Concentration of Gaussian random matrices












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I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?










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    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    – cdipaolo
    Nov 27 at 4:05










  • Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    – cdipaolo
    Nov 27 at 4:18


















1














I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?










share|cite|improve this question


















  • 1




    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    – cdipaolo
    Nov 27 at 4:05










  • Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    – cdipaolo
    Nov 27 at 4:18
















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1








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1





I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?










share|cite|improve this question













I know that if $X$ be a random matrix distributed as $N(0,I_n)$, then $frac{1}{n}X^TX$ is concentrated around the identity matrix. Does any body know the probability of $P(||frac{1}{n}X^TX-I||<delta)$?







probability-theory normal-distribution concentration-of-measure






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share|cite|improve this question











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asked Nov 27 at 3:44









S_Alex

858




858








  • 1




    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    – cdipaolo
    Nov 27 at 4:05










  • Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    – cdipaolo
    Nov 27 at 4:18
















  • 1




    A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
    – cdipaolo
    Nov 27 at 4:05










  • Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
    – cdipaolo
    Nov 27 at 4:18










1




1




A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
– cdipaolo
Nov 27 at 4:05




A relatively recent paper by Vershynin (arxiv/abs/1004.3484) shows how to answer this question. He's mainly interested in asymptotics, but working through the proof of Proposition 2.1 would give you the result you want.
– cdipaolo
Nov 27 at 4:05












Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
– cdipaolo
Nov 27 at 4:18






Another approach that would be looser yet would be probably a bit easier to compute is to apply Tropp's matrix concentration inequalities and bound the norm of a Gaussian vector with high probability. See Section 1.6.3 of arxiv/abs/1501.01571 for this.
– cdipaolo
Nov 27 at 4:18

















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