinate?
$endgroup$
– Math Girl
Dec 17 '18 at 11:26












$begingroup$
That woudn't work either. The Y can vary as well. I think the best solution would be to find if the AP and BQ intesect.. but I'm not sure on how to check that..
$endgroup$
– Madz
Dec 17 '18 at 11:30




$begingroup$
That woudn't work either. The Y can vary as well. I think the best solution would be to find if the AP and BQ intesect.. but I'm not sure on how to check that..
$endgroup$
– Madz
Dec 17 '18 at 11:30












$begingroup$
Does my answer below help?
$endgroup$
– Math Girl
Dec 17 '18 at 12:28




$begingroup$
Does my answer below help?
$endgroup$
– Math Girl
Dec 17 '18 at 12:28










1 Answer
1






active

oldest

votes


















1












$begingroup$

if(A.y() > B.x())
if(P.y() > Q.y())
// extend A to P
// extend B to Q
else
// extend A to Q
// extend B to P
else
if(P.y() > Q.y())
// extend A to Q
// extend B to P
else
// extend A to P
// extend B to Q





share|cite|improve this answer









$endgroup$













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    1 Answer
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    $begingroup$

    if(A.y() > B.x())
    if(P.y() > Q.y())
    // extend A to P
    // extend B to Q
    else
    // extend A to Q
    // extend B to P
    else
    if(P.y() > Q.y())
    // extend A to Q
    // extend B to P
    else
    // extend A to P
    // extend B to Q





    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      if(A.y() > B.x())
      if(P.y() > Q.y())
      // extend A to P
      // extend B to Q
      else
      // extend A to Q
      // extend B to P
      else
      if(P.y() > Q.y())
      // extend A to Q
      // extend B to P
      else
      // extend A to P
      // extend B to Q





      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        if(A.y() > B.x())
        if(P.y() > Q.y())
        // extend A to P
        // extend B to Q
        else
        // extend A to Q
        // extend B to P
        else
        if(P.y() > Q.y())
        // extend A to Q
        // extend B to P
        else
        // extend A to P
        // extend B to Q





        share|cite|improve this answer









        $endgroup$



        if(A.y() > B.x())
        if(P.y() > Q.y())
        // extend A to P
        // extend B to Q
        else
        // extend A to Q
        // extend B to P
        else
        if(P.y() > Q.y())
        // extend A to Q
        // extend B to P
        else
        // extend A to P
        // extend B to Q






        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 17 '18 at 11:31









        Math GirlMath Girl

        625318




        625318






























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