Locally Complete Metric Space












3














It is undoubtedly the concept of "Complete Metric Space" is well known for all the users.



The Locally Complete Metric Space is a metric space where each point has a neighbourhood (which is closed) is a complete metric space.



It is so obvious that every complete metric space is locally complete metric space.



I am looking for an example of locally complete metric space that is not complete metric space.










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    3














    It is undoubtedly the concept of "Complete Metric Space" is well known for all the users.



    The Locally Complete Metric Space is a metric space where each point has a neighbourhood (which is closed) is a complete metric space.



    It is so obvious that every complete metric space is locally complete metric space.



    I am looking for an example of locally complete metric space that is not complete metric space.










    share|cite|improve this question

























      3












      3








      3


      1





      It is undoubtedly the concept of "Complete Metric Space" is well known for all the users.



      The Locally Complete Metric Space is a metric space where each point has a neighbourhood (which is closed) is a complete metric space.



      It is so obvious that every complete metric space is locally complete metric space.



      I am looking for an example of locally complete metric space that is not complete metric space.










      share|cite|improve this question













      It is undoubtedly the concept of "Complete Metric Space" is well known for all the users.



      The Locally Complete Metric Space is a metric space where each point has a neighbourhood (which is closed) is a complete metric space.



      It is so obvious that every complete metric space is locally complete metric space.



      I am looking for an example of locally complete metric space that is not complete metric space.







      general-topology functional-analysis metric-spaces complete-spaces






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      share|cite|improve this question











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      asked Nov 26 at 22:06









      Neil hawking

      47219




      47219






















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          Example 1: $lbrace dfrac1n: n in Bbb Nrbrace$ with the usual metric.



          Example 2: Any open but non-closed subset $U$ of a complete metric space. Like open intervals of finite length in $Bbb R$.



          How to bring these examples together? I think the following characterisation is valid: Let $A$ be a subset of a complete metric space. Then $A$ with the restricted metric is locally complete but not complete if and only if:





          1. $A$ is not closed


          2. $cl(cl(A) setminus A) cap A = emptyset$, or equivalently, no limit point of $cl(A)setminus A$ lies in $A$, or equivalently, for every $ain A$, $inf lbrace d(a, x): xin cl(A)setminus Arbrace > 0$.


          Since every metric space embeds into its completion, this gives a full (well, up to describing completions and checking these properties ...) characterisation of the spaces you ask for.






          share|cite|improve this answer























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            1 Answer
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            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6














            Example 1: $lbrace dfrac1n: n in Bbb Nrbrace$ with the usual metric.



            Example 2: Any open but non-closed subset $U$ of a complete metric space. Like open intervals of finite length in $Bbb R$.



            How to bring these examples together? I think the following characterisation is valid: Let $A$ be a subset of a complete metric space. Then $A$ with the restricted metric is locally complete but not complete if and only if:





            1. $A$ is not closed


            2. $cl(cl(A) setminus A) cap A = emptyset$, or equivalently, no limit point of $cl(A)setminus A$ lies in $A$, or equivalently, for every $ain A$, $inf lbrace d(a, x): xin cl(A)setminus Arbrace > 0$.


            Since every metric space embeds into its completion, this gives a full (well, up to describing completions and checking these properties ...) characterisation of the spaces you ask for.






            share|cite|improve this answer




























              6














              Example 1: $lbrace dfrac1n: n in Bbb Nrbrace$ with the usual metric.



              Example 2: Any open but non-closed subset $U$ of a complete metric space. Like open intervals of finite length in $Bbb R$.



              How to bring these examples together? I think the following characterisation is valid: Let $A$ be a subset of a complete metric space. Then $A$ with the restricted metric is locally complete but not complete if and only if:





              1. $A$ is not closed


              2. $cl(cl(A) setminus A) cap A = emptyset$, or equivalently, no limit point of $cl(A)setminus A$ lies in $A$, or equivalently, for every $ain A$, $inf lbrace d(a, x): xin cl(A)setminus Arbrace > 0$.


              Since every metric space embeds into its completion, this gives a full (well, up to describing completions and checking these properties ...) characterisation of the spaces you ask for.






              share|cite|improve this answer


























                6












                6








                6






                Example 1: $lbrace dfrac1n: n in Bbb Nrbrace$ with the usual metric.



                Example 2: Any open but non-closed subset $U$ of a complete metric space. Like open intervals of finite length in $Bbb R$.



                How to bring these examples together? I think the following characterisation is valid: Let $A$ be a subset of a complete metric space. Then $A$ with the restricted metric is locally complete but not complete if and only if:





                1. $A$ is not closed


                2. $cl(cl(A) setminus A) cap A = emptyset$, or equivalently, no limit point of $cl(A)setminus A$ lies in $A$, or equivalently, for every $ain A$, $inf lbrace d(a, x): xin cl(A)setminus Arbrace > 0$.


                Since every metric space embeds into its completion, this gives a full (well, up to describing completions and checking these properties ...) characterisation of the spaces you ask for.






                share|cite|improve this answer














                Example 1: $lbrace dfrac1n: n in Bbb Nrbrace$ with the usual metric.



                Example 2: Any open but non-closed subset $U$ of a complete metric space. Like open intervals of finite length in $Bbb R$.



                How to bring these examples together? I think the following characterisation is valid: Let $A$ be a subset of a complete metric space. Then $A$ with the restricted metric is locally complete but not complete if and only if:





                1. $A$ is not closed


                2. $cl(cl(A) setminus A) cap A = emptyset$, or equivalently, no limit point of $cl(A)setminus A$ lies in $A$, or equivalently, for every $ain A$, $inf lbrace d(a, x): xin cl(A)setminus Arbrace > 0$.


                Since every metric space embeds into its completion, this gives a full (well, up to describing completions and checking these properties ...) characterisation of the spaces you ask for.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Nov 27 at 6:25

























                answered Nov 26 at 22:21









                Torsten Schoeneberg

                3,7312833




                3,7312833






























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