Flux of the amount of buffalo entering a square kilometer per minute
$begingroup$
So Eq.(13) is just $int F.n dS = int int div(F) dA$
So I did $div(F) = nabla . F = y+1$, then I did $int_2^3 int_2^3 y + 1 dx dy = int_2^3 y + 1 dy = .5(3^2) + 3 - (.5(2^2) + 2) = 3.5$ This multiplied by density is 1750.
This is not the answer. The answer is 29.2
multivariable-calculus vector-fields fluid-dynamics
$endgroup$
add a comment |
$begingroup$
So Eq.(13) is just $int F.n dS = int int div(F) dA$
So I did $div(F) = nabla . F = y+1$, then I did $int_2^3 int_2^3 y + 1 dx dy = int_2^3 y + 1 dy = .5(3^2) + 3 - (.5(2^2) + 2) = 3.5$ This multiplied by density is 1750.
This is not the answer. The answer is 29.2
multivariable-calculus vector-fields fluid-dynamics
$endgroup$
$begingroup$
What book is this?
$endgroup$
– rogerl
Apr 21 '16 at 0:43
$begingroup$
Rogawski Calculus 3rd edition
$endgroup$
– user116528
Apr 21 '16 at 0:45
add a comment |
$begingroup$
So Eq.(13) is just $int F.n dS = int int div(F) dA$
So I did $div(F) = nabla . F = y+1$, then I did $int_2^3 int_2^3 y + 1 dx dy = int_2^3 y + 1 dy = .5(3^2) + 3 - (.5(2^2) + 2) = 3.5$ This multiplied by density is 1750.
This is not the answer. The answer is 29.2
multivariable-calculus vector-fields fluid-dynamics
$endgroup$
So Eq.(13) is just $int F.n dS = int int div(F) dA$
So I did $div(F) = nabla . F = y+1$, then I did $int_2^3 int_2^3 y + 1 dx dy = int_2^3 y + 1 dy = .5(3^2) + 3 - (.5(2^2) + 2) = 3.5$ This multiplied by density is 1750.
This is not the answer. The answer is 29.2
multivariable-calculus vector-fields fluid-dynamics
multivariable-calculus vector-fields fluid-dynamics
asked Apr 21 '16 at 0:24
user116528
$begingroup$
What book is this?
$endgroup$
– rogerl
Apr 21 '16 at 0:43
$begingroup$
Rogawski Calculus 3rd edition
$endgroup$
– user116528
Apr 21 '16 at 0:45
add a comment |
$begingroup$
What book is this?
$endgroup$
– rogerl
Apr 21 '16 at 0:43
$begingroup$
Rogawski Calculus 3rd edition
$endgroup$
– user116528
Apr 21 '16 at 0:45
$begingroup$
What book is this?
$endgroup$
– rogerl
Apr 21 '16 at 0:43
$begingroup$
What book is this?
$endgroup$
– rogerl
Apr 21 '16 at 0:43
$begingroup$
Rogawski Calculus 3rd edition
$endgroup$
– user116528
Apr 21 '16 at 0:45
$begingroup$
Rogawski Calculus 3rd edition
$endgroup$
– user116528
Apr 21 '16 at 0:45
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The value 1750 corresponds with the number of buffalo entering/leaving the area per hour. Divide by 60 to get 29.2.
edited Dec 12 '18 at 19:18
Nij
2,03811223
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
$endgroup$
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The value 1750 corresponds with the number of buffalo entering/leaving the area per hour. Divide by 60 to get 29.2.
edited Dec 12 '18 at 19:18
Nij
2,03811223
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
$endgroup$
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
add a comment |
$begingroup$
The value 1750 corresponds with the number of buffalo entering/leaving the area per hour. Divide by 60 to get 29.2.
edited Dec 12 '18 at 19:18
Nij
2,03811223
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
$endgroup$
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
add a comment |
$begingroup$
The value 1750 corresponds with the number of buffalo entering/leaving the area per hour. Divide by 60 to get 29.2.
edited Dec 12 '18 at 19:18
Nij
2,03811223
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
$endgroup$
The value 1750 corresponds with the number of buffalo entering/leaving the area per hour. Divide by 60 to get 29.2.
edited Dec 12 '18 at 19:18
Nij
2,03811223
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
edited Dec 12 '18 at 19:18
Nij
2,03811223
edited Dec 12 '18 at 19:18
Nij
2,03811223
edited Dec 12 '18 at 19:18
Nij
2,03811223
2,03811223
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
answered Dec 12 '18 at 17:51
David StevensDavid Stevens
111
111
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
add a comment |
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
$begingroup$
This answer is correct. It is asking for buffalo per minute and the flux is given per hour
$endgroup$
– whpowell96
Dec 12 '18 at 19:28
add a comment |
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$begingroup$
What book is this?
$endgroup$
– rogerl
Apr 21 '16 at 0:43
$begingroup$
Rogawski Calculus 3rd edition
$endgroup$
– user116528
Apr 21 '16 at 0:45